 | Mathematics - 1801 - 446 pages
...ratio. PROBLEM I. Given the first termt the last term, and the ratio, to find tht sum of the series. RULE.* Multiply the last term by the ratio, and from...term, and the remainder, divided by the ratio less I, will give the sum of the series. EXAMPLES. * DEMONSTRATION. Take any series whatever, as i, 3, 9,... | |
 | Samuel Webber - Arithmetic - 1812 - 260 pages
...ratio. PROBLEM 1. Given thefirst term, the last term, and the ratio, to find the sum of the series. RULE.* Multiply the last term by the ratio, and from...term, and the remainder, divided by the ratio less 1, will give the sum of the series. * DEMONSTRATION. Take any series whatever, as 1, 3, 9, 27, 81,... | |
 | Nathan Daboll - Arithmetic - 1813 - 244 pages
...The first term, the last term (or the extremes) and the ratio given, to find the sum of the series RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by 1, and the quotient will be the sum of all the terms.... | |
 | Arithmetic - 1818 - 264 pages
...Given the first term, the last term, (or extremes') and the ra* t|O, to find the sum of the series, RULE. Multiply the last term by the ratio, and from the product subtract the first term, and the rem ainder, divided by the ratio less I, wjif'give the sum of all the terms of the series. EXAMPLES.... | |
 | Phinehas Merrill - Arithmetic - 1819 - 116 pages
...•Given the first term, the last term, and the ratio, to find the aggregate or total sum of the series. RULE. — Multiply the last term by the ratio, and...divided by the ratio less one, will give the sum of the whole series. EXAMPLES. 1. The first term of a series in geometrical progression is 1 , the last term... | |
 | Zadock Thompson - Arithmetic - 1826 - 176 pages
...ratio. Problem I. The Jlnt term, the latt term, and the ratio given to find the turn of the series. RULE.* — Multiply the last term by the ratio, and...term, and the remainder divided by the ratio, less 1, will give the sum of the series. Examples. 1 . The first term of a series in geometrical progression... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...stand over the first term, the number oí the exponents must equal the number of terms. PROBLEM I. # RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio less one, and the quotient will be the sum of all the terms.... | |
 | William Kinne - 1829 - 246 pages
...ratio. PROBLEM 1. Given the first term, the last term, and the ratio, to find the sum of the series. RULE. — Multiply the last term by the ratio, and...term, and the remainder divided by the ratio less 1, will give the sum of the series. EXAMPLES. 1 . The extremes of a geometrical progression are 1 and... | |
 | Nathan Daboll - Arithmetic - 1829 - 252 pages
...The first term, the last term (or the extremes) and the ratio given, to find the sum of the series. RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by 1, and the quotient will be the sum of all the terms.... | |
 | James L. Connolly (mathematician.) - Arithmetic - 1829 - 266 pages
...first term, the last term, or the extremes, and the ratio, given to find the sum of the series. RULK 1. Multiply the last term by the ratio, and from the product subtract the first term; then divide the remainder by the ratio less one, and the quotient will be the sum of all the terms.... | |
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The first term, the last term (or the extremes) and the ratio given, to find the sum of the series. RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by 1, and the quotient... 
