## The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for the Use of Schools in the United States |

### From inside the book

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Page 41

9

« 1 sq . rod , rd . | | 1568160 10890 1210 40 1 | 40 rods ro . | 6272640 ] 43560

4840 160 41 4 roods , « 1 acre , acr . 110 choine moketaren | 640 acres 66 1 sq ...

9

**feet**" 1 sq . yard , yd . | | 12969 80 % yards . " 1 sq . rod , rd . 392041 ' 2724**feet**,« 1 sq . rod , rd . | | 1568160 10890 1210 40 1 | 40 rods ro . | 6272640 ] 43560

4840 160 41 4 roods , « 1 acre , acr . 110 choine moketaren | 640 acres 66 1 sq ...

Page 114

2 is 20 , that is , 8000 feel of the stone will make a pile measuring 20 3 * * *

0072X30 = 1260 ) 4167

remain to be add1200X3 _ 3600 ed to this pile in such a manner as 69X3X3 =

510 to ...

2 is 20 , that is , 8000 feel of the stone will make a pile measuring 20 3 * * *

0072X30 = 1260 ) 4167

**feet**on each side , and ( 12167 – 8000 – ) 4167**feet**remain to be add1200X3 _ 3600 ed to this pile in such a manner as 69X3X3 =

510 to ...

Page 135

What is the area of a cir . circle whose diameter is 7 , and cle whose diameter is

10 roda , circumference 22

circumference . Ans . 78 . 54 rods . 3 . 5 % ) diameter . 4 . How Inany square

chains 55 in a ...

What is the area of a cir . circle whose diameter is 7 , and cle whose diameter is

10 roda , circumference 22

**feet**? | and circumference 31 . 416 ? 11 = dcircumference . Ans . 78 . 54 rods . 3 . 5 % ) diameter . 4 . How Inany square

chains 55 in a ...

Page 137

YENSURATION OF SOLIDS . 137 1 . What is the content of a 2 . How many

in a stick parallelopipedon whose length of hewn timber 30

its breadth 24

YENSURATION OF SOLIDS . 137 1 . What is the content of a 2 . How many

**feet**in a stick parallelopipedon whose length of hewn timber 30

**feet**long , is 6**feet**,its breadth 24

**feet**, 9 inches broad , and . 6 inches and its depth lf**feet**? thick ? Page 149

Having two dimensions in

other must be in order to hold a given quantity . RULE . - Multiply the given

dimensions together for a divisor , and multiply the given quantity by the cubic

Having two dimensions in

**feet**of a bin , box , or coal - house , to find what theother must be in order to hold a given quantity . RULE . - Multiply the given

dimensions together for a divisor , and multiply the given quantity by the cubic

**feet**in a ...### What people are saying - Write a review

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### Common terms and phrases

acres added Addition amount ANALYSIS answer body bush bushels called cash cents Change ciphers column common compound contains cost cube cubic decimal denominator denoted diameter difference distance divide dividend division divisor dollars dolls equal evidently example expressed factors feet figures foot four fraction gain gallon give given greater half Hence hundred hundredths inches interest least left hand length less mean measure method miles months multiply names operation payment period person pound principal proceed proportion quantity QUESTIONS FOR PRACTICE quotient ratio receive Reduce remainder right hand rods root rule share shillings side simple solid square square root subtract supposed tens tenths third tion units vulgar weight whole worth write written yard

### Popular passages

Page 82 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.

Page 89 - The greatest common divisor of two or more numbers, is the greatest number which will divide them without a remainder. Thus 6 is the greatest common divisor of 12, 18, 24, and 30.

Page 118 - PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct.

Page 111 - Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend...

Page 94 - It will be seen that we multiply the denominator of the dividend by the numerator of the divisor for the denominator of the quotient, and the numerator of the dividend by the denominator of the divisor for the numerator of the quotient.

Page 120 - Add together the most convenient indices to make an index less by 1 than the number expressing the place of the term sought. 3. Multiply the terms of the geometrical series together belonging to those indices, and make the product a dividend. 4. Raise...

Page 115 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.

Page 31 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.

Page 2 - Los números cardinales 0: zero 1: one 2: two 3: three 4: four 5: five 6: six 7: seven 8: eight 9: nine 10: ten 11: eleven 12: twelve 13: thirteen 14: fourteen 15: fifteen 16: sixteen 17: seventeen 18: eighteen 19: nineteen 20: twenty...

Page 93 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.