 | Alexander Ingram - Mathematics - 1830 - 458 pages
...term of the dividend by the first term of the divisor to obtain the first term of the quotient, then multiply the whole divisor by this term, and subtract the product from the dividend ; the remainder is a new dividual, with whicli proceed as before. NOTE. — When the remainder is a... | |
 | Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 326 pages
...the first term on the left of the divisor, and the first term of the quotient is found ; multiply the divisor by this term, and subtract the product from the dividend. Divide the first term of this remainder by the first term of the divisor, and the second term of the quotient is found ; multiply... | |
 | Charles Frederick Partington - Encyclopedias and dictionaries - 1838 - 1116 pages
...the dividend by the first term in the divisor, and the result will be the first term of the required quotient; multiply the whole divisor by this term, and subtract the product from the whole dividend. Then divide the first term of the remainder by the first term of the divisor, and the... | |
 | Alexander Ingram - 1844 - 262 pages
...term of the dividend by the first term of the divisor to obtain the first term of the quotient, then multiply the whole divisor by this term, and subtract the product from the dividend ; bring down as many terms to the remainder as is requisite for a new dividual, with which proceed... | |
 | James Elliot - 1850 - 116 pages
...of some one letter contained in them : then divide the first term of the dividend by the first term of the divisor, for the first term of the quotient. Multiply the whole divisor by the term thus found. Subtract the product from the corresponding terms of the dividend : bring down... | |
 | Charles Davies - Algebra - 1857 - 408 pages
...certain letter, and then divide the first term on the left of the dividend by the first term on the left of the divisor, for the first term of the quotient; multiply the divisor by this term and subtract the product from ike dividend. II. Then divide the fast term of the... | |
 | Isaac Todhunter - Algebra - 1858 - 530 pages
...first term of the divisor is contained in the first term of the dividend, and write down this result for the first term of the quotient ; multiply the...term, and subtract the product from the dividend. Bring down as many terms of the dividend as the case may require, and repeat the operation till all... | |
 | Isaac Todhunter - 1860 - 620 pages
...of the divisor is contained in the first term of the dividend, and write down this result for tlte first term of the quotient; multiply the whole divisor by this term, and subtract the product from tlie dividend. Bring down as many terms of the dividend as the case may require, and repeat the operation... | |
 | Charles Davies - Algebra - 1860 - 412 pages
...certain letter, and then divide the first term on the left of the dividend by the first term on the left of the divisor, for the first term of the quotient ; multiply the divisor by this term and subtract the product from the dividend. II. Then divide the first term of... | |
 | Charles Davies - Algebra - 1860 - 330 pages
...divisor with reference to the same letter : II. Divide the first term of the dividend by the first term of the divisor, for the first term of the quotient. Multiply the divisor by this term of the quotient, and subtract the product from the dividend: m. Divide the first... | |
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Divide the first term of the dividend by the first term of the divisor, giving the first term of the quotient. Multiply the whole divisor by this term, and subtract the product from the dividend, arranging the remainder in the same order of powers as... 
