The Elements of Algebra |
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Page 141
... interest at 4 per cent . , and 4 years after £ 8000 . out at 5 per cent . will the interest received from the one other sum ? Ans . 10 . In how many years equal that from the ( 22 ) The circumference of each of the two EQUATIONS . 141.
... interest at 4 per cent . , and 4 years after £ 8000 . out at 5 per cent . will the interest received from the one other sum ? Ans . 10 . In how many years equal that from the ( 22 ) The circumference of each of the two EQUATIONS . 141.
Page 230
... + x + + 1.2 2.3 + & c . To find e let x = 1 ; 1 1 ..e = 1 + 1 + + 1.2 2.3 + & c . = 3 2.71828 , & c . a value which we have had occasion to mention . APPENDIX . LOGARITHMS . SIMPLE AND COMPOUND INTEREST . 1. 230 BINOMIAL THEOREM .
... + x + + 1.2 2.3 + & c . To find e let x = 1 ; 1 1 ..e = 1 + 1 + + 1.2 2.3 + & c . = 3 2.71828 , & c . a value which we have had occasion to mention . APPENDIX . LOGARITHMS . SIMPLE AND COMPOUND INTEREST . 1. 230 BINOMIAL THEOREM .
Page 231
Thomas Grainger Hall. APPENDIX . LOGARITHMS . SIMPLE AND COMPOUND INTEREST . 1. IF N be a number such that N = a " , then x is said to be the logarithm of N and a is called the base of the system of logarithms . Hence a logarithm may be ...
Thomas Grainger Hall. APPENDIX . LOGARITHMS . SIMPLE AND COMPOUND INTEREST . 1. IF N be a number such that N = a " , then x is said to be the logarithm of N and a is called the base of the system of logarithms . Hence a logarithm may be ...
Page 235
... INTEREST AND DISCOUNT . 3. Let P = the principal or sum lent , r = interest of £ ( 1 ) for one year , n time ; .. nr = interest of £ 1 . for the time ( n ) , and Pur = interest of £ P for the time ( n ) , or if I be the interest , I ...
... INTEREST AND DISCOUNT . 3. Let P = the principal or sum lent , r = interest of £ ( 1 ) for one year , n time ; .. nr = interest of £ 1 . for the time ( n ) , and Pur = interest of £ P for the time ( n ) , or if I be the interest , I ...
Page 236
... interest on £ 120 . for 3 years at 4 per cent . .04 ; Here r = 4 100 = .. I = 120 × 3 × .04 - = 14.4 £ 14 . 88. , 120 × 3 × 4 40 or by the common rule , I - £ 14 . £ 14 , 8s . 100 100 COR . The amount ( M ) is the principal + the interest ...
... interest on £ 120 . for 3 years at 4 per cent . .04 ; Here r = 4 100 = .. I = 120 × 3 × .04 - = 14.4 £ 14 . 88. , 120 × 3 × 4 40 or by the common rule , I - £ 14 . £ 14 , 8s . 100 100 COR . The amount ( M ) is the principal + the interest ...
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Common terms and phrases
2ab+b² a²+2ab+b² a²x² a³b ab² ab³ algebraical quantities arithmetic mean arithmetic series arithmetical progression ax² binomial coefficient common difference compound cube root decimal denominator digits divided dividend division divisor equal examples expressed Extract the square factor Find the greatest find the numbers Find the sum fraction geometrical progression greatest common divisor greatest common measure Hence last term least common multiple less letters logarithm multiplied negative number of terms numbers in arithmetical P₁ permutations QUADRATIC EQUATIONS quotient ratio remainder result rule shew square root subtract surd third unity unknown quantity whence write written xy³
Popular passages
Page 38 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Page 199 - Three lines are in harmonical proportion, when the first is to the third, as the difference between the first and second, is to the difference between the second and third ; and the second is called a harmonic mean between the first and third. The expression 'harmonical proportion...
Page 22 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Page 173 - If the product of two quantities be equal to the product of two others, two of them may be made the extremes and the other two the means of a proportion.