Elements of Geometry: With Practical Applications, for the Use of Schools |
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Page vi
... perimeters with unequal areas Area of a circle , sector 43 50 Approximate ratio of circumference Planes and their angles · 53 SECTION THIRD . - SOLIDS . 57 Page Page Polyedron Prism Pyramid Cylinder Cone Sphere Surface of polyedrons ...
... perimeters with unequal areas Area of a circle , sector 43 50 Approximate ratio of circumference Planes and their angles · 53 SECTION THIRD . - SOLIDS . 57 Page Page Polyedron Prism Pyramid Cylinder Cone Sphere Surface of polyedrons ...
Page viii
... perimeter . The first man who digested the Elements of Geometry into a regular treatise , was Hippocrates , who lived soon after Pythagoras . This work has not come down to us ; but history informs us , respecting Hippocrates , that he ...
... perimeter . The first man who digested the Elements of Geometry into a regular treatise , was Hippocrates , who lived soon after Pythagoras . This work has not come down to us ; but history informs us , respecting Hippocrates , that he ...
Page xvi
... 12 43 intersection " 6 31 11 66 .38 11 perimter centre O 66 42 " C 40 " C 60 " 41 G = C prism is a circle read A B to C D vertices as centres A E C BED intersection . G = B perimeter centre N prism is a cube * SECTION FIRST -LINES Page.
... 12 43 intersection " 6 31 11 66 .38 11 perimter centre O 66 42 " C 40 " C 60 " 41 G = C prism is a circle read A B to C D vertices as centres A E C BED intersection . G = B perimeter centre N prism is a cube * SECTION FIRST -LINES Page.
Page 38
... perimeter of a polygon we mean the sum of its sides . Then we say that the perimter A B C F64 D E F ( fig . 64 ) , is to the perimeter G H I K L M as C N is to I O. Suppose the two polygons are hexagons . As they are similar ( 89 ) we ...
... perimeter of a polygon we mean the sum of its sides . Then we say that the perimter A B C F64 D E F ( fig . 64 ) , is to the perimeter G H I K L M as C N is to I O. Suppose the two polygons are hexagons . As they are similar ( 89 ) we ...
Page 42
... perimeter by half the radius of the inscribed cir- F64 cle- Let A B C D E F ( fig . 64 ) be the polygon , and NP the radius of the inscribed circle . From the centre O draw lines to all the vertices . These will all be equal , being ...
... perimeter by half the radius of the inscribed cir- F64 cle- Let A B C D E F ( fig . 64 ) be the polygon , and NP the radius of the inscribed circle . From the centre O draw lines to all the vertices . These will all be equal , being ...
Other editions - View all
Elements of Geometry: With Practical Applications, for the Use of Schools Timothy Walker No preview available - 2023 |
Elements of Geometry: With Practical Applications, for the Use of Schools Timothy Walker No preview available - 2019 |
Common terms and phrases
A B C D A B fig adjacent angles axis B A C base and altitude base multiplied bisect called centre chord circ circumference coincide convex surface cube cylinder D E F demonstrated diameter divided draw equally distant equivalent found by multiplying frustum geometry given line gles height Hence homologous sides hundredths inches infinite number infinitely small inscribed angles inscribed circle inscribed sphere intersection line A B line drawn linear unit mean proportional method of Exhaustions number of sides parallel sides perimeter perpendicular polyedrons preceding proposition proved pyramid radii radius ratio regular polygon rence right angle right parallelogram right parallelopiped right triangle semicircumference similar triangles solid angles sphere square feet straight line Suppose tangent tion trapezoid triangles A B C triangles are equal triangular prism vertex vertices
Popular passages
Page ii - Co. of the said district, have deposited in this office the title of a book, the right whereof they claim as proprietors, in the words following, to wit : " Tadeuskund, the Last King of the Lenape. An Historical Tale." In conformity to the Act of the Congress of the United States...
Page xiv - Magnitudes which coincide with one another, that is, which exactly fill the same space, are equal to one another.
Page 30 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Page xiv - LET it be granted that a straight line may be drawn from any one point to any other point.
Page 25 - In any proportion, the product of the means is equal to the product of the extremes.
Page 38 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Page 25 - Multiplying or dividing both the numerator and denominator of a fraction by the same number does not change the value of the fraction.
Page xiv - Things which are equal to the same thing are equal to one another. 2. If equals be added to equals, the wholes are equal. 3. If equals be taken from equals, the remainders are equal. 4. If equals be added to unequals, the wholes are unequal. 5. If equals be taken from unequals, the remainders are unequal. 6. Things which are double of the same are equal to one another.
Page 42 - The area of a trapezoid is equal to the product of its altitude, by half the sum of its parallel bases.
Page xiv - If a straight line meets two straight lines, so as to make the two interior angles on the same side of it taken together lesi than two right angles...