Elements of Algebra: To which is Prefixed, a Choice Collection of Arithmetical Questions, with Their Solutions, Including Some New Improvements Worthy the Attention of Arithmeticians. The Principles of Algebra are Clearly Demonstrated, and Applied in the Resolution of a Great Variety of Problems on Different Parts of the Mathematicks and Natural Philosophy |
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Page 7
... solved by the moft fimple Equations poffible : fome are new , and thefe it is hoped , will be found , both from their nature , and the manner of folution , adapted to improve and amuse the learner . Every work will meet with fuccess in ...
... solved by the moft fimple Equations poffible : fome are new , and thefe it is hoped , will be found , both from their nature , and the manner of folution , adapted to improve and amuse the learner . Every work will meet with fuccess in ...
Page 33
... of multiplying each Suppofition by the Error of the other fuppofed Num ber , there is another Method used fometimes by Alge- D braifts , braists , in solving Equations , containing Surds , and ELEMENTS OF ALGEBRA . 33.
... of multiplying each Suppofition by the Error of the other fuppofed Num ber , there is another Method used fometimes by Alge- D braifts , braists , in solving Equations , containing Surds , and ELEMENTS OF ALGEBRA . 33.
Page 34
... solving Equations , containing Surds , and ex- ponential Quantities , which Method I fhall make Use of here . And the Rule is this : Having taken two convenient Numbers for your Suppofitions , work with both accord- ing to the Nature of ...
... solving Equations , containing Surds , and ex- ponential Quantities , which Method I fhall make Use of here . And the Rule is this : Having taken two convenient Numbers for your Suppofitions , work with both accord- ing to the Nature of ...
Page 132
... solved , gives 15 ; the other three Parts are 25 , 4 and 100 . x Or more generally thus , put a 5 , and 144 , then will x + x + 2a + · + 1 + ax + a2 = s , hence multiplying by a , we get a2x + 2ax + x + a3 + 2a2 + aas , therefore a a2x ...
... solved , gives 15 ; the other three Parts are 25 , 4 and 100 . x Or more generally thus , put a 5 , and 144 , then will x + x + 2a + · + 1 + ax + a2 = s , hence multiplying by a , we get a2x + 2ax + x + a3 + 2a2 + aas , therefore a a2x ...
Page 189
... solved , gives x = 7 ± ✓ = 8 , or 6 ; fo that the three Roots of the original Equation are 5 , 6 , and 8 . Let there be propofed the Biquadratic x - 4x3 - 8x + 32 = 0 , and in order to change it to another whose last Term admits of ...
... solved , gives x = 7 ± ✓ = 8 , or 6 ; fo that the three Roots of the original Equation are 5 , 6 , and 8 . Let there be propofed the Biquadratic x - 4x3 - 8x + 32 = 0 , and in order to change it to another whose last Term admits of ...
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Elements of Algebra: To Which Is Prefixed, a Choice Collection of ... John Mole No preview available - 2016 |
Common terms and phrases
Acres added affumed alfo Algebraic Quantities Anſwer arifing becauſe Biquadratic Cafe Cent Co-efficient completing the Square confequently Cube Root Cubic Cubic Equation Denominator denotes Difference Diſtance divided Dividend Divifion Divifor Equa equal EXAMPLE Exponent expreffed fame Manner fecond Equation fecond Term Feet fhall fhews fifth Power fignifies fimple fince firft Equation firft Term firſt folved fome fourth fquare Fraction fubtracted fuch fuppofe given Equation gives hence Inches Increaſe Intereft itſelf laft Term laſt Latitude leaft lefs likewife Logarithm meaſure merator Miles muft multiplied muſt negative nth Root Number fought obferve pofitive Pound Product Progreffion propofed Queſtion Quotient refpectively Remainder repreſented ſhall Sides Square Root Surd thefe theſe third Term thofe thoſe tion Triangle unknown Quantity uſed Value vulgar Fraction Weight whence whofe whole Numbers writing Yards
Popular passages
Page 13 - If the sun moves every day one degree, and the moon thirteen degrees, and at a certain time the sun be at the beginning of Cancer, and in...
Page 21 - The workmen thought that substituting part silver was only a proper perquisite ; which taking air, Archimedes was appointed to examine it ; who on putting it into a vessel of water, found it raised the fluid 8-2245 cubic inches : and having discovered that the inch of gold more critically weighed 10-36 ounces, and that of silver but 5-85 ounces, he found by calculation what part of the king's gold had been changed. And you are desired to repeat the process. Ans.
Page 81 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Page 23 - ... in 9 weeks, how many oxen will eat 24 acres in 18 weeks, the grass being at first equal on every acre, and growing uniformly ? This example is taken from Newton's Universal Arithmetic.
Page 113 - RULE. 1. Observe which of all your unknown Quantities is the least involved, and let the Value of that Quantity be found in each Equation by the Rules already given), looking upon all the Rest as known : let the Values thus found be put equal to each other (for they are equal...
Page 21 - Vespasian weighed,, suppose 10OOOOlb. and was moved, let us admit, with such a Velocity, by Strength of Hands, as to pass through 20 Feet in one Second of Time ; and this was found suffic:ent to demolish the Walls of Jerusalem.
Page 179 - The coefficient of the third term is the fum of all the products that can be made by multiplying any two of the roots together. The coefficient of the fourth term is the fum of all the products which can be made by multiplying together any three of the roots with their figns changed ; and fo of others.
Page 78 - Jhall give the numerator of the quotient. Then multiply the denominator of the dividend by the numerator of the divifor, and their produft Jhall give the denominator.
Page 181 - and there are three changes ^ from the firft to the fécond, from the third to the fourth, and from the fourth to the fifth term : therefore there are three affirmative roots.
Page 114 - ... for that quantity and its respective powers in the other equation; and with the new equations thus arising repeat the operation, till you have only one unknown quantity and one equation. Thus x being the...