Daboll's Complete Schoolmaster's Assistant Being a Plain Comprehensive System of Practical Arithmetic |
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Page 3
... received a greater share of public patronage than Daboll's Schoolmaster's Assistant : But it must be obvious to teachers of Arithmetic , and also to men of business , that Arith- metics written some thirty or forty years ago , however ...
... received a greater share of public patronage than Daboll's Schoolmaster's Assistant : But it must be obvious to teachers of Arithmetic , and also to men of business , that Arith- metics written some thirty or forty years ago , however ...
Page 4
... received that attention which their importance demands ; being simplified and illustrated in such a manner as to render the study of them pleasing and interesting to the pupil . In Simple Interest several short rules are given . Also ...
... received that attention which their importance demands ; being simplified and illustrated in such a manner as to render the study of them pleasing and interesting to the pupil . In Simple Interest several short rules are given . Also ...
Page 26
... received 411 dollars , 88 cents and B received just three times as much money as A received ; how much mo- ney did B receive ? Ans . 1235,64 . 12. B paid me $ 98,56 , C paid me just four times as much as B , and D paid me just as much ...
... received 411 dollars , 88 cents and B received just three times as much money as A received ; how much mo- ney did B receive ? Ans . 1235,64 . 12. B paid me $ 98,56 , C paid me just four times as much as B , and D paid me just as much ...
Page 32
... received $ 135,41 and Henry received just three times as much lacking 94 cents ; how much money did Henry receive ? Ans . $ 405,29 . 23. A man received $ 1500 , and out of which he paid to A $ 511,45 , to B $ 251,15 , to C $ 180,39 ...
... received $ 135,41 and Henry received just three times as much lacking 94 cents ; how much money did Henry receive ? Ans . $ 405,29 . 23. A man received $ 1500 , and out of which he paid to A $ 511,45 , to B $ 251,15 , to C $ 180,39 ...
Page 42
... received 2943 cents for melons that he sold at 9 cents apiece ; how many did he sell ? Ans . 327 . 16. How many times is 7 contained in 6680 , and how many over ? Ans . 954 times , and 2 over . 17. A merchant has $ 5122 to purchase ...
... received 2943 cents for melons that he sold at 9 cents apiece ; how many did he sell ? Ans . 327 . 16. How many times is 7 contained in 6680 , and how many over ? Ans . 954 times , and 2 over . 17. A merchant has $ 5122 to purchase ...
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Common terms and phrases
2qrs 3qrs acres 3 roods annex annuity answer Arithmetic barrels breadth broadcloth bushels called cent per annum ciphers circumference common denominator common difference common multiple compound interest contained cords cost cube root diameter divi dividend divisor dollars dols equal EXAMPLES farthings Federal money find the amount Find the value frustrum gain gallons given number given sum greatest common divisor hogshead hundred improper fraction last term least common multiple leave length lowest terms merchant bought miles mills mixed number months multiplicand Multiply Note number of terms payment pence pint pound present worth principal PROB proportion quantity quarts quotient figure rate per cent ratio Reduce remainder right hand Rule of Three separatrix shillings sold solid contents square rods square root subtract subtrahend sugar tare tens thousand units VULGAR FRACTIONS weight whole number wine yards of cloth
Popular passages
Page 195 - Find the first figure of the root by trial, and subtract its power from the left hand period of the given number. 3. To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Page 167 - Multiply all the numerators together for a new numerator, and all the denominators for a new denominator; and they will form the fraction required.
Page 183 - ... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Page 106 - Let the farthings in the given pence and farthings possess the second and third places ; observing to increase the second place or place of hundredths, by 6 if the shillings be odd ; and the third place by 1 "when the farthings exceed 12, and by 2 when they exceed 36. EXAMPLES. 1. Find the decimal of 7s. 9fd. by inspection. ,3 =4 6s. 5 for the odd shillings. 39=the farthings in 9|d. 2 for the excess of 36. £. ,391=dechnal required'.
Page 90 - To reduce an improper fraction to a whole or mixed number. RULE. Divide the numerator by the denominator, and the quotient will be the whole or mixed number sought.
Page 233 - To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content.
Page 44 - If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before.
Page 126 - ... multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term.
Page 119 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Page 205 - ... the terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms.