| Alexander Ingram - 1830
...term of the dividend by the first term of the divisor to obtain the first term of the quotient, then **multiply the whole divisor by this term, and subtract the product from the dividend** ; the remainder is a new dividual, with whicli proceed as before. NOTE. — When the remainder is a... | |
| Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 304 pages
...the first term on the left of the divisor, and the first term of the quotient is found ; multiply the **divisor by this term, and subtract the product from the dividend. Divide the first term of** this remainder by the first term of the divisor, and the second term of the quotient is found ; multiply... | |
| Charles Frederick Partington - Encyclopedias and dictionaries - 1838
...the dividend by the first term in the divisor, and the result will be the first term of the required **quotient; multiply the whole divisor by this term, and subtract the product from the** whole dividend. Then divide the first term of the remainder by the first term of the divisor, and the... | |
| Alexander Ingram - 1844
...term of the dividend by the first term of the divisor to obtain the first term of the quotient, then **multiply the whole divisor by this term, and subtract the product from the dividend** ; bring down as many terms to the remainder as is requisite for a new dividual, with which proceed... | |
| James Elliot - 1850
...of some one letter contained in them : then divide the first term of the dividend by the first term **of the divisor, for the first term of the quotient. Multiply the whole divisor by** the term thus found. Subtract the product from the corresponding terms of the dividend : bring down... | |
| Charles Davies, M. Bourdon (Louis Pierre Marie) - Algebra - 1857 - 400 pages
...certain letter, and then divide the first term on the left of the dividend by the first term on the left **of the divisor, for the first term of the quotient; multiply the** divisor by this term and subtract the product from ike dividend. II. Then divide the fast term of the... | |
| Isaac Todhunter - Algebra - 1858 - 496 pages
...first term of the divisor is contained in the first term of the dividend, and write down this result **for the first term of the quotient ; multiply the...term, and subtract the product from the dividend.** Bring down as many terms of the dividend as the case may require, and repeat the operation till all... | |
| Isaac Todhunter - 1860
...of the divisor is contained in the first term of the dividend, and write down this result for tlte **first term of the quotient; multiply the whole divisor by this term, and subtract the product from** tlie dividend. Bring down as many terms of the dividend as the case may require, and repeat the operation... | |
| Charles Davies - Algebra - 1860 - 400 pages
...certain letter, and then divide the first term on the left of the dividend by the first term on the left **of the divisor, for the first term of the quotient ; multiply the** divisor by this term and subtract the product from the dividend. II. Then divide the first term of... | |
| Charles Davies - Algebra - 1860 - 299 pages
...divisor with reference to the same letter : II. Divide the first term of the dividend by the first term **of the divisor, for the first term of the quotient. Multiply the** divisor by this term of the quotient, and subtract the product from the dividend: m. Divide the first... | |
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