Elementary Algebra |
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12 rods A's share a² b³ a³ b² added algebraic algebraic quantities arithmetical arithmetical progression binomial bought bushels called cents coefficient completing the square compound interest denominator Divide the number dividend divisor dollars equal equation equidifference evident exponent Extract the square extracting the root factors feet find a number find the square Find the values following rule formula fourth fraction gallons gentleman given number gives greater last term learner least common multiple less letters logarithm manner monomial multiplied number of terms obtain perfect square permutations persons piece polynomials positive pounds progression by difference progression by quotient proportion proposed ratio received Reduce remainder result rods second degree sheep shillings square root subtracted third tion travelled twice unknown quantity value of x whence whole number yards
Popular passages
Page 134 - ... said he, I have not a hundred, but if I had as many more, and half as many more, and two geese and a half, I should have a hundred.
Page 135 - Two travellers, A and B, set out to meet each other, A leaving the town C at the same time that B left D. They travelled the direct road between C and D ; and on meeting, it appeared that A had travelled 18 miles more than B, and that A could have gone B's distance in 15J days, but B would have been 28 days in going A's distance.
Page 102 - In a series of equal ratios, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent.
Page 13 - A company of 90 persons consists of men, women, and children. The men are 4 in number more than the women, the children 10 more than the adults. How many men, women, and children, are there in the company ? f 22 men, .•In*.
Page 171 - There is a number consisting of two digits, which being multiplied by the digit on the left hand, the product is 46; but if the sum. of the digits be multiplied by the same digit, the product is only 10. Required the number. Ans. 23.
Page 122 - Multiply £ the sum of the extremes by the number of terms, and the product will be the answer 10.
Page 106 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Page 157 - At this sale, he loses as much per cent. upon the price of his purchase as the horse cost him. What did he pay for the horse...
Page 138 - A charitable person distributed a certain sum amongst some poor men and women, the number of whom were in the proportion of 4 to 5. ' Each man received one third as many shillings as there were persons relieved ; and each woman received twice as many shillings as there were women more than men. The men received all together 18s.
Page 148 - This result indicates, that there is some absurdity in the conditions of the question proposed, since in order to obtain the value of x, we must extract the root of a negative quantity, which is impossible. In order to see in what this absurdity consists, let us examine into what two parts a given number should be divided, in order that the product of these parts may be the greatest possible. Let us represent the given number by p, the product of the two parts by q, and the difference of the two...