The Theory and Practice of Surveying: Containing All the Instructions Requisite for the Skillful Practice of this Art |
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Page 12
... perches to the dicimal of 5 furlongs 8 40 8 fur . 200 40 = vulgar fraction . 320 320 per . 320 ) 200.0 ( .625 = decimal sought . 192 0 800 640 1600 1600 Reduce 21 minutes 54 seconds to the decimal of a degree . Ans . .365 Reduce 056 of ...
... perches to the dicimal of 5 furlongs 8 40 8 fur . 200 40 = vulgar fraction . 320 320 per . 320 ) 200.0 ( .625 = decimal sought . 192 0 800 640 1600 1600 Reduce 21 minutes 54 seconds to the decimal of a degree . Ans . .365 Reduce 056 of ...
Page 13
... perch- 1 [ es in a rood . 14.0000 The value , therefore , is 1 rood 14 perches . What is the value of .6875 of a yard ? DECIMAL FRACTIONS . 13.
... perch- 1 [ es in a rood . 14.0000 The value , therefore , is 1 rood 14 perches . What is the value of .6875 of a yard ? DECIMAL FRACTIONS . 13.
Page 110
... perches , or miles , & c . and this mark " , ei- ther in an angle or on a side , denotes the angle or side to be required . From these proportions it may be observed ; that to find a side , when the angles and one side are given , any ...
... perches , or miles , & c . and this mark " , ei- ther in an angle or on a side , denotes the angle or side to be required . From these proportions it may be observed ; that to find a side , when the angles and one side are given , any ...
Page 126
... perches , 4A33 ° 45 ' Ans . To find the other two sides . { BC 300 AB 449 Ex . 2. In the right - angled triangle ABC . Given , the base AB 162 chains , Ans . To find the other two sides . AC 270 BC 216 Ex . 3. In the right - angled ...
... perches , 4A33 ° 45 ' Ans . To find the other two sides . { BC 300 AB 449 Ex . 2. In the right - angled triangle ABC . Given , the base AB 162 chains , Ans . To find the other two sides . AC 270 BC 216 Ex . 3. In the right - angled ...
Page 145
... perches , which consists of 100 links ; and this is the most natural division ) or by one of 50 links , which contains two poles or perches : but because the length of a perch differs in many places , therefore the length of chains and ...
... perches , which consists of 100 links ; and this is the most natural division ) or by one of 50 links , which contains two poles or perches : but because the length of a perch differs in many places , therefore the length of chains and ...
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Common terms and phrases
ABCD acres altitude Answer arch base bearing centre chains and links circle circumferentor Co-sec Co-tang column compasses contained cube root decimal diagonal difference of latitude Dist divided divisions divisor draw east Ecliptic edge EXAMPLE feet field-book figure four-pole chains geometrical series given angle given number half the sum height Hence Horizon glass hypothenuse inches instrument length Logarithms measure meridian distance multiplied Natural Co-sines natural number natural sine Nonius number of degrees object observed off-sets opposite parallelogram perches perpendicular plane pole PROB proportional protractor Quadrant quotient radius rhombus right angles right line screw Secant sect semicircle side square root station subtract survey taken tance Tang tangent theo theodolite trapezium triangle ABC trigonometry two-pole chains vane versed sine vulgar fraction whence
Popular passages
Page 246 - ... that triangles on the same base and between the same parallels are equal...
Page 58 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Page 231 - RULE. From half the sum of the three sides subtract each side severally.
Page 45 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.
Page 14 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Page 5 - His method is founded on these three considerations: 1st, that the sum of the logarithms of any two numbers is the logarithm of the product of...
Page 91 - ... scale. Given the length of the sine, tangent, or secant of any degrees, to find the length of the radius to that sine, tangent, or secant.
Page 35 - DIVISION BY LOGARITHMS. RULE. From the logarithm of the dividend subtract the logarithm of the divisor, and the number answering to the remainder will be the quotient required.
Page 30 - Then, because the sum of the logarithms of numbers, gives the logarithm of their product ; and the difference of the logarithms, gives the logarithm of the quotient of the numbers ; from the above two logarithms, and the logarithm of 10, which is 1, we may obtain a great many logarithms, as in the following examples : EXAMPLE 3.
Page 211 - At 170 feet distance from the bottom of a tower, the angle of its elevation was found to be 52° 30' : required the altitude of the tower ? Ans.