| John Bonnycastle - Algebra - 1811 - 230 pages
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 12. It is required to divide the number 24 into two such...parts, that their product may be equal to 35 times theix difference. Ans. 10 and 14. 13. The sum of two numbers i* 8; -uul the sum' of their cubes is... | |
| Charles Hutton - Mathematics - 1811 - 406 pages
...of which the first is to the third as 5 to 9, and the sum of all three is 63. Ans. 1 <, 21, 27. 22. It is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
| Charles Hutton - Mathematics - 1812 - 620 pages
...progression, of which the first is to the third as 5 to 9,and the sum of all three is 63? Ans. 15, 21,27. 22. It is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
| John Bonnycastle - Algebra - 1813 - 456 pages
...from 10, and then multiply the remainder by the numbpr itself, the product shall be 21. Ans. 7 or 3 3. It is required to divide the number 24 into two such...product may be equal to 35 times their difference. Ans. 10 and 14 4. It is required to divide a line, of 20 inches in length, into two such parts, that... | |
| John Bonnycastle - Algebra - 1818 - 326 pages
...10, aijd then multiply the remainder by the number itself, the product shall be 21. Ans. 7 or 3. 3. It is required to divide the number 24 into two such parts, that their product shall be equal to 35 times their difference. Ans. 10 and 14 4. It is required to divide a line, of... | |
| Charles Hutton - Arithmetic - 1818 - 646 pages
...which the first is to the third as 5 to 9, and the sum of all three is 63 ? Ans. 15, 21, 27. 22. lt is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
| Bewick Bridge - Algebra - 1818 - 254 pages
...18 x (x-yY = 7'2, or (xy)*=4 ; .:xy = 2. Again, x1— and 4xy =96. _12_ .. r~~ > but xy =2; Ex. 6. To divide the number 24 into two such parts, that their product shall, be to thes๎ora of their squares : : 3': 10. ANSWER, 18 and 6. Ex. 7. There are two numbers... | |
| Bewick Bridge - Algebra - 1821 - 284 pages
...THEOR. 1, 18 x(x— j/)'=72, Again, x*—2xу+у'=4, and 4xy =96. or ж+^=ю,| but x— y=2 ; Ex. 6. To divide the number 24 into two such parts, that their product shall be to the sum of their squares : : 3 : 10. : ANSWER, 18 and 6. Ex. 7. There are two numbers which... | |
| John Bonnycastle - Algebra - 1825 - 336 pages
...from 10, and then multiply the remainder by the number itself, the product shall be 21. Ans. 7 or 3 3. It is required to divide the number 24 into two such parts, that their product shall be equal to 35 times their difference. Ans. 10 and 14 4. It is required to divide a line, of... | |
| Peter Nicholson - Mathematics - 1825 - 1046 pages
...2.п/+у*= 100, or extracting the root дг+y = but x* + 2.n/+y= lOO, }ia . . , = = 2 -*, — 8 — У 2 6. It is required to divide the number 24 into two such parts, that their product shall be to the sum of their squares :: 3 : 1O. Ans. 18 and 6. 7. There are two numbers which are to... | |
| |