Elements of Arithmetic: For Schools and Academies. In which Decimal and Integral Arithmetic are Combined, and Taught Inductively, on the System of Pestalozzi. Part second |
From inside the book
Results 1-5 of 17
Page 17
... selling the same stock for $ 290451.00 ? How much ? 8. In a certain factory there were made 916482.7 yards of satinet , and 895267.594207 yards of broadcloth . How many yards were there of satinet more than of broadcloth ? CHAPTER IV ...
... selling the same stock for $ 290451.00 ? How much ? 8. In a certain factory there were made 916482.7 yards of satinet , and 895267.594207 yards of broadcloth . How many yards were there of satinet more than of broadcloth ? CHAPTER IV ...
Page 41
... selling 11cwt . 2qr . 17lb . 12oz . ? 6. A man sold his horse for £ 40 , which was £ 9 8s . 6d . more than it cost him . What did he give for the horse ? 7. Subtract 9 73 73 19 11gr . from 16 33 9gr . 8. Subtract 19yd . 3qr . 3na . from ...
... selling 11cwt . 2qr . 17lb . 12oz . ? 6. A man sold his horse for £ 40 , which was £ 9 8s . 6d . more than it cost him . What did he give for the horse ? 7. Subtract 9 73 73 19 11gr . from 16 33 9gr . 8. Subtract 19yd . 3qr . 3na . from ...
Page 62
... selling property . 1. A broker sold goods at a commission of 4 per cent . , for which he received $ 1963.50 . What was the amount of his commission , and how much did he pay to his em- ployer ? 2. How much shall I receive for my real ...
... selling property . 1. A broker sold goods at a commission of 4 per cent . , for which he received $ 1963.50 . What was the amount of his commission , and how much did he pay to his em- ployer ? 2. How much shall I receive for my real ...
Page 64
... selling at 90cts . a pound , tea that cost me 75 cents ? [ The gain is 15cts . , or 15 of the prime cost . This fraction reduced to a deci- mal , gives .2 , or .20 . ] Ans . 20 per cent . 75 Ans . 1939 per . cent . 12 ? 13.7 49.25 ? 18 ...
... selling at 90cts . a pound , tea that cost me 75 cents ? [ The gain is 15cts . , or 15 of the prime cost . This fraction reduced to a deci- mal , gives .2 , or .20 . ] Ans . 20 per cent . 75 Ans . 1939 per . cent . 12 ? 13.7 49.25 ? 18 ...
Page 65
... selling broadcloth at $ 2.975 per yard , what was the prime cost ? 23. A draper sold cloth at 12 per cent . less than it cost him , thereby losing 62 cents a yard . What did he pay for the cloth ? 24. When sugar is $ 6.50 per cwt ...
... selling broadcloth at $ 2.975 per yard , what was the prime cost ? 23. A draper sold cloth at 12 per cent . less than it cost him , thereby losing 62 cents a yard . What did he pay for the cloth ? 24. When sugar is $ 6.50 per cwt ...
Other editions - View all
Common terms and phrases
5th power 9 hours acres amount annuity approximate values Arithmetic Avoirdupois bill BOARD bought bushel cents a pound column commence common difference compound interest contained continued fraction cost cube root cubic denominator diameter discount Divide dividend divisible dollars dominical letter equal example exchange Extract extremes feet fraction gain gallons Geometrical Progression given number greatest common divisor harmonical means hours a day hundred improper fraction inches last term least common multiple less lowest terms marcs mean proportional miles minuend months multiplicand Multiply number of terms obtained oxen paid payable payment piece present worth prime factors prime number PROBLEM quotient figure ratio Reduce remainder repetend rods root figure RULE sold square number square root subtract sugar tens third trial divisor undecillion units weeks weight whole number wide yards zeroes లు
Popular passages
Page 18 - Remove the decimal point as many places to the right as there are ciphers in the multiplier.
Page 177 - To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity.
Page 30 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Page 106 - PROBLEM II. Any number of different things being given, to find how many changes can be made out of them by taking a given number of the things at a time.
Page 27 - RULE. Multiply all the numerators together for a new numerator, and all the denominators for a new denominator: then reduce the new fraction to its lowest terms.
Page 106 - To find the number of Permutations or changes, that can be made of any given number of things, all different from each other.- . RULE. Multiply all the terms of the natural series of numbers, from one up to the given number, continually together, and the last product will be the answer required.
Page 9 - ... say one and one are two, two and one are three, three and one are four, four and one are five, five and one are six, six and two are eight ; in this way they go on until they are desired to stop.
Page 207 - A farmer has a stack of hay, from which he sells a quantity which is to the quantity remaining, as 4 to 5. He then uses 15 loads and finds that the quantity left, is to the quantity sold, as 1 to 2. Required the number of loads at first in the stack.
Page 130 - RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient.
Page 117 - All numbers between 1000 or 103, antj iQO0000 or 100», will have two figures in their root. And generally, if we divide a cube into periods of three figures each, by placing a point over units, and one over every third figure from units, the number of points will show the number of figures in the root. EXAMPLES FOR THE BOARD. In order properly to understand the principles of the cube root, the student should be provided with the following blocks : 1. A cubical block, each side measuring 3 inches,...