## Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive System of Practical Arithmetic, Adapted to the Use of Schools in the United States... |

### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Other editions - View all

Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive ... Nathan Daboll No preview available - 2016 |

Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive ... Nathan Daboll No preview available - 2017 |

### Common terms and phrases

2qrs 3qrs acres added addition amount annuity answer barrels bought bushels called cent cent per annum ciphers common common denominator compound contained contents continue cost cube root cubic currency decimal denominator diameter difference divide dividend divisor dollars dols equal EXAMPLES expressed factors Federal money feet figure foot fraction gain gallons given given number gives greater half Hence hogshead hundred inches interest least leave length less loss measure merchant method miles mills months Multiply Note Operation paid payment period piece pound present worth principal proportion quantity Questions quotient rate per cent ratio received Reduce remainder right hand rods RULE share shillings side simple sold solid square root subtract sugar tare tens term thick third thousand units weight whole number wide write yards

### Popular passages

Page 207 - Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.

Page 191 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.

Page 195 - Find the first figure of the root by trial, and subtract its power from the left hand period of the given number. 3. To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.

Page 167 - Multiply all the numerators together for a new numerator, and all the denominators for a new denominator; and they will form the fraction required.

Page 183 - ... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...

Page 106 - Let the farthings in the given pence and farthings possess the second and third places ; observing to increase the second place or place of hundredths, by 6 if the shillings be odd ; and the third place by 1 "when the farthings exceed 12, and by 2 when they exceed 36. EXAMPLES. 1. Find the decimal of 7s. 9fd. by inspection. ,3 =4 6s. 5 for the odd shillings. 39=the farthings in 9|d. 2 for the excess of 36. £. ,391=dechnal required'.

Page 141 - Compute the interest to the time of the first payment ; if that be one year or more from the time the interest commenced , add it to the principal, and deduct the payment from the sum total. If there be after payments made, compute the interest on the balance due, to the next payment, and then deduct the payment as above ; and in like manner from one payment to another till all the payments are absorbed ; provided the time between one payment and another be one year or more.

Page 44 - If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before.

Page 228 - What difference is there between the interest of 500Z. at 5 per cent, for 12 j'ears, and the discount of the same sum at the same rate, and for the same time ? Ans.

Page 119 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.