| Mathematics - 1801
...diminished, is called the ratio. PROBLEM I. Given the first termt the last term, and the ratio, to find tht **sum of the series. RULE.* Multiply the last term by...ratio, and from the product subtract the first term,** and the remainder, divided by the ratio less I, will give the sum of the series. EXAMPLES. * DEMONSTRATION.... | |
| Samuel Webber - Mathematics - 1808
...calfed the r'atio. PR0BLEM I. Giyen thejirst term, the last term, and the ratio, to find the sum of thc **series. RULE.* Multiply the last term by the ratio, and from the product subtract the first term,** and the remainder, divided by the ratio less 1, will give the sum of the series. • DEM0NSTRATI0N.... | |
| Samuel Webber - Arithmetic - 1812 - 248 pages
...increased or diminished, is called the ratio. PROBLEM 1. Given thefirst term, the last term, and the ratio, **to find the sum of the series. RULE.* Multiply the...ratio, and from the product subtract the first term,** and the remainder, divided by the ratio less 1, will give the sum of the series. * DEMONSTRATION. Take... | |
| Jeremiah Joyce - Arithmetic - 1812 - 258 pages
...determined. I. Given the first term a, the last term z, and the common ratio r, to find the sum s. **RULE. Multiply the last term by the ratio, and from the product subtract the first term,** and the remainder divided by the ratio, less one, will give the sum of the series ; or — r — 1... | |
| Nathan Daboll - Arithmetic - 1818 - 240 pages
...8, 1 6, &c. increase by the multiplier 2 ; and 27, $, 3, 1, decrease by the divisor 3. PROBLEM I. >i **The first term, the last term (or the extremes) and...the sum of the series. RULE. Multiply the last term** fay the ratio, and from the product subtract the first term ; then divide the remainder by the- ratio,... | |
| Arithmetic - 1818 - 251 pages
...is called the RATIO. PROBLEM I. Given the first term, the last term, (or extremes') and the ra* t|O, **to find the sum of the series, RULE. Multiply the...ratio, and from the product subtract the first term,** and the rem ainder, divided by the ratio less I, wjif'give the sum of all the terms of the series.... | |
| Phinehas Merrill - Arithmetic - 1819 - 107 pages
...answer. CASE H. •Given the first term, the last term, and the ratio, to find the aggregate or total **sum of the series. RULE. — Multiply the last term...ratio, and from the product subtract the first term,** and the remainder, divided by the ratio less one, will give the sum of the whole series. EXAMPLES.... | |
| Nicolas Pike - Arithmetic - 1822 - 532 pages
...terms ? Ana. £Jff. Ill 18. What is the sura of j-^t, f^.^p- &c. to infinity ? Ans. 16f. PROBLEM IH. **The .first term, the last term (or the extremes) and the ratio given,** ft> Jlnd the snm of the series.^. RULE I. Divide the difference of the extremes by the ratio legs by... | |
| Nathan Daboll - Arithmetic - 1823 - 240 pages
...8, 16, &.c. increase by the multiplier 2: and S7, 9, 3, 1, decrease by the divisor 3. PROBLEM I. . ' **The first term, the last term (or the extremes) and the ratio given, to** fmd the-sum of the series. RULE. Multiply the last term by t!ie ratio, and from the product subtract... | |
| Zadock Thompson - Arithmetic - 1826 - 164 pages
...is called the ratio. Problem I. The Jlnt term, the latt term, and the ratio given to find the turn **of the series. RULE.* — Multiply the last term by...ratio, and from the product subtract the first term,** and the remainder divided by the ratio, less 1, will give the sum of the series. Examples. 1 . The... | |
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