The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for the Use of Schools in the United States |
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Page 7
I have 100 bushels zef wheat , worth 125 dollars , 150 6 . A man has three fields ,
| bushels of rye , worth 90 dolone contains 12 acres , ano . | | lars , and 90
bushels of corn , ther 23 acres , and the other worth 45 dollars ; how many 47
acres ...
I have 100 bushels zef wheat , worth 125 dollars , 150 6 . A man has three fields ,
| bushels of rye , worth 90 dolone contains 12 acres , ano . | | lars , and 90
bushels of corn , ther 23 acres , and the other worth 45 dollars ; how many 47
acres ...
Page 68
A holds a nole against B for $ 218 , payable in one year and six months without
interest , which he wishes to turn out to B in payment for a farm ; what is the
present worth of the note , supposing the use of money we be worth 6 per ceni .
per ...
A holds a nole against B for $ 218 , payable in one year and six months without
interest , which he wishes to turn out to B in payment for a farm ; what is the
present worth of the note , supposing the use of money we be worth 6 per ceni .
per ...
Page 73
... to be found . Denoting the unknown term by the letter x , the proportion would
stand lem . lem . . ets . cts . · lem . cts . fem . ca . Now , since the product of the
extremes is equal. 4 6 : : 12 : . or 4 : 12 : : 6 : 1 . - 1 . A person has lea worth 40
cents a.
... to be found . Denoting the unknown term by the letter x , the proportion would
stand lem . lem . . ets . cts . · lem . cts . fem . ca . Now , since the product of the
extremes is equal. 4 6 : : 12 : . or 4 : 12 : : 6 : 1 . - 1 . A person has lea worth 40
cents a.
Page 81
... which are worth 8 cents a quart , with 2 quarts worth 12 cents a quart , what will
a quart of the mixture bo worth ? ' ( 60 ) Six quarts at 8 cents are worth ( 8X6 = )
48 cents , and 2 quarts at 12 cents are worth ( 12X2 = ) 24 cents ; then 48 + 24 ...
... which are worth 8 cents a quart , with 2 quarts worth 12 cents a quart , what will
a quart of the mixture bo worth ? ' ( 60 ) Six quarts at 8 cents are worth ( 8X6 = )
48 cents , and 2 quarts at 12 cents are worth ( 12X2 = ) 24 cents ; then 48 + 24 ...
Page 82
the whole mixture , and 72 : 8 ( 6 + 2 , the whole mixture ) 9 cents , the worth of 1
quart of the mixture . When the prices and quantities of the simples are given ,
and it is required to find the price of a given quantity of the mixture , as in the ...
the whole mixture , and 72 : 8 ( 6 + 2 , the whole mixture ) 9 cents , the worth of 1
quart of the mixture . When the prices and quantities of the simples are given ,
and it is required to find the price of a given quantity of the mixture , as in the ...
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Common terms and phrases
acres added Addition amount ANALYSIS answer body bush bushels called cash cents Change ciphers column common compound contains cost cube cubic decimal denominator denoted diameter difference distance divide dividend division divisor dollars dolls equal evidently example expressed factors feet figures foot four fraction gain gallon give given greater half Hence hundred hundredths inches interest least left hand length less mean measure method miles months multiply names operation payment period person pound principal proceed proportion quantity QUESTIONS FOR PRACTICE quotient ratio receive Reduce remainder right hand rods root rule share shillings side simple solid square square root subtract supposed tens tenths third tion units vulgar weight whole worth write written yard
Popular passages
Page 82 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.
Page 89 - The greatest common divisor of two or more numbers, is the greatest number which will divide them without a remainder. Thus 6 is the greatest common divisor of 12, 18, 24, and 30.
Page 118 - PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct.
Page 111 - Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend...
Page 94 - It will be seen that we multiply the denominator of the dividend by the numerator of the divisor for the denominator of the quotient, and the numerator of the dividend by the denominator of the divisor for the numerator of the quotient.
Page 120 - Add together the most convenient indices to make an index less by 1 than the number expressing the place of the term sought. 3. Multiply the terms of the geometrical series together belonging to those indices, and make the product a dividend. 4. Raise...
Page 115 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 31 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Page 2 - Los números cardinales 0: zero 1: one 2: two 3: three 4: four 5: five 6: six 7: seven 8: eight 9: nine 10: ten 11: eleven 12: twelve 13: thirteen 14: fourteen 15: fifteen 16: sixteen 17: seventeen 18: eighteen 19: nineteen 20: twenty...
Page 93 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.