The Theory and Practice of Surveying: Containing All the Instructions Requisite for the Skillful Practice of this Art |
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... Theo- rems , and Problems , with the description and use of the Sec- tor , Gunter's Scale , and other Mathematical drawing instru- ments , used by surveyors . The fifth section contains Plane Trigonometry , right angled and oblique ...
... Theo- rems , and Problems , with the description and use of the Sec- tor , Gunter's Scale , and other Mathematical drawing instru- ments , used by surveyors . The fifth section contains Plane Trigonometry , right angled and oblique ...
Page 53
... THEO . II . PL . 1. fig . 21 . AEB to If one right line cross another , ( as AC does BD , ) the opposite an- gles made by those lines will be equal to each other : that is , CED , and BEC to AED . By theorem 1. BEC + CED = 2 right ...
... THEO . II . PL . 1. fig . 21 . AEB to If one right line cross another , ( as AC does BD , ) the opposite an- gles made by those lines will be equal to each other : that is , CED , and BEC to AED . By theorem 1. BEC + CED = 2 right ...
Page 54
... theo . ) GEB = CFH , and AEG - HFD . 2. Also GEB - AEF , and CFH - EFD ; but GEB = CFH ( by part 1. of this theo . ) therefore AEF - EFD . The same way we prove FEB = EFC . 3. AEF = EFD ; ( by the last part of this theo . ) but AEF ...
... theo . ) GEB = CFH , and AEG - HFD . 2. Also GEB - AEF , and CFH - EFD ; but GEB = CFH ( by part 1. of this theo . ) therefore AEF - EFD . The same way we prove FEB = EFC . 3. AEF = EFD ; ( by the last part of this theo . ) but AEF ...
Page 55
... THEO . V. PL . 1. fig . 23 . In any triangle ABC , all the three angles , taken together , are equal to two right angles , viz . A + B + ĂCВ 2 right angles . Produce CB to any distance , as D , then ( by the last ) ACD = B ÷ A ; to both ...
... THEO . V. PL . 1. fig . 23 . In any triangle ABC , all the three angles , taken together , are equal to two right angles , viz . A + B + ĂCВ 2 right angles . Produce CB to any distance , as D , then ( by the last ) ACD = B ÷ A ; to both ...
Page 56
... theo . 1. ) ; therefore the three an- gles A + B + ACB = 2 right angles . Q. E. D. Cor . 1. Hence if one angle of a triangle be known , the sum of the other two is also known ; for since the three angles of every triangle con- tain two ...
... theo . 1. ) ; therefore the three an- gles A + B + ACB = 2 right angles . Q. E. D. Cor . 1. Hence if one angle of a triangle be known , the sum of the other two is also known ; for since the three angles of every triangle con- tain two ...
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ABCD acres altitude Answer arch base bearing centre chains and links circle circumferentor Co-sec Co-tang column compasses contained cube root decimal diagonal difference of latitude Dist divided divisions divisor draw east Ecliptic edge EXAMPLE feet field-book figure four-pole chains geometrical series given angle given number half the sum height Hence Horizon glass hypothenuse inches instrument length Logarithms measure meridian distance multiplied Natural Co-sines natural number natural sine Nonius number of degrees object observed off-sets opposite parallelogram perches perpendicular plane pole PROB proportional protractor Quadrant quotient radius rhombus right angles right line screw Secant sect semicircle side square root station subtract survey taken tance Tang tangent theo theodolite trapezium triangle ABC trigonometry two-pole chains vane versed sine vulgar fraction whence
Popular passages
Page 246 - ... that triangles on the same base and between the same parallels are equal...
Page 58 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Page 231 - RULE. From half the sum of the three sides subtract each side severally.
Page 45 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.
Page 14 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Page 5 - His method is founded on these three considerations: 1st, that the sum of the logarithms of any two numbers is the logarithm of the product of...
Page 91 - ... scale. Given the length of the sine, tangent, or secant of any degrees, to find the length of the radius to that sine, tangent, or secant.
Page 35 - DIVISION BY LOGARITHMS. RULE. From the logarithm of the dividend subtract the logarithm of the divisor, and the number answering to the remainder will be the quotient required.
Page 30 - Then, because the sum of the logarithms of numbers, gives the logarithm of their product ; and the difference of the logarithms, gives the logarithm of the quotient of the numbers ; from the above two logarithms, and the logarithm of 10, which is 1, we may obtain a great many logarithms, as in the following examples : EXAMPLE 3.
Page 211 - At 170 feet distance from the bottom of a tower, the angle of its elevation was found to be 52° 30' : required the altitude of the tower ? Ans.