| Jeremiah Day - Measurement - 1815 - 388 pages
...surface of a. hemisphere is equal to the product of its radius into the circumference of its base ; and the surface of a sphere is equal to the product of its diameter into its circumference. Cor. T . From this demonstration it follows, that the surface of any... | |
| Adrien Marie Legendre - Geometry - 1819 - 574 pages
...circle. This axis FG will be at the same time the diameter of the circumscribed circle. THEOREM. 535. The surface of a sphere is equal to the product of its diameter by the circumference of a great circle. Demonstration. 1. We say that the diameter of a sphere... | |
| Adrien Marie Legendre - Geometry - 1825 - 276 pages
...circle. This axis FG will be at the same time the diameter of the circumscribed circle, • THEOREM. 535. The surface of a sphere is equal to the product of its diameter by the circumference of a great circle. Demonstration. 1. We say that the diameter of a sphere... | |
| Adrien Marie Legendre, John Farrar - Geometry - 1825 - 280 pages
...circle. This axis FG will be at the same time the diameter of the circumscribed circle. THEOREM. 535. The surface of a sphere is equal to the product of its diameter by the circumference of a great circle. measure of^the surface of a greater sphere. For, if... | |
| Adrien Marie Legendre - Geometry - 1828 - 346 pages
...circle. This axis FG xvill at the same time be the diameter of the circumscribed circle. THEOREM. 535. The surface of a sphere is equal to the product of its diameter by the circumference of a great circle. We shall first shew, that the diameter of a sphere... | |
| Jeremiah Day - Measurement - 1831 - 394 pages
...surface of a hemisphere is equal to the product of its radius into the circumference of its base ; and the surface of a sphere is equal to the product of its diameter into its circumference. Cor. 1. From this demonstration it follows, that the surface of any... | |
| Jeremiah Day - Logarithms - 1831 - 418 pages
...surface of a hemisphere is equal to the product of its radius into the circumference of its base; and the surface. of a sphere is equal to the product of its diameter into its circumference. Cor. 1. From this demonstration it follows, that the surface of any... | |
| Adrien Marie Legendre - Geometry - 1836 - 394 pages
...described by ED + DC, is equal to (HI + IP) xcirc. ON, or equal to HP x circ. ON. PROPOSITION X. THEOREM. The surface of a sphere is equal to the product of its diameter by the circumference- of a great circle. Let ABCDE be -a semicircle. Inscribe in it any regular... | |
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