A Practical and Theoretical System of Arithmetic: Containing a New System of Proportion : with Theoretical Explanations of All the Principal Rules |
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Page 32
... quantity of provision will last 324 men 7 days ; how many men will it last one day ? Ans . 2268 . 13. A garrison of 527 men have provision sufficient to last 47 days , if each man is allowed 15 oz . per day ; how many men would it serve ...
... quantity of provision will last 324 men 7 days ; how many men will it last one day ? Ans . 2268 . 13. A garrison of 527 men have provision sufficient to last 47 days , if each man is allowed 15 oz . per day ; how many men would it serve ...
Page 33
... quantities con- sisting of different denominations , but of the same generic kind ; as Tons , Hundreds , Quarters , & c .; Bushels , Pecks , Quarts , Pints . The following Tables of the denominations of Compound Numbers , are to be ...
... quantities con- sisting of different denominations , but of the same generic kind ; as Tons , Hundreds , Quarters , & c .; Bushels , Pecks , Quarts , Pints . The following Tables of the denominations of Compound Numbers , are to be ...
Page 39
... quantity remains unchanged , although it is expressed in a different denomination . When higher denominations are to be reduced to lower . RULE . Multiply the successive denominations , commen- cing with the highest given , by as many ...
... quantity remains unchanged , although it is expressed in a different denomination . When higher denominations are to be reduced to lower . RULE . Multiply the successive denominations , commen- cing with the highest given , by as many ...
Page 45
... . 4. 12 cwt . of sugar , at £ 3 7s . 4d . per cwt . Ans . £ 40 8s . 5. The weight of 3 chests of tea , each weighing 3 cwt Ans . 10 cwt . 2 qr . 27 lb. 2 qr . 9 lb. 6. What quantity of wood in 6 parcels , each COMPOUND NUMBERS . 45.
... . 4. 12 cwt . of sugar , at £ 3 7s . 4d . per cwt . Ans . £ 40 8s . 5. The weight of 3 chests of tea , each weighing 3 cwt Ans . 10 cwt . 2 qr . 27 lb. 2 qr . 9 lb. 6. What quantity of wood in 6 parcels , each COMPOUND NUMBERS . 45.
Page 46
... quantity of wood in 6 parcels , each containing 3 cords and 96 feet ? ( 7 ) Ans . 224 cords ( 8 ) ( 9 ) lb. oz . dwt . gr . Multiply 21 1 7 13 lb. oz . dr . sc yd . qr . n . 2 4 2 1 8 32 4 7 12 ( 10 ) gal . qt . pt . gi . 3 2 1 3 ( 11 ) ...
... quantity of wood in 6 parcels , each containing 3 cords and 96 feet ? ( 7 ) Ans . 224 cords ( 8 ) ( 9 ) lb. oz . dwt . gr . Multiply 21 1 7 13 lb. oz . dr . sc yd . qr . n . 2 4 2 1 8 32 4 7 12 ( 10 ) gal . qt . pt . gi . 3 2 1 3 ( 11 ) ...
Other editions - View all
A Practical and Theoretical System of Arithmetic: Containing Several New ... George Willson No preview available - 2016 |
A Practical and Theoretical System of Arithmetic: Containing a New System of ... George Willson No preview available - 2016 |
Practical and Theoretical System of Arithmetic: Containing a New System of ... George Willson No preview available - 2017 |
Common terms and phrases
acres amount angles annuity annum barrels bought bushels bushels of oats bushels of wheat cents a bushel ciphers compound interest Compound Numbers contain cube root cubic currency decimal point denote diameter divide the product dividend division divisor dollars equal example Federal Money feet long Find the interest gallons given number hand figures hours a day hypotenuse improper fraction inches integer least common multiple length less lowest terms method miles mills minuend mixed number months multiplicand Multiply number of terms paid payment perpendicular piece pound principal quantity question quotient ratio Reduce remainder Required the interest rhombus right-angled rods Rule of Three RULE.-Multiply separatrix share shillings sides simple solid square root statement subtract third term tion triangle Troy Weight units vulgar fraction weight whole number yards cost yards of cloth
Popular passages
Page 164 - Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terns. EXAMPLES. 1. If the extremes be 3 and 45, and the common difference 2 ; what is the number of terms 1 Ans.
Page 62 - Multiplying or dividing both terms of a fraction by the same number does not change its value.
Page 164 - PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct.
Page 105 - If 8 men can build a wall 20 feet long, 6 feet high and 4 feet thick, in 12 days ; in what time...
Page 174 - To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area.
Page 51 - When the numerator is less than the denominator, the value of the fraction is less than 1.
Page 55 - ... thing remains, multiply it by the next inferior denomination, and divide by the denominator as before, and so on as far as necessary, and the quotient will be the answer.
Page 124 - The rule for casting interest, when partial payments have been made, is to apply the payment, in the first place, to the discharge of the interest then due. If the payment exceeds the interest, the surplus goes towards discharging the principal, and the subsequent interest is to be computed on the balance of principal remaining due.
Page 53 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Page 102 - The fourth term is found by multiplying the second and third terms together and dividing by the first § 14O.