The Elements of Arithmetic...: In which Decimal and Integral Arithmetic are Combined, and Taught Inductively, on the System of Pestalozzi, Part 2 |
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Page 19
... gives in addition , as well as for the exercise of the memory . 1. 49863 x .06 x 1.3 = ? 2. Multiply 7441.08 by 236 . 3. Find .06 of 284931.75 . 4. Find .0725 of 164.25 × 1000 . 5. 96.8 × 12000 × 45.93 = ? 6. Multiply 4489.076 by ...
... gives in addition , as well as for the exercise of the memory . 1. 49863 x .06 x 1.3 = ? 2. Multiply 7441.08 by 236 . 3. Find .06 of 284931.75 . 4. Find .0725 of 164.25 × 1000 . 5. 96.8 × 12000 × 45.93 = ? 6. Multiply 4489.076 by ...
Page 22
... give a quotient as large as , or larger than , the divisor . If there is but one such figure , it will be the one sought ; if there is more than one , the larger will be the true quotient figure . 1. Divide .0497 by 368000 . 2. What is ...
... give a quotient as large as , or larger than , the divisor . If there is but one such figure , it will be the one sought ; if there is more than one , the larger will be the true quotient figure . 1. Divide .0497 by 368000 . 2. What is ...
Page 26
... give each of them 5 , and have 1 left . If we wish to divide the re- maining apple among them , we must cut it into 3 equal parts , and give one to each of them . Each of those parts would be called one - third , and written . Again ...
... give each of them 5 , and have 1 left . If we wish to divide the re- maining apple among them , we must cut it into 3 equal parts , and give one to each of them . Each of those parts would be called one - third , and written . Again ...
Page 34
... gives 4071 for the true remainder . .4071 remainder . 1. Divide 870468 by 999 ; by 99 . 2. Divide 408176 by 999 ; by 9999 . 3. Divide 7963142 by 999000. Divide first by 999 , then divide the quotient by 1000 . 4. Divide 1046.84 by 993 ...
... gives 4071 for the true remainder . .4071 remainder . 1. Divide 870468 by 999 ; by 99 . 2. Divide 408176 by 999 ; by 9999 . 3. Divide 7963142 by 999000. Divide first by 999 , then divide the quotient by 1000 . 4. Divide 1046.84 by 993 ...
Page 36
... give to each remainder the name of the dividend from which it is derived . 1. In 41 chal . 19 bu . of coal , how many pecks ? 2. How many cwt . & c . , in 1870953 gr . ? 3. How many , & c . , in 24753 gr . Troy ? 4. Reduce 195 113 33 to ...
... give to each remainder the name of the dividend from which it is derived . 1. In 41 chal . 19 bu . of coal , how many pecks ? 2. How many cwt . & c . , in 1870953 gr . ? 3. How many , & c . , in 24753 gr . Troy ? 4. Reduce 195 113 33 to ...
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Common terms and phrases
5th power 9 hours acres amount annuity approximate values Arithmetic Avoirdupois bill bought bushel cents a pound column commence common difference compound interest contained continued fraction cost cube root cubic decimal denominator diameter discount Divide dividend divisible dollars dominical letter equal example exchange Extract extremes feet fraction gain gallons Geometrical Progression given number greatest common divisor harmonical means hours a day hundred improper fraction inches last term least common multiple less lowest terms marcs mean proportional miles minuend months multiplicand Multiply number of terms obtained oxen paid payable payment piece present worth prime factors prime number PROBLEM quotient figure ratio Reduce remainder repetend rods root figure RULE sold square number square root subtract sugar tens third trial divisor undecillion units weeks weighs whole number wide yards zeroes లు
Popular passages
Page 127 - And we may moreover observe, that the sum of the extremes is equal to the sum of any two terms equally distant from the extremes, or to twice the middle term, when the number of terms is odd.
Page 177 - To find the solid contents of a cylinder. RULE. Multiply the area of the base by the height.
Page 107 - Take a series of numbers, commencing with the number of things given, and decreasing by 1, until the number of terms is equal to the number of things to be taken at a time : the product of all the terms will be the answer required.
Page 18 - ... move the decimal point as many places to the right as there are ciphers in the multiplier.
Page 166 - If 2 men start from the same place and travel in opposite directions, one at the rate of 4...
Page 29 - Ten Pounds Avoirdupois Weight of distilled Water weighed in Air, at the Temperature of Sixty two Degrees of Fahrenheit's Thermometer, the Barometer being at Thirty Inches...
Page 106 - PROBLEM II. Any number of different things being given, to find how many changes can be made out of them by taking a given number of the things at a time.
Page 106 - To find the number of Permutations or changes, that can be made of any given number of things, all different from each other.- . RULE. Multiply all the terms of the natural series of numbers, from one up to the given number, continually together, and the last product will be the answer required.
Page 20 - DIVISION is the process by which we find how many times one number or part of a number is contained in, or may be subtracted from, another. The number to be divided is the dividend. The number to divide by, is the divisor. The number of times the dividend contains the divisor, is the quotient. The divisor and quotient may also be regarded as factors of the dividend. The number left, (if any,) after the operation, is the remainder.
Page 27 - RULE. Multiply all the numerators together for a new numerator, and all the denominators for a new denominator: then reduce the new fraction to its lowest terms.