A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page 3
... sides of a quadrilateral in a circle , towards the same parts , and are respectively proportional to these sides : to prove that the resultant will pass through the intersection of the diagonals . Let ABCD , fig . ( 6 ) , be RESULTANT ...
... sides of a quadrilateral in a circle , towards the same parts , and are respectively proportional to these sides : to prove that the resultant will pass through the intersection of the diagonals . Let ABCD , fig . ( 6 ) , be RESULTANT ...
Page 4
... sides , constructed as in Euclid I. 47 ; prove that the resultant of forces represented by CD , BF , is parallel to a diagonal of the rectangle the sides of which are AE , AG . ( 9 ) Having given a line representing in length the ...
... sides , constructed as in Euclid I. 47 ; prove that the resultant of forces represented by CD , BF , is parallel to a diagonal of the rectangle the sides of which are AE , AG . ( 9 ) Having given a line representing in length the ...
Page 5
... sides ; prove that their resultant passes through the intersection of the two other sides . SECT . 2. Trigonometrical Method . Let two forces P , Q , act upon a point , and let a be the angle between their directions : then , if R be ...
... sides ; prove that their resultant passes through the intersection of the two other sides . SECT . 2. Trigonometrical Method . Let two forces P , Q , act upon a point , and let a be the angle between their directions : then , if R be ...
Page 6
... sides of the polygon ; 0 , fig . ( 9 ) , its centre ; AB , BC , any two consecutive sides : join AO , BO , CO . Let P be the tension of the string 6 RESULTANT OF TWO FORCES ACTING ON A POINT .
... sides of the polygon ; 0 , fig . ( 9 ) , its centre ; AB , BC , any two consecutive sides : join AO , BO , CO . Let P be the tension of the string 6 RESULTANT OF TWO FORCES ACTING ON A POINT .
Page 11
... side of the triangle is hung over them , and its two ends attach- ed to a weight W : to find the pressure on each peg . The pressure on A is equal to W , and the pressure on either B or C is equal to W √3 ( 30 ) A , B , C , fig . ( 10 ) ...
... side of the triangle is hung over them , and its two ends attach- ed to a weight W : to find the pressure on each peg . The pressure on A is equal to W , and the pressure on either B or C is equal to W √3 ( 30 ) A , B , C , fig . ( 10 ) ...
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attached axle beam bisect the angle centre of gravity chord coefficient of friction collision component cos² cylinder denote determine distance equal forces equation feet find the inclination find the position find the pressure fixed point forces act fulcrum geometrical given circle given point hangs hence highest point horizontal plane impact impinges inclined plane intersection join latus rectum length lever line of quickest magnitude and direction middle point motion moveable parabola parallel parallelogram particle perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles SECT shew sides sin² sliding sphere straight line string passing supposing suspended tan¹ three forces uniform rod University of Cambridge velocity of projection vertical plane wheel
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Page 145 - OUT of childhood into manhood Now had grown my Hiawatha, Skilled in all the craft of hunters, Learned in all the lore of old men, In all youthful sports and pastimes, In all manly arts and labors. Swift of foot was Hiawatha ; He could shoot an arrow from him, And run forward with such fleetness, That the arrow fell behind him...