The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for the Use of Schools in the United States |
From inside the book
Results 1-5 of 14
Page 6
216 dolls . gin with the right hand colunm - 3 and 4 are 7 , and 6 84 dolls . are 13 ; but 13 are l'ten and 3 units ; we therefore write 63 dolls . the 3 under the column of units , and carry the 1 ten te the column of tens , saying , 1 ...
216 dolls . gin with the right hand colunm - 3 and 4 are 7 , and 6 84 dolls . are 13 ; but 13 are l'ten and 3 units ; we therefore write 63 dolls . the 3 under the column of units , and carry the 1 ten te the column of tens , saying , 1 ...
Page 7
Ans . 82 . worth 260 dolls . 7. A person killed an ox , 12. A man killed 4 hogs , the meat of which weighed one'weighed 371 pounds , one : 842 pounds , the ' hide 105 510 pounds , one 472 pounds , " pounds , and the tallow 92 and the ...
Ans . 82 . worth 260 dolls . 7. A person killed an ox , 12. A man killed 4 hogs , the meat of which weighed one'weighed 371 pounds , one : 842 pounds , the ' hide 105 510 pounds , one 472 pounds , " pounds , and the tallow 92 and the ...
Page 8
20485 dolls . ly 31 , in August 31 , in Sep 16. According to the centember 30 , in October 31 , in sus of the United States in November 30 , and in Decem 1820 , there were 3995053 free her 81 days ? Ans . 365 . white males , 3866657 ...
20485 dolls . ly 31 , in August 31 , in Sep 16. According to the centember 30 , in October 31 , in sus of the United States in November 30 , and in Decem 1820 , there were 3995053 free her 81 days ? Ans . 365 . white males , 3866657 ...
Page 11
If a man's income be i among 207 men , each man's dollar a day , what will be the share was 534 dollars ; what amount of his income in 45 was the value of the prize ? years , allowing 365 days to 534 dolls . each year ?
If a man's income be i among 207 men , each man's dollar a day , what will be the share was 534 dollars ; what amount of his income in 45 was the value of the prize ? years , allowing 365 days to 534 dolls . each year ?
Page 14
We now proceed 542 dolls . to the tens , but find we cannot take 4 tens from 2 tens . We may , however , separate 7 hundreds into two parts , Ains . 185 dolls . one of which shall be 6 hundred , and the other 1 hundred , or 10 tens ...
We now proceed 542 dolls . to the tens , but find we cannot take 4 tens from 2 tens . We may , however , separate 7 hundreds into two parts , Ains . 185 dolls . one of which shall be 6 hundred , and the other 1 hundred , or 10 tens ...
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Common terms and phrases
acres added Addition amount ANALYSIS answer bush bushels called cash cents Change ciphers column common compound contains cost cube cubic decimal denominator denoted diameter difference distance divide dividend division divisor dollars dolls equal evidently example expressed factors feet figures foot four fraction gain gallon give given greater half Hence hundred hundredths inches interest least left hand length less mean measure method miles months multiplicand multiply names operation payment period person pound principal proceed proportion quantity QUESTIONS FOR PRACTICE quotient ratio receive Reduce remainder right hand rods root rule share shillings side simple solid square square root subtract supposed tens tenths third tion units vulgar weight whole worth write written yard
Popular passages
Page 82 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.
Page 89 - The greatest common divisor of two or more numbers, is the greatest number which will divide them without a remainder. Thus 6 is the greatest common divisor of 12, 18, 24, and 30.
Page 118 - PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct.
Page 111 - Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend...
Page 94 - It will be seen that we multiply the denominator of the dividend by the numerator of the divisor for the denominator of the quotient, and the numerator of the dividend by the denominator of the divisor for the numerator of the quotient.
Page 120 - Add together the most convenient indices to make an index less by 1 than the number expressing the place of the term sought. 3. Multiply the terms of the geometrical series together belonging to those indices, and make the product a dividend. 4. Raise...
Page 115 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 31 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Page 2 - Los números cardinales 0: zero 1: one 2: two 3: three 4: four 5: five 6: six 7: seven 8: eight 9: nine 10: ten 11: eleven 12: twelve 13: thirteen 14: fourteen 15: fifteen 16: sixteen 17: seventeen 18: eighteen 19: nineteen 20: twenty...
Page 93 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Bibliographic information
| Title | The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for the Use of Schools in the United States |
| Author | Zadock Thompson |
| Publisher | H. Johnson, 1838 |
| Original from | Harvard University |
| Digitized | 29 Jan 2007 |
| Length | 164 pages |
| Export Citation | BiBTeX EndNote RefMan |