 | Thomas Dilworth - Arithmetic - 1810 - 234 pages
...CASE 7. Q. How is the time found when the principal, amount • nad rate per cent are given? A. As the interest of the principal for 1 year at the given rate Is tr- one year: So is the whole interest, To the time required. -• EXAMPLES. 1. In what time will... | |
 | Roswell Chamberlain Smith - 1814 - 300 pages
...The inters« on $200 lor 1 vr. at 6 per cent, is $13; hence a« I i years, the requited time, Jiiu. Q. What, then, is the RULE 7 '• A. Divide the given...principal for 1 year at the given rate ; the quotient Witt be the time required, in years and decinal parts of a year. 2. Paid $36 interest on a note of... | |
 | Phinehas Merrill - Arithmetic - 1819 - 116 pages
...cent. To find the time, iahen the firinci/ial, amount andratefier cent^ . , . are five*. RULE.— As the. interest of the principal for 1 year at the given rate, is to 1 year, so h the whole interest to the time required. EXAMPLES. 1. In what time will L.500 amount... | |
 | Roswell Chamberlain Smith - Arithmetic - 1829 - 284 pages
...is $13 ; henee $13 -H 12 = 1,5 = 1£ years, the required time, Ane. Q. What, then, is the RULE ? JL Divide the given interest by the interest of the principal...be the time required, in years and decimal parts of ay ear. 2. Paid $30 interest on a note of $6O0, the rato being 6 per cent.; what was the time f A.... | |
 | Roswell Chamberlain Smith - Arithmetic - 1831 - 282 pages
...is $12 ; hence $18 -H 12 = 1,5 — 1 \ years, the required time, jîne. Q. What, then, is the RULE ? A. Divide the given interest by the interest of the...be the time required, in years and decimal parts of ay ear. 2. Paid $36 interest on a note of $600, the rate being 6 per tent. ; what was the time ? A.... | |
 | Roswell Chamberlain Smith - Arithmetic - 1831 - 286 pages
...Лепи $18 -H 12 = If *"•• I ,'¿ year«, the required time, .fins. Q. What, then, is the RULE ? A. Divide the given interest by the interest of the...principal for 1 year at the given rate, the quotient will bo the time required, in years and decimal parts of a year. 2. Paid $36 interest on a note of $600,... | |
 | Roswell Chamberlain Smith - 1837 - 306 pages
...cent. u $12; hence $1,8 -«- 12 = 1,5 = IB years, the required time, Ana. Q. What, then, is the RULE ? A. Divide the given interest by the interest of the...quotient will be the time required, in years and decimal narts of a vear. UC11L Wilt 'H tllC Lilt. mal parts of a year. 2. Paid $36 interest on a note of $600,... | |
 | Benjamin Greenleaf - Arithmetic - 1839 - 356 pages
...take 1 year to gain $30, it will require to gain $120, igi° = 4 years Ans. Hence the following RULE. Divide the given interest, by the interest of the principal, for 1 year, and the quotient is the lime. 5. How long must $120 be on interest at 8J per cent. to amount to $133.20... | |
 | Roswell Chamberlain Smith - Arithmetic - 1843 - 306 pages
...cent, i« »12; hence $18-i-13=*U «z I¿ ycarMj the rcqMirod time, Яш. Q. What, then, is the RULE Т A. Divide the given interest by the interest of the...the quotient will be the time required, in years and dec» ша! parts of a year. 8. Taid $3G interest on a note of $000, the rate being 6 p« fent ; what... | |
 | Francis Henney Smith - Arithmetic - 1845 - 300 pages
...Ans. 204* When the principal, rate per cent., and interest are given, we may find the time by dividing the given interest by the interest of the principal for 1 year at the given rate. Thus, If the interest of $500 at 6 per cent. amount to $45, how long was the principal at interest... | |
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Or, make the given interest the numerator, and the interest of the principal for 1 year at the given rate the... 
