A New and Complete System of Arithmetick: Composed for the Use of the Citizens of the United States |
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Page 10
... Bill of Parcels 122 125 132 133 137 140 141 143 - 144 148 150 152 155 157 180 Tare and Tret 180 Involution 182 Evolution 184 Table of Powers Extraction of the Square Root Application and Use of the Square Root Extraction of the Cube ...
... Bill of Parcels 122 125 132 133 137 140 141 143 - 144 148 150 152 155 157 180 Tare and Tret 180 Involution 182 Evolution 184 Table of Powers Extraction of the Square Root Application and Use of the Square Root Extraction of the Cube ...
Page 134
... bill of exchange for £ 537 10s . 6d . Massachusetts , to be paid in Ireland , at £ 123 Massachusetts , per £ 100 Irish , or 16 Mass . for 13 Irish ; for how much Irish money must I draw the bill ? Ans . £ 436 14s . 91d Irish . 52 ...
... bill of exchange for £ 537 10s . 6d . Massachusetts , to be paid in Ireland , at £ 123 Massachusetts , per £ 100 Irish , or 16 Mass . for 13 Irish ; for how much Irish money must I draw the bill ? Ans . £ 436 14s . 91d Irish . 52 ...
Page 179
... many pounds of tea , at 5s . per lb. for £ 37 ? 148lb . Ans . 3d . How many yards at 9s . per yard may I have for £ 540 ? Ans . 1200 yards . 100 70 30 BILL OF PARCELS . Mr. Timothy Huckster Newburyport , January PRACTICE . 179.
... many pounds of tea , at 5s . per lb. for £ 37 ? 148lb . Ans . 3d . How many yards at 9s . per yard may I have for £ 540 ? Ans . 1200 yards . 100 70 30 BILL OF PARCELS . Mr. Timothy Huckster Newburyport , January PRACTICE . 179.
Page 180
... BILL OF PARCELS . Mr. Timothy Huckster Newburyport , January 1st , 1808 . Bought of Samuel Merchant , 25 Bohea tea , at 3s . 6d . per b . 48 Cheese , at 9d . per . 15 Pair worsted hose , at 5s . 8d . per pair . 4 Dozen women's gloves ...
... BILL OF PARCELS . Mr. Timothy Huckster Newburyport , January 1st , 1808 . Bought of Samuel Merchant , 25 Bohea tea , at 3s . 6d . per b . 48 Cheese , at 9d . per . 15 Pair worsted hose , at 5s . 8d . per pair . 4 Dozen women's gloves ...
Page 254
... bill of $ 359 was due January 1 , 1807 ; that $ 75 was paid February 3d , $ 50 March 5th , $ 80 April 9th , and June 7th , $ 145 What interest is due at 5 , 6 and 7 per cent . ? Dates . | Bill . Days | Products . January 1 . $ 350 33 ...
... bill of $ 359 was due January 1 , 1807 ; that $ 75 was paid February 3d , $ 50 March 5th , $ 80 April 9th , and June 7th , $ 145 What interest is due at 5 , 6 and 7 per cent . ? Dates . | Bill . Days | Products . January 1 . $ 350 33 ...
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A New and Complete System of Arithmetick: Composed for the Use of the ... Nicolas Pike, U.S,Chester Dewey No preview available - 2016 |
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amount annexed annuity annum answer assumed root Avoirdupois Balance bushels ciphers circle common difference compound interest cube root cubick currency debt decimal denominator diameter discount ditto divide the product dividend divisor dollars Dominical Letter endorsement English Epact equal EXAMPLES farthings Federal Money feet figure find the value foot fourth gain gallons geometrical Geometrical Progression given number gold Golden Number greatest term half Hence inches integer last term Leger length livres Livres Tournois measure miles moidore months multiplicand Multiply Note number of terms payment pence perpendicular pound sterling pounds present worth principal Prob PROBLEM proportion quotient rate per cent ratio Reduce remainder repetend right hand Rule of Three shillings side solid Spanish dollar specifick gravity square root sterling subtract Suppose surd Table Theorem third term velocity vulgar fraction weight whole number yards cost
Popular passages
Page 263 - If the payment exceeds the interest, the surplus goes towards discharging the principal, and the subsequent interest is to be computed on the balance of principal remaining due. If the payment be less than the interest, the surplus of interest must not be taken to augment the principal ; but interest continues on the former principal until the period when the payments, taken together, exceed the interest due, and then the surplus is to be applied towards discharging the principal, and interest is...
Page 349 - If the errors are alike, divide the difference of tire products by the difference of the errors, and the quotient will be the answer. 5. If the errors are unlike, divide the sum of the products by the sum of the errors, and the quotient will be the answer.
Page 191 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 199 - Find the first figure of the root by trial, and subtract its power from the" left hand period of the given number. 5. To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply, it by the number denoting the given power, for a divisor.
Page 69 - Operations with Fractions A) To change a mixed number to an improper fraction, simply multiply the whole number by the denominator of the fraction and add the numerator.
Page 86 - ... from the right hand of the quotient, point off so many places for decimals, as the decimal places in the dividend exceed those in the divisor.
Page 281 - RULE.* — Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the true time required.
Page 262 - If there be after-payments made, compute the interest on the balance due to the next payment, and then deduct the payment as above ; and, in like manner, from one payment to another, till all the payments are absorbed ; provided the time between one payment and another be one year or more.
Page 262 - ... then compute the interest on the principal sum due on the obligation for ONE YEAR, add it to the principal, and compute the interest on the sum paid from the time it was paid up to the end of the year; add it to the sum paid, and deduct that sum from the principal and interest added as above.
Page 346 - RULE. 1. Take any number and perform the same operations with it as are described to be performed in the question. 2. Then say as the sum of the errors is to the giren sum, so is the supposed number to the true one required.