The Western Arithmetic: Or, Pennsylvania and Ohio Accomptant: Being a Plain Practical Treatise, with a Complete System of Mensuration |
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Page 6
... bases 165 are equal 185 165 165 Of round timber , whose bases are unequal 186 166 Of the Five Regular Bodies 171 Of a Tetraedron · 186 186 172 Octaedron · ❤ · 186 172 Dodecaedron · 187 173 · Icosaedron 173 Of any irregular body 173 ...
... bases 165 are equal 185 165 165 Of round timber , whose bases are unequal 186 166 Of the Five Regular Bodies 171 Of a Tetraedron · 186 186 172 Octaedron · ❤ · 186 172 Dodecaedron · 187 173 · Icosaedron 173 Of any irregular body 173 ...
Page 164
... base by half the perpendicular , or half the base by the whole perpendicular ; or multiply the whole base by the whole perpendicular , and take half the product . Any of these ways will give the content . Let the base of a right ...
... base by half the perpendicular , or half the base by the whole perpendicular ; or multiply the whole base by the whole perpendicular , and take half the product . Any of these ways will give the content . Let the base of a right ...
Page 174
... base , or greatest ordinate , by the perpendicular height , and multiply that product by 2 , and divide the last product by 3 , and the quotient will be the area of the parabola . Let it be required to find the area of a parabola , whose ...
... base , or greatest ordinate , by the perpendicular height , and multiply that product by 2 , and divide the last product by 3 , and the quotient will be the area of the parabola . Let it be required to find the area of a parabola , whose ...
Page 175
... base , and multiply said area by the length in inches , and divide that product by 1728 ; or multiply the area of the base by length in feet , and divide by 144 , and you will have the solid content in feet . Ans . 45,9+ feet , the ...
... base , and multiply said area by the length in inches , and divide that product by 1728 ; or multiply the area of the base by length in feet , and divide by 144 , and you will have the solid content in feet . Ans . 45,9+ feet , the ...
Page 176
... base . To find the solid content thereof , this is the RULE . To the rectangle ( or product ) of the sides of the two bases , add the sum of their squares , and that sum being multiplied into one - third part of the frustum's height ...
... base . To find the solid content thereof , this is the RULE . To the rectangle ( or product ) of the sides of the two bases , add the sum of their squares , and that sum being multiplied into one - third part of the frustum's height ...
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Common terms and phrases
100 dollars 25 cents 9 inches amount annuity annum answer barrels Bought breadth bushels ciphers circle circumference compound interest contained cube root Culen decimal denominator diameter difference dimes divide dividend divisor dollars 25 dollars 50 cents dolls dominical letter DRY MEASURE epact equal EXAMPLES feet 6 inches figure find the area find the solid frustum furlongs gain gallons given number given sum given to find half hhds hogshead improper fraction inches length measure miles mills months multiply neat weight number of terms Paid 1st perpendicular present worth principal proportion Question quotient rate per cent Reduce remainder resolvend rods RULE semidiameter side sold solid content specific gravity square root subtract superficial content Suppose thereof thick third timber triangle triple TROY WEIGHT unit's place VULGAR FRACTIONS whole number yards
Popular passages
Page 65 - Operations with Fractions A) To change a mixed number to an improper fraction, simply multiply the whole number by the denominator of the fraction and add the numerator.
Page 109 - But if any payment be made before one year's interest hath accrued, then compute the interest on the principal sum due on the obligation for one year, add it to the principal, and compute the interest on the sum paid, from the time it was paid, up to the end of the year : add it to the sum paid, and deduct that sum from the principal and interest added as...
Page 153 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 74 - Multiply all the numerators together for a new numerator, and all the denominators together for a new denominator.
Page 127 - PROBLEM II. • The first term, the last term, and the number of terms given, to find the common difference. RULE. Divide the difference of the extremes by the number o.
Page 206 - ... as the diameter of the axle is to the diameter of the wheel, so is the power applied to the wheel, to the weight suspended by the axle.
Page 63 - If 8 men can build a wall 20 feet long, 6 feet high and 4 feet thick, in 12 days ; in what time...
Page 141 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Page 11 - APOTHECARIES' WEIGHT 20 grains = 1 scruple. 3 scruples = 1 dram. 8 drams = 1 ounce. 12 ounces = 1 pound.
Page 111 - ... amount of the second, and so on for any number of years required. Subtract the original principal from the last amount, and the remainder will be the Compound Interest for the whole time.