 | Mathematics - 1801 - 446 pages
...mentioned. 3. Multiply the second and third numbers together, and divide.* the product by the first, and the quotient will be the answer to the question, in the same denomination you left the second number in ; which may be brought into any other denomination required. EXAMPLE. If 24lb. of raisins... | |
 | Charles Vyse - Arithmetic - 1806 - 342 pages
...mentioned. 3. Multiply the second and third Terms together, and divide that Product by the first. ' The Quotient will be the Answer to the Question, in the same Denomination or Name you left your second Term in. 4. If there happens to be a Remainder after the Division, reduce... | |
 | Samuel Webber - Arithmetic - 1812 - 260 pages
...mentioned. 3. Multiply the second and third numbers together, and divide the product by the first, and the quotient will be the answer to the question, in the same denomination you left the second number in ; which may be brought into any other denoroina- . don required. Write the less of the two... | |
 | Nathan Daboll - Arithmetic - 1813 - 244 pages
...third terms to the same denomination, and reduce the second term to the lowest name mentioned in it. 3. Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term... | |
 | Roswell Chamberlain Smith - 1814 - 300 pages
...Reduction. Q. How do yoj proceed in the operation f -Л. Multiply the second and third terms to* gether, and divide their product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term. Q. How may this process of multiplying... | |
 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...terms to the same denomination, aiid reduce the second term to the lowest name ir.antioned in it. 3. Multiply the second and third terms together, and...you left the second term in, which may be brought inta any other denomination required. . Thn method of proof is by inverting the question. VOTE. —... | |
 | Charles Vyse - Arithmetic - 1815 - 340 pages
...name mentioned. 3. Multiply the second ^nd third terms together, and divide that product by the «rst. The quotient will be the answer to the question, in the same denomination you left your second term in. 4. If there happen to be a remainder after the division, reduce it into the next... | |
 | Nathan Daboll - Arithmetic - 1817 - 252 pages
...lowest name mentioned i" it. 3. Multiply the second and third tern?s together, and divide their project by the first term ; the quotient will be the answer...left the second term in, which may be brought into nny other denomination required. The method of proof is by inverting the question. NOTE. — The followiug... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...terms to the same denomination, and reduce the second term to the lowest naiae mentioned in it. 3. Multiply the second and third terms together, and...the quotient will be the answer to the question, in fue same denomination you left the second term in, which may be brought into any other denomination... | |
 | John Davidson, Robert Scott (writing master) - Arithmetic - 1818 - 190 pages
...write the greater as thefirst, and the other as the second proportional. The numbers being thus stated, multiply the second and third terms together, and divide their product by thefirst, the quotient will be the answer, in ihe same name in which the third term is9 when you arc... | |
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... 3. Multiply the second and third terms together, and divide their product by the first term , the quotient will be the answer to the question, in the same denomination you left the, second term in, which may be brought into anv other denomination... 
