Arithmetic: In which the Principles of Operating by Numbers are Analytically Explained and Synthetically Applied : Illustrated by Copious Examples |
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Page 13
... Hence , units o any higher order may be rendered in units of any lower order . TABLE . 6th order . Hundreds of Thousands . 5th order . Tens of Thousands . 4th order . Thousands . Hundreds . 1 3d order . Tens . 1st order . Units . 2d ...
... Hence , units o any higher order may be rendered in units of any lower order . TABLE . 6th order . Hundreds of Thousands . 5th order . Tens of Thousands . 4th order . Thousands . Hundreds . 1 3d order . Tens . 1st order . Units . 2d ...
Page 20
... Hence , OPERATION . 876 3 653 5 426 3 In the upper number , 8 ( hundreds ) is 8 more than a certain number of nines , ( 5 ) 7 ( tens ) is 7 more . Adding the 8 and 7 , and the 6 units together , the sum is 212 nines and 3 remainder ...
... Hence , OPERATION . 876 3 653 5 426 3 In the upper number , 8 ( hundreds ) is 8 more than a certain number of nines , ( 5 ) 7 ( tens ) is 7 more . Adding the 8 and 7 , and the 6 units together , the sum is 212 nines and 3 remainder ...
Page 22
... hence ? 11. What is the amount of 46723 , 6742 , and 986 dollars ? 12. A man has three orchards ; in the first there are 140 trees that bear apples , and 64 trees that bear cherries ; in the second , 234 trees bear apples , and 73 bear ...
... hence ? 11. What is the amount of 46723 , 6742 , and 986 dollars ? 12. A man has three orchards ; in the first there are 140 trees that bear apples , and 64 trees that bear cherries ; in the second , 234 trees bear apples , and 73 bear ...
Page 34
... , it follows that the multiplier ( number of rows ) in reality simply express- es the number of times the multiplicand ( stars in a row ) is to be taken . Hence , to multiply by 1 , 34 T21 . MULTIPLICATION OF SIMPLE NUMBERS .
... , it follows that the multiplier ( number of rows ) in reality simply express- es the number of times the multiplicand ( stars in a row ) is to be taken . Hence , to multiply by 1 , 34 T21 . MULTIPLICATION OF SIMPLE NUMBERS .
Page 35
... Hence , to multiply by 1 , ( 1 row of stars , ) is to take the multiplicand ( stars in a row ) 1 time ; to multiply ... hence , 3 dollars being of the same name as the thing or answer sought , is the true multiplicand . That num- ber ...
... Hence , to multiply by 1 , ( 1 row of stars , ) is to take the multiplicand ( stars in a row ) 1 time ; to multiply ... hence , 3 dollars being of the same name as the thing or answer sought , is the true multiplicand . That num- ber ...
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Common terms and phrases
acres amount annexing apples arithmetic bought bushels called ciphers common fractions composite number compound interest Compound Numbers contained cord cost cube root cubic decimal fractions diameter divided dividend division dollars equal EXAMPLES FOR PRACTICE expressed factor farthings feet long figure frac gallons Give given number greatest common divisor Hence hogshead hundred hundredths improper fraction inches integers last term length measure merchant miles mills minuend mixed number months multiplicand multiply NOTE number of terms OPERATION oranges paid payment pence pieces pound present worth principal proper fraction proportion pupil quantity quarts Questions Questions.-T quotient rate per cent ratio receive Reduce remainder right hand rule shillings side sold solid feet SOLUTION square miles square root subtraction subtrahend tens tenths third thousandths tion units weight whole number write
Popular passages
Page 146 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Page 196 - What is the interest of $216'80, at 7 per cent., for 1 month ? for 2 months ? 3 mo. ? 4 mo. ? 5 mo. ? 6 mo. ? 7 mo. ? 8 mo. ? 9 mo.? 10 mo. ? 11 mo.
Page 287 - The first term, ratio , and number of terms given to find the sum of the series. 1. A lady bought 6 yards of silk, agreeing to pay 5 cents for the first yard, 15 for the second, and so on, increasing in a three fold proportion ; what did the whole cost ? SOLUTION.
Page 49 - The number to be divided is called the dividend. The number by which we divide is called the divisor. The number which shows how many times the divisor is contained in the dividend is called the quotient.
Page 236 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Page 60 - Multiply the last remainder by the first divisor, and to the product add the first remainder ; the sum will be the true remainder.
Page 55 - Multiply the integer of the quotient by the divisor, and to the product add the remainder, if any ; and the result will equal the dividend, if the work is right.
Page 147 - TABLE. 60 seconds (") - make - 1 minute, - marked - ' 60 minutes ----- 1 degree, - - - - - ° 30 degrees ,----- 1 sign, ------ s. 12 signs, or 360 degrees, - 1 circle of the zodiac. Note. Every circle, whether great or small, is divisible into 360 equal parts, called degrees. 71. Reduce 9s. 13° 25
Page 84 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Page 83 - Fractions. Reduction of fractions is changing them from one form to another without altering their value. To reduce an improper fraction to a whole or mixed number. 1. In 4 halves (J) .of an apple how many whole apples?