| Warren Colburn - Algebra - 1828 - 276 pages
...divisor, produces the dividend 6 ab c. Examples. 1. How many times is 2 « contained in 6 abc ? Ans. **3bc times, because 3 bc times 2 a is 6 ab c. 2. If...letters of the divisor from the dividend. 3. Divide** 16«6c by 4. 4. " 12 abc by 3 a. 5. " 20 abc by 10 b c. 6. " 18 abed by 6 ad. 7. " 23a6c by ab. 8.... | |
| Warren Colburn - Algebra - 1829 - 276 pages
...divided into 2 a parts, what is one of the parts ? Ans. Sic; because 2 a times 3 6 c is 6 « A <• **Hence we derive the following RULE. Divide the coefficient...letters of the divisor from the dividend. 3. Divide** 4. " 5. " 6. « 7. " 8. " 9. " Observe that 4 a3 is the same as 4 aaa and a* is the same as aa ; 4... | |
| John Darby (teacher of mathematics.) - 1829
...Multiplication, and is commonly divided into three cases. CASE I. When the quantities are both simple. **RULE. — Divide the coefficient of the dividend, by the coefficient of the divisor,** to obtain the coefficient of the quotient ; expunge the letters which are common to both quantities,... | |
| Warren Colburn - Algebra - 1830 - 276 pages
...be divided into 2 a parts, what is one of the parts ? Ans. 3 bc ; because 2 « times 3 bc is 6 ab c. **Hence we derive the following RULE. Divide the coefficient...coefficient of the divisor, and strike out the letters of** ilie divisor from the dividend. 3. Divide 1 6 abc by 4. 4. " 12 abc by 3 a. 5. " 20a6c by 10 b c. 6.... | |
| William Smyth - Algebra - 1830 - 264 pages
...From what has been said we have the following rule for the division of simple quantities, viz. 1°. **divide the coefficient of the dividend by the coefficient of the divisor;** 2°. suppress in the dividend the letters, which are common to it and the divisor, when they have the... | |
| Warren Colburn - Algebra - 1833 - 276 pages
...divided into 2 a parts, what is one of tht parts ? Ant. 3 6 c ; because 2 a times 3 bc is 6 a 6 c. **Hence we derive the following RULE. Divide the coefficient...the dividend. 3. Divide 16 abc by 4. 4. " 12a6c by** 3 a. 5. « 20 abc by 10 b c. 6. « 18 abed by Gad. 7. <• 23 abc by a b. 8. " 17 arf by ad. 9. " 4... | |
| Warren Colburn - Algebra - 1834 - 276 pages
...be divided into 2 a parts, what is one of the part? ? AM. 3 bc ; because 2 a times 3 6 c is 6 ab c. **Hence we derive the following RULE. Divide the coefficient of the dividend by the coefficient** rf the divisor, and strike out the letters of the dicisor from the dividend. 3. Divide 16n6c by 4.... | |
| Charles Davies - Algebra - 1835 - 353 pages
...Also1 for, 7ai x 5a'ic = 35a^c. 50. Hence for the division of monomials we have the following RULE. I. **Divide the co-efficient of the dividend by the co-efficient of the divisor.** II. Write in tJie quotient, after the co-efficient, all the tellers common to tlie dividend and divisor,... | |
| Silas Totten - Algebra - 1836 - 304 pages
...therefore, only to reverse the rule for multiplication. For the division of monomials, we have thc'n **the following RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and** to the quotient annex the letters common fo both, each affected wit'i an exponent equal to the difference... | |
| Silas Totten - Algebra - 1836 - 304 pages
...to reverse the rule for multiplication. For the division of monomials, we have then the following i **RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and** to the quotient annex the letters common to both, each affected wit,1 an exponent eqiial>to the difference... | |
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