Elements of Arithmetic: For Schools and Academies. In which Decimal and Integral Arithmetic are Combined, and Taught Inductively, on the System of Pestalozzi. Part second |
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Page 45
... wall 19ft . 6in . long , 2ft . 3in . thick , and 4ft . 6in . high ? 5. How many cubic feet of wood in a pile 16 3 ′ long , 4 6 ′ wide , and 8 feet high ? 6. The number of square feet , & c . , in a floor , is 166 9 ′ 6 ′′ 3 ′′ ′′ 9 ...
... wall 19ft . 6in . long , 2ft . 3in . thick , and 4ft . 6in . high ? 5. How many cubic feet of wood in a pile 16 3 ′ long , 4 6 ′ wide , and 8 feet high ? 6. The number of square feet , & c . , in a floor , is 166 9 ′ 6 ′′ 3 ′′ ′′ 9 ...
Page 50
... wall that 15 men can build in 411 days ? 70. How many square feet in a board 2ft . 3in . wide , and 11ft . Tin . long ? 71. The sum of two numbers is 96 , and one of the numbers is 185 ; what is the other ? 72. The greater of two ...
... wall that 15 men can build in 411 days ? 70. How many square feet in a board 2ft . 3in . wide , and 11ft . Tin . long ? 71. The sum of two numbers is 96 , and one of the numbers is 185 ; what is the other ? 72. The greater of two ...
Page 85
... wall in 3 days , how many men will build 100 rods in 12 days ? To build 100 rods it will evidently take 40 100 40 as many men as to build 40 rods , or 100 of 8 , which may be expressed by the proportion rods . rods . men . 40 : 100 :: 8 ...
... wall in 3 days , how many men will build 100 rods in 12 days ? To build 100 rods it will evidently take 40 100 40 as many men as to build 40 rods , or 100 of 8 , which may be expressed by the proportion rods . rods . men . 40 : 100 :: 8 ...
Page 87
... wall in a day , 4 men will build 2 rods in the same time . Stating the proportion , we have men . 8 : cause . men ... wall 150 feet long , 2 feet wide and 4 feet high , in how many days of 12 hours will 24 men build a wall 200 feet long ...
... wall in a day , 4 men will build 2 rods in the same time . Stating the proportion , we have men . 8 : cause . men ... wall 150 feet long , 2 feet wide and 4 feet high , in how many days of 12 hours will 24 men build a wall 200 feet long ...
Page 88
... wall that 36 men will build in 8 months ? 13. How many bushels of meal will serve 36 persons 12 months , if 10 persons consume 8 bushels in 2 months ? 14. If 18 men build a cistern 20 feet long , 12 feet wide , and 10 feet high , in 3 ...
... wall that 36 men will build in 8 months ? 13. How many bushels of meal will serve 36 persons 12 months , if 10 persons consume 8 bushels in 2 months ? 14. If 18 men build a cistern 20 feet long , 12 feet wide , and 10 feet high , in 3 ...
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Common terms and phrases
5th power 9 hours acres amount annuity approximate values Arithmetic Avoirdupois bill BOARD bought bushel cents a pound column commence common difference compound interest contained continued fraction cost cube root cubic denominator diameter discount Divide dividend divisible dollars dominical letter equal example exchange Extract extremes feet fraction gain gallons Geometrical Progression given number greatest common divisor harmonical means hours a day hundred improper fraction inches last term least common multiple less lowest terms marcs mean proportional miles minuend months multiplicand Multiply number of terms obtained oxen paid payable payment piece present worth prime factors prime number PROBLEM quotient figure ratio Reduce remainder repetend rods root figure RULE sold square number square root subtract sugar tens third trial divisor undecillion units weeks weight whole number wide yards zeroes లు
Popular passages
Page 18 - Remove the decimal point as many places to the right as there are ciphers in the multiplier.
Page 177 - To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity.
Page 30 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Page 106 - PROBLEM II. Any number of different things being given, to find how many changes can be made out of them by taking a given number of the things at a time.
Page 27 - RULE. Multiply all the numerators together for a new numerator, and all the denominators for a new denominator: then reduce the new fraction to its lowest terms.
Page 106 - To find the number of Permutations or changes, that can be made of any given number of things, all different from each other.- . RULE. Multiply all the terms of the natural series of numbers, from one up to the given number, continually together, and the last product will be the answer required.
Page 9 - ... say one and one are two, two and one are three, three and one are four, four and one are five, five and one are six, six and two are eight ; in this way they go on until they are desired to stop.
Page 207 - A farmer has a stack of hay, from which he sells a quantity which is to the quantity remaining, as 4 to 5. He then uses 15 loads and finds that the quantity left, is to the quantity sold, as 1 to 2. Required the number of loads at first in the stack.
Page 130 - RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient.
Page 117 - All numbers between 1000 or 103, antj iQO0000 or 100», will have two figures in their root. And generally, if we divide a cube into periods of three figures each, by placing a point over units, and one over every third figure from units, the number of points will show the number of figures in the root. EXAMPLES FOR THE BOARD. In order properly to understand the principles of the cube root, the student should be provided with the following blocks : 1. A cubical block, each side measuring 3 inches,...