The Elements of Arithmetic ... in which Decimal and Integral Arithmetic are Combined, and Taught Inductively: On the System of Pestalozzi. Part 1st [2d].U. Hunt and Son, 1844 |
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Page 19
... gives in addition , as well as for the exercise of the memory . 1. 49863 x .06 x 1.3 = ? 2. Multiply 7441.08 by 236 . 3. Find .06 of 284931.75 . 4. Find .0725 of 164.25 × 1000 . 5. 96.8 × 12000 × 45.93 = ? 6. Multiply 4489.076 by ...
... gives in addition , as well as for the exercise of the memory . 1. 49863 x .06 x 1.3 = ? 2. Multiply 7441.08 by 236 . 3. Find .06 of 284931.75 . 4. Find .0725 of 164.25 × 1000 . 5. 96.8 × 12000 × 45.93 = ? 6. Multiply 4489.076 by ...
Page 22
... give a quotient as large as , or larger than , the divisor , If there is but one such figure , it will be the one sought ; if there is more than one , the larger will be the true quotient figure . 1. Divide .0497 by 368000 . 2. What is ...
... give a quotient as large as , or larger than , the divisor , If there is but one such figure , it will be the one sought ; if there is more than one , the larger will be the true quotient figure . 1. Divide .0497 by 368000 . 2. What is ...
Page 26
... give each of them 5 , and have 1 left . If we wish to divide the re- maining apple among them , we must cut it into 3 equal parts , and give one to each of them . Each of those parts would be called one - third , and written 3 . Again ...
... give each of them 5 , and have 1 left . If we wish to divide the re- maining apple among them , we must cut it into 3 equal parts , and give one to each of them . Each of those parts would be called one - third , and written 3 . Again ...
Page 34
... gives 4071 for the true remainder . .4071 remainder . 1. Divide 870468 by 999 ; by 99 . 2. Divide 408176 by 999 ; by 9999 . 3. Divide 7963142 by 999000. Divide first by 999 , then divide the quotient by 1000 . 4. Divide 1046.84 by 993 ...
... gives 4071 for the true remainder . .4071 remainder . 1. Divide 870468 by 999 ; by 99 . 2. Divide 408176 by 999 ; by 9999 . 3. Divide 7963142 by 999000. Divide first by 999 , then divide the quotient by 1000 . 4. Divide 1046.84 by 993 ...
Page 36
... give to each remainder the name of the dividend from which it is derived . 1. In 41 chal . 19 bu . of coal , how many pecks ? 2. How many cut . & c . , in 1870953 gr . ? 3. How many , & c . , in 24753 gr . Troy ? 4. Reduce 195 113 33 to ...
... give to each remainder the name of the dividend from which it is derived . 1. In 41 chal . 19 bu . of coal , how many pecks ? 2. How many cut . & c . , in 1870953 gr . ? 3. How many , & c . , in 24753 gr . Troy ? 4. Reduce 195 113 33 to ...
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Common terms and phrases
5th power 9 hours acres amount annuity approximate values Arithmetic Avoirdupois bill BOARD bought bushel cents a pound column commence common difference compound interest contained continued fraction cost cube root cubic denominator diameter discount Divide dividend divisible dollars dominical letter duodecillion equal example exchange Extract extremes feet fraction gain gallons Geometrical Progression given number greatest common divisor harmonical means hours a day hundred improper fraction inches last term least common multiple less lowest terms marcs mean proportional miles minuend months multiplicand Multiply number of terms obtained oxen payable payment piece present worth prime factors prime number PROBLEM quotient figure ratio Reduce remainder repetend rods root figure RULE selling sold square number square root subtract sugar tens third trial divisor units weeks weight whole number wide yards zeroes లు
Popular passages
Page 136 - WHEN three numbers are such that the first is to the third, as the difference of the first and second is to the difference of the second and third...
Page 177 - To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity.
Page 30 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Page 18 - ... move the decimal point as many places to the right as there are ciphers in the multiplier.
Page 25 - Ten Pounds Avoirdupois Weight of distilled Water weighed in Air, at the Temperature of Sixty two Degrees of Fahrenheit's Thermometer, the Barometer being at Thirty Inches...
Page 27 - RULE. Multiply all the numerators together for a new numerator, and all the denominators for a new denominator: then reduce the new fraction to its lowest terms.
Page 20 - DIVISION is - the process by which we find how many times one number or part of a number is contained in, or may be subtracted from, another. The number to be divided is the dividend. The number to divide by, is the divisor. The number of times the dividend contains the divisor, is the quotient. The divisor and quotient may also be regarded as factors of the dividend. The number left, (if any,) after the operation, is the remainder.
Page 203 - ... 24 acres in 18 weeks; the grass being at first equal on every acre, and growing uniformly ? THE END.
Page 117 - ... nine integral cubes between 1 and 1000. All the other intermediate integers are imperfect cubes, and their roots can only be obtained approximately. All perfect cubes from 1 to 1000, evidently have but one integral figure in their cube root. All numbers between 1000 or 103, and 1000000 or 1003, will have two figures in their root. And generally, if we divide a cube into periods of three figures each, by placing a point over units, and one over every third figure from units, the number of points...
Page 18 - That from and after the passage of this act, the following silver coins shall be of the legal value, and shall pass current as money within the United States, by tale, for the payment of all debts and demands, at the rate of...