The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for the Use of Schools in the United States |
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Page
... side of it ; and 3dly , by . writing the number to be divided over the other in the form of a fraction ; thus 2 ) 6 ( 3 , and 6 ÷÷ 2 = 3 and § = 3 , all signify the same thing , namely , that if 6 be divided by 2 the quotient is 3 ...
... side of it ; and 3dly , by . writing the number to be divided over the other in the form of a fraction ; thus 2 ) 6 ( 3 , and 6 ÷÷ 2 = 3 and § = 3 , all signify the same thing , namely , that if 6 be divided by 2 the quotient is 3 ...
Page 17
... side of the 1 hundred , making 15 tens , and find 2 in 15 , 7 times . But as 15 are so many tens ; the 7 must be tens also , and must occupy the place next below hundreds in the quotient . We now multiply the diviser by 7 , and write ...
... side of the 1 hundred , making 15 tens , and find 2 in 15 , 7 times . But as 15 are so many tens ; the 7 must be tens also , and must occupy the place next below hundreds in the quotient . We now multiply the diviser by 7 , and write ...
Page 28
... side . 0.5 ft . by 0.5 gives a square , measuring 0.5 ft . equal to foot on each side . Br the latter square , as shown by the diagram , is only 0.25 , or of the former ; hence 0.25 is evidently the product of 0.5 by Ans . 0.25 ft ...
... side . 0.5 ft . by 0.5 gives a square , measuring 0.5 ft . equal to foot on each side . Br the latter square , as shown by the diagram , is only 0.25 , or of the former ; hence 0.25 is evidently the product of 0.5 by Ans . 0.25 ft ...
Page 40
... side , and contains 12X12 = 144 square inches . 3 feet in length make a yard ; a square yard is a square measuring 3 feet on each side : but such a square contains ( see figure ) nine ( 3X3 = 9 ) squares measuring a foot on each side ...
... side , and contains 12X12 = 144 square inches . 3 feet in length make a yard ; a square yard is a square measuring 3 feet on each side : but such a square contains ( see figure ) nine ( 3X3 = 9 ) squares measuring a foot on each side ...
Page 49
... sides , whose lengths are as follows : 4ch . 27lin . 5ch . 19lin . 4ch . 50lin . and 6ch . 4lin .; what is the distance round it ? Ans . 20 ch . What is the weight of 3hhd . of sugar , the first weighing 10cwt . 201b .; the 2d , 9cwt ...
... sides , whose lengths are as follows : 4ch . 27lin . 5ch . 19lin . 4ch . 50lin . and 6ch . 4lin .; what is the distance round it ? Ans . 20 ch . What is the weight of 3hhd . of sugar , the first weighing 10cwt . 201b .; the 2d , 9cwt ...
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Common terms and phrases
3qrs acres Addition amount ANALYSIS answer Arithmetic bush bushels called ciphers circumference column common denominator common difference compound interest contains cost cube root cubic decimal denoted diameter divi divide dividend division dollars dolls DRY MEASURE equal evidently expressed factors Federal Money feet long foot gain gallon given number given to find greatest common divisor Hence hundred hundredths inches least common multiple least terms left hand leger lemons length man's share merator method miles minuend mixed number months multiplicand multiply number of figures number of terms payment pence pound present worth principal proportion quantity quarts QUESTIONS FOR PRACTICE ratio Reduce remainder right hand rods RULE RULE.-Divide RULE.-Multiply shillings side simple solid square root subtract subtrahend supposed tens tenths tion Troy weight units velocity vulgar fraction weight whole number write
Popular passages
Page 82 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.
Page 89 - The greatest common divisor of two or more numbers, is the greatest number which will divide them without a remainder. Thus 6 is the greatest common divisor of 12, 18, 24, and 30.
Page 118 - PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct.
Page 111 - Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend...
Page 94 - It will be seen that we multiply the denominator of the dividend by the numerator of the divisor for the denominator of the quotient, and the numerator of the dividend by the denominator of the divisor for the numerator of the quotient.
Page 120 - Add together the most convenient indices to make an index less by 1 than the number expressing the place of the term sought. 3. Multiply the terms of the geometrical series together belonging to those indices, and make the product a dividend. 4. Raise...
Page 115 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 31 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Page 2 - Los números cardinales 0: zero 1: one 2: two 3: three 4: four 5: five 6: six 7: seven 8: eight 9: nine 10: ten 11: eleven 12: twelve 13: thirteen 14: fourteen 15: fifteen 16: sixteen 17: seventeen 18: eighteen 19: nineteen 20: twenty...
Page 93 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.