The American Preceptor's Assistant: Containing a System of Practical Arithmetic

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T. L. Plowman, 1801 - Arithmetic - 222 pages

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Page 159 - Involve the root to the next inferior power to that which is given, and multiply, it by the number denoting the given power, for a divisor.
Page 109 - As the whole sum of the products is to the whole gain or loss, so is each man's particular product to his particular share of the loss or gain.* EXAMPLES.
Page 165 - In any continued geometrical progression, the product of the two extremes is equal to the product of any two means that are equally distant from them, or equal to the square of the middle term when there is an uneven number of terms.
Page 93 - ... 2. What principal at interest for 10 years, at 6 per cent, per annum, will amount to 1300L.?
Page 222 - When first the marriage knot was ty'd Between my wife and me ; My age was to that of my bride, As three times three to three ; But now when ten and half ten years, We man and wife have been, Her age to mine exactly bears As eight is to sixteen ; Now tell, I pray, from what I've said, What were our ages when we wed...
Page 113 - Thirty days after sight of this my first of exchange, second and third of like tenor and date not paid, pay to Samuel Sims, or order, four hundred and fifty-two pounds, ten shillings and sixpence sterling, value received, which place to account of Peter Simpson.
Page 103 - What difference is there between the interest of 5Q(H. at 5 per cent. for 12 years, and the discount of the same sum, at the same rate, and for the same time ? Jlns.
Page 62 - If a staff 4 feet long cast a shade (on level ground) 7 feet long, what is the height of a steeple whose shade at the same time is 198 feet ? Ans.
Page 151 - If the errors be alike, ie both too much, or both too little, take their difference for a divisor, and the difference of the products for a dividend: but if the errors be unlike, take their sum for a divisor, and the sum of the products for a dividend.
Page 67 - If 10 bushels of oats be sufficient for 18 horses 20 days, how many bushels will serve 60 horses 36 days ? Ans.

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