38. What will 72 yards of broadcloth cost, at 19s. 11d. per yard ?

39. What will 84 yards of cotton cost, at 1s. 11d. per yard ? 40. Bought 90 hogsheads of sugar, each weighing 12cwt. 2qr. 11lb.; what was the weight of the whole?

41. What cost 18 sheep, at 5s. 94d, a piece?

42. What cost 21 yards of cloth, at 9s. 11d. per yard? 43. What cost 22 hats, at 11s. 6d. each?

44. If 1 share in a certain stock be valued at 13£. 8s. 91d., what is the value of 96 shares?

45. If 1 spoon weigh 3oz. 5dwt. 15gr., what is the weight of 120 spoons ?

46. If a man travel 24m. 7fur. 4rd. in 1 day, how far will he go in 1 month?

47. If the earth revolve 0° 15′ per minute, how far per hour? 48. Multiply 39A. 3R. 17p. 30yd. 8ft. 100in. by 32.

49. If a man be 2d. 5h. 17m. 19sec. in walking 1 degree, how long would it take him to walk round the earth, allowing 365 days to a year?

CASE III.

When the multiplier is such a number as cannot be produced by the product of two or more numbers, we should proceed as in the following

EXAMPLE.

50. What is the value of 53 tons of iron, at 18£. 17s. 11d. a

944

9 7= price of 5 tons.

10

15 10= price of 50 tons. 56 13 9 price of 3 tons. 1001 9 7 price of 53 tons.

£. 8. d.
18 17 11

3

56 13 9= price of 3 tons.

Because 53 is a prime nurnber, that is, it cannot be produced by the product of any two numbers; we therefore find a convenient composite number less than the given number, viz. 50, which may be produced by multiplying 5 by 10. Having found the price of 50 tons by the last Case, we then find the price of the 3 remaining tons by Case I., and add it to the former, making the value of the whole quantity 1001£. 9s. 7d.

The pupil will hence perceive the propriety of the following

RULE.

Take for successive multipliers two or more numbers, whose continued product will be nearest the proper multiplier, and then find the value of the remainder by Case I., and the sum of the last two products will be

the answer.

51. What will 57 gallons of wine cost, at 8s. 34d. per gallon? 52. Bought 29 lots of wild land, each containing 117A. 3R. 27p.; what were the contents of the whole ?

53. Bought 89 pieces of cloth, each containing 37yd. 3qr. 2na. 2in.; what was the whole quantity?

54. Bought 59 casks of wine, each containing 47gal. 3qt. 1pt.; what was the whole quantity?

55. If a man travel 17m. 3fur. 13rd. 14ft. in one day, how far will he travel in a year?

56. If a man drink 3gal. 1qt. 1pt. of beer in a week, how much will he drink in 52 weeks?

57. There are 17 sticks of timber, each containing 37ft. 978in.; what is the whole quantity?

58. There are 17 piles of wood, each containing 7 cords 98 cubic feet; what is the whole quantity? 59. Multiply 2hhd. 19gal. Oqt. 1pt. by 39. 60. Multiply 3bu. 1pk. 4qt. 1pt. 1gi. by 53. 61. Multiply 16ch. 7bu. 2pk. Oqt. Opt. by 17.

5.

John Jones, of Philadelphia, U. S.,

Liverpool, June 2, 1835.

Bought of Thomas Hasseltine,

297 yds. Black Broadcloth, at 17s. 34d.

London, May 11, 1846.

Messrs. Kimball, Jewett, & Co., of Boston, U. S.,

Bought of Benjamin Fowler,

2345 yds. Red Broadcloth, at

1£. 17s. 94d. :

=

£. S. d. 4428 12 71

186 66 Green do.

66

SECTION XV.

COMPOUND DIVISION.

COMPOUND DIVISION is when the dividend consists of several denominations.

EXAMPLES.

1. Divide 598£. 8s. 9d. equally among 5 persons.

£.

8. d.

Having divided the pounds by 5, we find 5)598 8 9 3£. remaining, which are 60s.; to these we 119 13 9 add the 8s. in the question, and again divide by 5 and find 3s. remaining, which are 36d.; to these we add the 9d. in the question, and divide their sum by 5. The several quotients we write under their respective denominations.

2. Divide 168£. 15s. Od. equally among 36 men.

From the above examples and illustrations we deduce the following

RULE.

Divide the highest denomination of the dividend by the divisor, and, if there be a remainder, reduce it to the next lower denomination, adding to the number thus found the number in the dividend of the same denomination. Divide the result thus obtained by the divisor; and, if there be a remainder, proceed as before, till all the denominations of the dividend are taken, or till the work is finished. The successive quotients will be of the same denominations with the successive numbers divided, or will correspond with the several denominations of the dividend.