EXAMPLES. 1. How much shalloon that is yard wide, will line 5¦ yards of cloth which is 13 yard wide? Yds. yds. yds, Yds. Ans. As 13:5 And 7××==16 2. If a man perform a journey in 3 days, when the day is 12 hours long; in how many days the day is but 9 hours? 3. If 13 men in 114 days, mow 21 days will 8 men do the same? 4. How much in length that is 7 make a square foot? will he do it when Ans. 4 days. acres, in how many Ans. 18 days. inches broad, will Ans. 20 inches. 5. If 254s. will pay for the carriage of a cwt. 145 miles; how far may 61 cwt. be carried for the same money? Ans. 22 6. How many yards of baize which is 1 will line 183 yards of camblet yard wide? mile. yards wie, Ans. 11 yds. 1 qr. 1} na. RULE OF THREE DIRECT IN DECIMALS. RULE. Reduce your fractions to decimals, and state your ques tion as in whole numbers; multiply the second and third to gether; divide by the first, and the quotient will be the an swer, &c. EXAMPLES. 1. If of a yard cost of a pound; what will 153 yards come to ? 1=,875,7=,583+ and 2,75 Yds. £. £. s. d. qrs. Yds. £. As ,875,583 :: 15,75: 10,494-10 9 10 2,24 Ans 2. If 1 pint of wine cost 1,2s. what cost 12,5 hhds? Ans. £378 3. If 41 yards cost 3s. 44d. what will 30 yards cost? Ans. £1 4s. 3d. 3 qrs. + 4. If 1,4 cwt. of sugar cost 10 dols. 9 cts., what will 9 ewt. 3 qrs. cost at the same rate? cwt. As 1,4 19 10,09 : : 9,75: 70,269=$70, 26 cts. 9 m.+ 5. If 19 yards cost 25,75 dollars, what will 435 yards come to ? Ans. $590, 21 cts. 72 m. 6. If 345 yards of tape cost 5 dols. 17 cents, 5 m., what will one yard cost? Ans. ,015-14 cts. 7. If a man lay out 121 dollars 23 cts. in merchandise, and thereby gains 39,51 dollars, how much will he gain in laying out 12 dollars at the same rate? Ans. $3,91=$3, 91 cts. 8. How many yards of riband can I buy for 251⁄2 dols. if 93 yards cost 41 dollars? Ans. 178 yards. 9. If 178 yds. cost 25 dollars, what cost 293 yards? Ans. $41 10. If 1,6 cwt. of sugar cost 12 dols. 12 cts., what cost 3 hhds., each 11 cwt. 3 qrs. 10,12 lb. ? Ans. 269,072 dols.=$269, 7 cts. 2 m.+ SIMPLE INTEREST BY DECIMALS. A TABLE OF RATIOS. Ratio is the simple interest of 17. for one year; or in federal money, of $1 for one year, at the rate per cent. agreed on. RULE. Multiply the principal, ratio and time continually toge ther, and the last product will be the interest required. EXAMPLES. 1. Required the interest of 211 dols. 45 cts. for 5 years at 5 per cent. per annum? $cts. 211,45 principal. 10,5725 interest for one year. 52,8625 Ans.=$52, 86 cts. 21⁄2 m. 2. What is the interest of 6457. 10s. for 3 years, at 5 per cent. per annum? £645,5×06×3=116,190=£116 3s. 9d. 2,4 qrs. Ans. 3. What is the interest of 1217. 8s. 6d. for 4 years, at 6 per cent. per annum? Ans. £32 15s. 8d. 1,36 qrs. 4. What is the amount of 536 dollars, 39 cents, for 11 years, at 6 per cent. per annum? Ans. $584,6651. 5. Required the amount of 648 dollars 50 cents for 123 years, at 5 per cent. per annum? CASE II. Ans. $1103, 26 cts. The amount, time and ratio given, to find the principal. RULE.-Multiply the ratio by the time, add unity to the product for a divisor, by which sum divide the amount, and the quotient will be the principal. EXAMPLES. 1. What principal will amount to 1235,975 dollars, in 5 years, at 6 per cent. per annum? $ $ ,66×5+1=1,30, 1235,975(950,75 Ans. 2. What principal will amount to 8731. 19s. in 9 years, at 6 per cent. per annum? Ans. £567 10s. 3. What principal will amount to $626, 6 cents in 12 years, at 7 per cent.? Ans. $340,25=$340, 25 cts. amount to 9567. 10s. 4,125d. In Ans. £645 15s. 4. What principal will 83 years, at 5 per cent.? CASE III. The amount, principal and time given, to find the ratio. RULE.-Subtract the principal from the amount, divide the re mainder by the product of the time and principal, and the quotient will be the ratio. EXAMPLES. 1. At what rate per cent. will 950,75 dollars amount to 1230,975 dollars in 5 years? 950,75×5=4753,75)285,2250(,06-6 per cent. 285,2250 Ans. 2. At what rate per cent. will 5677. 10s. amount to 8731. 19s. in 9 years ? Ans. 6 per cent. 3. At what rate per cent. will 340 dols. 25 cts amount to 626 dols. 6 cts. in 12 years? 4. At what rate per cent. will 6457. 15s. amount to 956/. 10s. 4,125d. in 83 years? CASE IV. Ans. 7 per cent. Ans. 51 per cent. The amount, principa, and rate per cent. given, to find the time. RULE.-Subtract the principal from the amount; divide the remainder by the product of the ratio and principal; and the quotient will be the time. EXAMPLES. 1. In what time will 950 dols. 75 cts. amount to 1235 lollars, 97,5 cents, at 6 per cent. per annum? From the amount $1235,975 Take the principal 950,75 950,7506=57,0450)285,2250(5 years, Ans. 285,2250 2. In what time will 5671. 10s. amount to 8731. 19s. at per cent. per annum? Ans. 9 years. amount to 626 Ans. 12 years. amount to 9567. 10s. Ans. 8,75–83 years. 3. In what time will 340 dols. 25 cts. dols. 6 cts. at 7 per cent per annum? 4. In what time will 6457. 15s. 4,125d. at 51 per ct. per annum? TO CALCULATE INTEREST FOR DAYS. RULE.-Multiply the principal by the given number of days, and that product by the ratio; divide the last product by 365 (the number of days in a year) and it will give the interest required. EXAMPLES. 1. What is the interest of 3607. 10s. for 146 days, at 6 pr. ct.? 2. What is the interest of 640 dols. 60 cts. for 100 day & at 6 per cent. per annum? Ans. $10, 53 cts.+ Ans. £4,1235=4l. 2s. 51⁄2d.+ 3. Required the interest of 2507. 17s. for 120 days, at á 4. Required the interest of 481 dollars 75 cents, for 21 days, at 7 per cent. per annum? Ans. $2,30 cts. 9m.+ per cent per annum? A TABLE, showing the number of Days from any day of month, to the same day of any other month. FROM ANY DAY OF one Jan. Feb. Mar. Ap'l. May June July Aug. Sept Oct. Nov. Dec. 89 61 30 365 334 304 273 242 212| 181| 151; 92 61 30 365 334 304 Oct. 273 242 214 183 153 122 Nov. 304 273 246 214 184 153 123 92 61 31 365 335 Dec. 334 303 275 244 214 183 153 122 91 61 30 365 |