Practical and Mental Arithmetic, on a New Plan, in which Mental Arithmetic is Combined with the Use of the Slate: Containing a Complete System for All Practical Purposes ...R.L.Underhill & Company, 1814 |
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Page 10
... hence its introductiei into our own country Q. About what time was it introduced into England ? A. About the middle of the eleventh century . Q. How extensively is it now used ? 4. All over the civilized world A. Ten , ( 10. ) Q. How ...
... hence its introductiei into our own country Q. About what time was it introduced into England ? A. About the middle of the eleventh century . Q. How extensively is it now used ? 4. All over the civilized world A. Ten , ( 10. ) Q. How ...
Page 3
... hence the 5 must be placed in the tens ' place . To explain why you add the two products together . Q. What does multiplying 365 by 6 give ? A. The number of days in 6 years . Q. What does mutuplying 365 by 3 tens give ? . As the 3 ...
... hence the 5 must be placed in the tens ' place . To explain why you add the two products together . Q. What does multiplying 365 by 6 give ? A. The number of days in 6 years . Q. What does mutuplying 365 by 3 tens give ? . As the 3 ...
Page 4
... hence the value is in- creased 10 times . Q. What effect would two ciphers have , or three ciphers , & c ! A. Two ciphers would remove any figure two places towards the left , and of course increase it 100 times , and so on for 1000 ...
... hence the value is in- creased 10 times . Q. What effect would two ciphers have , or three ciphers , & c ! A. Two ciphers would remove any figure two places towards the left , and of course increase it 100 times , and so on for 1000 ...
Page 20
... hence , when the cents are less than 10 , they must occupy the units ' place of cents , and a cipher the tens ' place of cents . Q. In writing down mills with dollars , when there are no cents , how many ciphers must you place between ...
... hence , when the cents are less than 10 , they must occupy the units ' place of cents , and a cipher the tens ' place of cents . Q. In writing down mills with dollars , when there are no cents , how many ciphers must you place between ...
Page 12
... Hence , to divide by 54 , 304 , & c . , we need only bring the divisor into halves , quarters , & c . , also the dividend into the same , and the quotient will be the answer . 29. In 132 yards how many rods ? In 4224 yards ? A 792 rods ...
... Hence , to divide by 54 , 304 , & c . , we need only bring the divisor into halves , quarters , & c . , also the dividend into the same , and the quotient will be the answer . 29. In 132 yards how many rods ? In 4224 yards ? A 792 rods ...
Other editions - View all
Practical and Mental Arithmetic, on a New Plan, in Which Mental Arithmetic ... Roswell C. Smith No preview available - 2017 |
Practical and Mental Arithmetic on a New Plan, in Which Mental Arithmetic Is ... Roswell Chamberlain Smith No preview available - 2017 |
Common terms and phrases
12 leaves 20 cents 50 cents acres amount annuity apiece apples barrel bbls broadcloth bushels bushels of rye called ciphers cloth cost common denominator common fraction compound interest contained cord feet cube root derive the following dimes divide dividend divisor dollars equal example Exercises farthings federal money feet long feet wide figure following RULE gain gallons gals gills give greatest common divisor hence hogshead hundred illustrations we derive improper fraction James least common least common multiple length lowest terms miles mills mixed number molasses months Multiply number of terms OPERATION oranges ounces payment pence pints pounds present worth proceed pupil pwts quarts quotient ratio Reduce remainder shillings Slate sold solid feet solid inches square feet square rods square root subtract units whole number write yards of cloth
Popular passages
Page 17 - ... then compute the interest on the principal sum due on the obligation for ONE YEAR, add it to the principal, and compute the interest on the sum paid from the time it was paid up to the end of the year; add it to the sum paid, and deduct that sum from the principal and interest added as above.
Page 16 - Compute the interest to the time of the first payment ; if that be one year or more from the time the interest commenced, add it to the principal, and deduct the payment from the sum total. If there be...
Page 16 - But if any payments be made before one year's interest hath accrued, then compute the interest on the principal sum due on the obligation, for one year, add it to the principal, and compute the interest on the sum paid, from the time it was paid, up to the end of the...
Page 7 - Subtract the cube thus found from the said period, and to the remainder bring down the next period, and call this the dividend.
Page 2 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 8 - Divide by any number that will divide two or more of the given numbers without a remainder, and set the quotients, together with the undivided numbers, in a line beneath.
Page 12 - Divide the difference of the extremes by the common difference, and the quotient, increased by 1 , will be the answer.
Page 5 - Multiply the second and third terms together, and divide their product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term.
Page 16 - COMPUTE the interest on the principal sum, from the time when the interest commenced to the first time when a payment was made, which exceeds either alone or in conjunction with the preceding payments (if any) the interest at that time due: add that interest to the principal, and from the sum subtract the payment made at that time, together with the preceding payments (if any) and the remainder forms a new principal ; on which, compute and subtract the interest, as upon the first principal: and proceed...