| Miles Bland - Geometry - 1821 - 898 pages
...transposition, зл? = 120, and x = 40. /. they received 40, 30, 26, 15, 12, 7 pence respectively. 14. It is required to divide the number 99 into five such...exceed the second by 3 ; be less than the third by ю ; greater than the fourth by 9 ; and less than the fifth by 16. Let x = the first part, .". x —... | |
| Miles Bland - Algebra - 1824 - 404 pages
...transposition, 3т=120, and т = 40. .'. they received 40, 30, 26, 15, 12, 7 pence respectively. 14. It is required to divide the number 99 into five such...less than the fifth by 16. Let x = the first part, .'. x— 3 = second, т +10= third, x— 9= fourth, x + 16 = fifth. or 5т+14 = 99, .'. by transposition,... | |
| James Ryan, Robert Adrain - Algebra - 1824 - 542 pages
...the youngest received. How much had each ? Ans. 21, 30, 42, and 60 shillings respectively. Prob. 4D. It is required to divide the number 99 into five such...than the fourth by 9 ; and less than the fifth by 16. Ans. 17, 14,27, 8, and 33. Prob. 50. Two persons began to play with equal sums of money : the first... | |
| James Ryan - Algebra - 1824 - 550 pages
...21, 30, 42, and 60 shillings respectively. Prob. 49. It is required to divide the number 99 into fire such parts, that the first may exceed the second by...than the fourth by 9; and less than the fifth by 16. Ans. 17, 14, 27, 8, and 33. Prob. 50. Two persons began to play with equal sums of money : the first... | |
| James Ryan - Algebra - 1826 - 430 pages
...the youngest received. How much had each ? Ans. 21, 30, 42, and 60 shillings respectively. Prob. 49. It is required to divide the number 99 into five such...parts, that the first may exceed the second by 3 ; be lest than the third by 10; greater than the fourth by 9 ; and less than the tilth by 16. Ans. 17, 14,... | |
| Jeremiah Day - Algebra - 1827 - 352 pages
...paid as much as A and B; and D paid as much as C and B. What did each pay? Ans. 317,951,1268,2219. Prob. 32. It is required to divide the number 99 into...part. Then x — 3= the seco"nd, x— 9= the fourth, z+ 10= the third, x + 16= the fifth. Therefore x+x — 3+x+10+x-9+x+ 16=99. And x=l7. Prob. 33. A father... | |
| James Ryan, Robert Adrain - Algebra - 1835 - 388 pages
...the youngest received. How much had each 1 Ans. 21, 30, 42, and 60 shillings respectively. PROB. 49. It is required to divide the number 99 into five such...than the fourth by 9 ; and less than the fifth by 16. Ans. 17, 14, 27, 8, and 33. PROB. 50. Two persons began to play with equal sums of money ; the first... | |
| Silas Totten - Algebra - 1836 - 320 pages
...reducing, Юж = 60, and » = 6. Wherefore he gave 6, 12, 18, and 24 pence to them respectively. 4. It is required to divide the number 99 into five such...x = the first part ; then x — 3 = the second, x + 10 = the third, x — 9 — -the fourth, ar+16 = the fifth, The sum of all the parts being 99, we... | |
| Silas Totten - Algebra - 1836 - 360 pages
...five shillings, or sixty pence ; therefore, x + 2x + 3x + ix = 60; reducing, 10* = 60, and sc = 6. 4. It is required to divide the number 99 into five such...greater than the fourth by 9, and less than the fifth by 1 6. Let x = the first part ; then x - — 3 = the second, x + 10 = the third, x — 9 = the fourth,... | |
| Silas Totten - Algebra - 1836 - 332 pages
...gave 6, 12, 18, and 24 pence to them respectively. 4. It is required to divide the number 99 into fwe such parts, that the first may exceed the second by...greater than the fourth by 9, and less than the fifth by 1 6. Let x = the first part ; then x — 3 = the second, x + 10 = the third, x — 9 = the fourth,... | |
| |