Ray's Algebra, Part First: On the Analytic and Inductive Methods of Instruction, with Numerous Practical Exercises, Designed for Common Schools and Academies, Part 1 |
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Page 7
... cents , which I wish to divide between William and Daniel , in such a manner , that Daniel shall have twice as many ... cents ; hence , 3 times a certain number is 15 . Now , if 3 times a certain number is 15 , one - third of 15 , or 5 ...
... cents , which I wish to divide between William and Daniel , in such a manner , that Daniel shall have twice as many ... cents ; hence , 3 times a certain number is 15 . Now , if 3 times a certain number is 15 , one - third of 15 , or 5 ...
Page 8
... cents ; after spending a part of them , he found he had as many left as he had spent ; how many cents had he spent ? 9. A pole 30 feet high was broken by a blast of wind ; the part broken off was equal to the part left standing ; what ...
... cents ; after spending a part of them , he found he had as many left as he had spent ; how many cents had he spent ? 9. A pole 30 feet high was broken by a blast of wind ; the part broken off was equal to the part left standing ; what ...
Page 9
... cents , and John has twice as many as James ; how many cents has each ? If a represents the number of cents James has , what will repre- sent the number John has ? What will represent the number they both have ? If 3x is equal to 18 ...
... cents , and John has twice as many as James ; how many cents has each ? If a represents the number of cents James has , what will repre- sent the number John has ? What will represent the number they both have ? If 3x is equal to 18 ...
Page 10
... cents ; he lost a certain number ; after this he gave away as many as he had lost , and then found that he had three ... cents ; John has twice as many as James , and James has three times as many as William ; how many cents has each ...
... cents ; he lost a certain number ; after this he gave away as many as he had lost , and then found that he had three ... cents ; John has twice as many as James , and James has three times as many as William ; how many cents has each ...
Page 11
... cents a piece , all for 25 cents ; if x repre- sents the number of lemons at 2 cents , what will represent their cost ? What will represent the cost of the lemons at 3 cents a piece ? How many lemons at each price did he buy ? 4. Mary ...
... cents a piece , all for 25 cents ; if x repre- sents the number of lemons at 2 cents , what will represent their cost ? What will represent the cost of the lemons at 3 cents a piece ? How many lemons at each price did he buy ? 4. Mary ...
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Common terms and phrases
acre added algebraic quantities apples arithmetical progression arithmetical series binomial Binomial Theorem bought bushels coefficient common difference complete equation Completing the square cost Divide the number dividend division dollars entire quantity equal EQUATIONS CONTAINING exactly divide exponent expressed extract the square Find a number Find the cube Find the product Find the square Find the sum find the value following examples fraction geometrical progression geometrical series Give an example greater greatest common divisor Hence least common multiple lemons less number letter minus monomial negative quantity number of places number of terms oranges perfect square polynomial positive quantity preceding principle proportion pupil quan question quotient radical sign ratio reduced remainder represent the number required the numbers required to find result second degree second power solution solving square root three numbers tities Transposing twice unknown quantity whole number yards
Popular passages
Page 60 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Page 106 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Page 178 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 235 - In any proportion the product of the means is equal to the product of the extremes.
Page 124 - A hare is 50 leaps before a greyhound, and takes 4 leaps to the greyhound's 3 ; but 2 of the greyhound's leaps are equal to 3 of the hare's ; how many leaps must the greyhound take to catch the hare ? Let x be the number of leaps taken by the hound.
Page 217 - If, then, any problem furnishes an equation in which the known term is negative, and greater than the square of half the coefficient of the first power of the unknown quantity, we infer, that the conditions of the problem are incompatible with each other.
Page 64 - That is, the square of the sum of two quantities is equal to the square of the first, plus twice the product of the first by the second, plus the square of the second.
Page 81 - The least Common Multiple of two or more quantities is the least quantity that will contain them exactly. Thus, 6 is the least common multiple of 2 and 3 ; and lOxy is the least common multiple of 2x and by. NOTE. — LCM stands for least common multiple.
Page 232 - If we compare the numbers 2 and 6, by the first method, we say that 2 is 4 less than 6, or that 6 is 4 greater than 2. If we compare 2 and 6 by the second method, we say that 6 is equal to three times 2, or that 2 is one third of 6.