The course of arithmetic as taught in the Pestalozzian school, Worksop. [With] Answers1854 |
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Page vii
... Cipher or Zero . 28 Absolute and relative values of every digit . 29 Table to illustrate their values . 30 Examples in Numeration . 31 Examples in Notation . 32 Roman Notation . 33 , 34 Illustrations . 35 36 Uses of Roman characters ...
... Cipher or Zero . 28 Absolute and relative values of every digit . 29 Table to illustrate their values . 30 Examples in Numeration . 31 Examples in Notation . 32 Roman Notation . 33 , 34 Illustrations . 35 36 Uses of Roman characters ...
Page x
... ciphers on its right . 172 Advantages of Decimals . 173 Every cipher affixed to the left hand of a Decimal , after the point , decreases its value tenfold . 174 , 175 Multiplication and Division of Decimals by 10 , 100 , & c . 176 To ...
... ciphers on its right . 172 Advantages of Decimals . 173 Every cipher affixed to the left hand of a Decimal , after the point , decreases its value tenfold . 174 , 175 Multiplication and Division of Decimals by 10 , 100 , & c . 176 To ...
Page 5
... cipher , or zero , having no value , becomes necessary when any order of units is wanting . It might be placed at the beginning of a number , but would have no meaning , for 034 is the same as 34 . 27. Therefore , by means of these ten ...
... cipher , or zero , having no value , becomes necessary when any order of units is wanting . It might be placed at the beginning of a number , but would have no meaning , for 034 is the same as 34 . 27. Therefore , by means of these ten ...
Page 24
... or 2 thousands + 4 hundreds , & c . Add the partial products , and the sum is the product required . From which it is inferred that we must multiply one 24 COURSE OF ARITHMETIC . to 27 Method of expressing every numerical quantity Cipher.
... or 2 thousands + 4 hundreds , & c . Add the partial products , and the sum is the product required . From which it is inferred that we must multiply one 24 COURSE OF ARITHMETIC . to 27 Method of expressing every numerical quantity Cipher.
Page 25
... ciphers on the right hand multiply them together , omitting the ciphers , and then place on the right hand of the product as many ciphers as there are on the right hand of the factors . - 75. Since 5x7 = 7 × 5 , or 14 × 25 = 25 × 14 ...
... ciphers on the right hand multiply them together , omitting the ciphers , and then place on the right hand of the product as many ciphers as there are on the right hand of the factors . - 75. Since 5x7 = 7 × 5 , or 14 × 25 = 25 × 14 ...
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Common terms and phrases
1st method 2nd method acres amount annuity annum avoirdupois bill bought bushel called ciphers circumference common difference compound interest compound quantity contained cost cube root cubic inches debts decimal places denominator discount divide a fraction dividend division divisor dwts equal example exchange EXERCISES Express factors farthings feet Find the number Find the sum Find the value florins francs gain gallon given greatest common measure guinea Hence hhds improper fraction insured integer interest length miles minutes mixed quantity months multiplicand number of terms operation paid pence performed person piastres piece pounds present worth quotient receive recurring decimal Reduce remainder result Rix-dollars rubles selling share shillings sold square root sterling subtracted tare thousandths Troy weight units vulgar fractions weight whole number Worksop yards long yards of cloth year's principal
Popular passages
Page 240 - ... one grain of wheat for the first square, two for the second, four for the third, and so on, doubling...
Page 42 - To reduce a mixed number to an improper fraction, Multiply the whole number by the denominator of the fraction, and to the product add the numerator; under this sum write the denominator.
Page 240 - Sessa requested that he might be allowed one grain of wheat for the first square on the chess board, 2 for the second, 4 for the third, and so on, doubling continually, to 64, the whole number of squares. Now, supposing, a pint to contain 7680 of these grains, and one quarter or 8 bushels to be worth yja 6d, it is required to compute the value of all the corn ? Ans.
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Page 45 - Divide the given number by any prime factor ; divide the quotient in the same manner, and so continue the division until the quotient is a prime number. The several divisors and the last quotient will be the prime factors required.