A System of Practical Arithmetic: Applicable to the Present State of Trade, and Money Transactions: Illustrated by Numerous Examples Under Each Rule; for the Use of Schools |
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Page 12
... remainder . ( 2 ) . If the figure in the lower line be the greater , add ten to the upper one , and then take the lower one from the sum , set down the remainder and carry one to the next lower figure , with which proceed as before ...
... remainder . ( 2 ) . If the figure in the lower line be the greater , add ten to the upper one , and then take the lower one from the sum , set down the remainder and carry one to the next lower figure , with which proceed as before ...
Page 13
... Remainder 313262 765087 762134 425436 597082 339651 165052 PROOF . Add the remainder to the last line , and if the sum be equal to the first , the work is right . From .. 658742 390076 431267 Take 346121 184193 280795 Remainder 312621 ...
... Remainder 313262 765087 762134 425436 597082 339651 165052 PROOF . Add the remainder to the last line , and if the sum be equal to the first , the work is right . From .. 658742 390076 431267 Take 346121 184193 280795 Remainder 312621 ...
Page 20
... remainder down on one side of the cross ; do the same with the multiplier , and put down the remainder on the other side of the cross . Multiply the two remainders toge- ther , and casting out the nines of their product , will leave the ...
... remainder down on one side of the cross ; do the same with the multiplier , and put down the remainder on the other side of the cross . Multiply the two remainders toge- ther , and casting out the nines of their product , will leave the ...
Page 21
... remainder is 1 , which answering to the 1 at the top of the cross , leads me to conclude that the operation is right . IV . When cyphers are intermixed with the figures in the multiplier . RULE . Omit the cyphers , and let the first ...
... remainder is 1 , which answering to the 1 at the top of the cross , leads me to conclude that the operation is right . IV . When cyphers are intermixed with the figures in the multiplier . RULE . Omit the cyphers , and let the first ...
Page 23
... remainder will be the lesser number : the answer will be found by multiplying the greater and lesser numbers together . § To find the number of cubic feet in any room , & c . , the continual product of the height , length , and width ...
... remainder will be the lesser number : the answer will be found by multiplying the greater and lesser numbers together . § To find the number of cubic feet in any room , & c . , the continual product of the height , length , and width ...
Other editions - View all
A System of Practical Arithmetic, Applicable to the Present State of Trade ... Jeremiah Joyce No preview available - 2018 |
A System of Practical Arithmetic, Applicable to the Present State of Trade ... Jeremiah Joyce No preview available - 2015 |
Common terms and phrases
9 Ex acres aliquot amount annual annuity annum answer arithmetical progression Avoirdupois bill bushels common denominator compound interest containing cost course of exchange cube root cubic cyphers decimal difference ditto divide dividend divisor equal EXAMPLES farthings feet figures find the value fraction gallons geometrical progression geometrical series given number given sum gives guineas per cent hogsheads hundred improper fractions inches insure joint lives last term lease logarithm London measure miles millions mixed numbers months multiplicand Multiply the number neat weight NOTE number of terms ounces paid payment pence person aged piastre pound sterling pounds present value purchase quantity quotient Reduce remainder Rule of Three shews shillings square root sterling subtract supposing tare thousand tons tret Troy TROY WEIGHT whole number wine worth yards
Popular passages
Page 177 - Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the equated time, nearly.
Page 112 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Page 243 - Multiply each term into the multiplicand, beginning at the lowest, by the highest denomination in the multiplier, and write the result of each under its respective term ; observing to carry an unit for every 12, from each lower denomination to its next superior.
Page 92 - III. finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term.
Page 150 - The first term, the last term (or the extremes) and the ratio given, to find the sum of the series. RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by 1, and the quotient will be the sum of all the terms.
Page 113 - Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Page 243 - In like manner, multiply all the multiplicand by the inches and parts of the multiplier, and set the result of each term one place removed to the right hand of those in the multiplicand...
Page 55 - Place the numbers so that those of the same denomination may stand directly under each other.
Page 149 - Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.
Page 28 - ... the number in the quotient. Multiply the divisor by the quotient figure, and set the product under that part of the dividend used. Subtract the product, last found, from that part of the dividend under which...