The course of arithmetic as taught in the Pestalozzian school, Worksop. [With] Answers1854 |
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Page 63
... side ; the same law being extended to the right side of the units ( after which let a point be placed ) , we shall find that the first figure next to the units expresses tenths , the second hundredths , the third thousandths , & c ...
... side ; the same law being extended to the right side of the units ( after which let a point be placed ) , we shall find that the first figure next to the units expresses tenths , the second hundredths , the third thousandths , & c ...
Page 176
... side the interest instead of the discount of those debts which he pays before they are due , whilst the other side of the operation is quite correct . 305. EXERCISES . 1. A owes B £ 1000 , to be paid yearly , in five equal payments ...
... side the interest instead of the discount of those debts which he pays before they are due , whilst the other side of the operation is quite correct . 305. EXERCISES . 1. A owes B £ 1000 , to be paid yearly , in five equal payments ...
Page 210
... side must be known , since that dimension is to be multiplied by itself ; for , if each of the sides be 8 inches , joining the points of division of the op- posite sides in order , we have 64 squares , each For this reason the name of ...
... side must be known , since that dimension is to be multiplied by itself ; for , if each of the sides be 8 inches , joining the points of division of the op- posite sides in order , we have 64 squares , each For this reason the name of ...
Page 211
... side of the cube , or one of the equal factors , is called the cube root , thus : 3 is the cube root of 27 , because 3 × 3 × 3 = 27 . The cube of 4 = 4 × 4 × 4 = 64 . The cube of 10 = 10 × 10 x10 = 1000 . The cube of 1 × 1 × 1 . ( See ...
... side of the cube , or one of the equal factors , is called the cube root , thus : 3 is the cube root of 27 , because 3 × 3 × 3 = 27 . The cube of 4 = 4 × 4 × 4 = 64 . The cube of 10 = 10 × 10 x10 = 1000 . The cube of 1 × 1 × 1 . ( See ...
Page 216
... cipher is set at the root , and also after the double of the root , and a new period is set down by the side of the other one , and proceed as before . 333. EXERCISES . 1. Extract the square roots of 676 216 COURSE OF ARITHMETIC .
... cipher is set at the root , and also after the double of the root , and a new period is set down by the side of the other one , and proceed as before . 333. EXERCISES . 1. Extract the square roots of 676 216 COURSE OF ARITHMETIC .
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Common terms and phrases
1st method 2nd method acres amount annum avoirdupois bought bushel called cent ciphers circumference common difference common fraction compound quantity contained cost cube root cubic inches decimal places denominator diameter discount divide a fraction dividend division divisor dwts equal example exchange EXERCISES Express factors farthings feet Find the number Find the sum Find the value florins francs gain gallon given greatest common measure guinea Hence hundreds improper fraction integer interest logarithms miles minutes mixed quantity months multiplicand number of terms operation paid pence performed person piastres piece pounds present worth principal quotient receive recurring decimal Reduce remainder result Rix-dollars rubles selling share shillings sold square root sterling subtracted tare tens thousandths Troy weight units vulgar fractions weight whole number Worksop yards of cloth
Popular passages
Page 238 - ... one grain of wheat for the first square, two for the second, four for the third, and so on, doubling...
Page 40 - To reduce a mixed number to an improper fraction, Multiply the whole number by the denominator of the fraction, and to the product add the numerator; under this sum write the denominator.
Page 238 - Sessa requested that he might be allowed one grain of wheat for the first square on the chess board, 2 for the second, 4 for the third, and so on, doubling continually, to 64, the whole number of squares. Now, supposing, a pint to contain 7680 of these grains, and one quarter or 8 bushels to be worth yja 6d, it is required to compute the value of all the corn ? Ans.
Page 128 - XV — 24, as shown in the operation. 2. 5 compositors, in 16 days, of 14 hours each, can compose 20 sheets of 24 pages in each sheet, 50 lines in a page, and 40 letters in a line; in...
Page 286 - The real resistance to a plane, from a fluid acting in a direction perpendicular to its face, is equal to the weight of a column of the fluid, whose base is the plane...
Page 53 - Multiply the numerator of the dividend by the denominator of the divisor...
Page 48 - To Multiply a Fraction by a Whole Number. Multiply the numerator by the whole number and divide the product by the denominator.
Page 43 - Divide the given number by any prime factor ; divide the quotient in the same manner, and so continue the division until the quotient is a prime number. The several divisors and the last quotient will be the prime factors required.