Elementary ArithmeticHarper & Brothers, 1878 |
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Results 1-5 of 21
Page 41
... load of hay with the wagon weighed 2,656 pounds on the hay scales , and the wagon alone weighed 987 pounds . How much did the hay weigh ? 1,669 pounds . 58. At a certain election 2,649 votes were cast for one can- didate , and 1,975 ...
... load of hay with the wagon weighed 2,656 pounds on the hay scales , and the wagon alone weighed 987 pounds . How much did the hay weigh ? 1,669 pounds . 58. At a certain election 2,649 votes were cast for one can- didate , and 1,975 ...
Page 43
... loads of hay , which weighed 1,577 pounds , 1,891 pounds , 1,648 pounds , 2,154 pounds , 1,736 pounds , 1,954 pounds , and 2,026 pounds . What was the weight of the seven loads ? What was 3. On board an ocean steamer were 114 cabin ...
... loads of hay , which weighed 1,577 pounds , 1,891 pounds , 1,648 pounds , 2,154 pounds , 1,736 pounds , 1,954 pounds , and 2,026 pounds . What was the weight of the seven loads ? What was 3. On board an ocean steamer were 114 cabin ...
Page 50
... loads of flour - barrels , and each load contained 146 barrels . How many barrels did he send ? 14. In one mile there are 5,280 feet . How many feet in 8 miles ? 15. The Pennsylvania Central Railroad Company bought 6 locomotives , at ...
... loads of flour - barrels , and each load contained 146 barrels . How many barrels did he send ? 14. In one mile there are 5,280 feet . How many feet in 8 miles ? 15. The Pennsylvania Central Railroad Company bought 6 locomotives , at ...
Page 50
... load contained 146 barrels . send ? What is the product ? loads of flour - barrels , and How many barrels did he 14. In one mile there are 5,280 feet . How many feet in 8 miles ? 15. The Pennsylvania Central Railroad Company bought 6 ...
... load contained 146 barrels . send ? What is the product ? loads of flour - barrels , and How many barrels did he 14. In one mile there are 5,280 feet . How many feet in 8 miles ? 15. The Pennsylvania Central Railroad Company bought 6 ...
Page 56
... load of 74 bushels of oats , allowing 32 pounds to a bushel ? 2,368 . 57. How much are 132 ounces of gold worth , at $ 16 an ounce ? 58. How many hills of corn in a field that contains 36 rows , and 185 hills in each row ? 59. A ...
... load of 74 bushels of oats , allowing 32 pounds to a bushel ? 2,368 . 57. How much are 132 ounces of gold worth , at $ 16 an ounce ? 58. How many hills of corn in a field that contains 36 rows , and 185 hills in each row ? 59. A ...
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Common terms and phrases
12 rods acres amount annex apples blocks bushels cents ciphers Commence Compound Numbers contained cords of wood cost Count by 9's cubic inches dealer decimal figures decimal point Divide Division divisor dollars dreds Dry Measure equal EXPLANATION EXPLANATION.-Since Express by figures farm farmer fence foot fourth gallons Hence higher denomination hundred hundred-thousandths hundredths improper fraction inches long inches wide integer interest Lake Itasca loads lowest terms Manual measure millionths minuend mixed number month multiplicand Multiply ounces paid partial dividend pile pint place the decimal pounds PROBLEMS pupils quarts quires quotient railroad Read Reduce remainder result right-hand figure rods long SECOND SOLUTION sell sheets similar fractions sold square miles subtract subtrahend ten-millionths ten-thousandths tenths third thousand thousandths tons week weighing Write in words write the numbers written yards
Popular passages
Page 177 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Page 78 - Cut off the ciphers from the divisor, and the same number of figures from the right of the dividend.
Page 138 - A pile of wood 8 feet long, 4 feet wide, and 4 feet high, contains 1 cord; and a cord foot is 1 foot in length of such a pile.
Page 55 - Zeros at the right of the partial products, since they do not affect the result of the addition, should be omitted as in (2). Care must be taken, however, to put the right-hand figure of each partial product directly under the figure of the multiplier used to obtain it.
Page 32 - It shows that the number after it is to be subtracted from the number before it.
Page 78 - III. Multiply the divisor by this quotient figure, subtract the product from the partial dividend, and to the remainder annex the next figure of the dividend.
Page 64 - It shows that the number before it is to be divided by the number after it. The expression 6 -H 2 = 3 is read, 6 divided by 2 is equal to 3.
Page 183 - This quotient may be obtained by multiplying the numerator of the dividend by the denominator of the divisor for the numerator of the quotient, and the denominator of the dividend by the numerator of the divisor for the denominator of the quotient Hence, the Rule.
Page 41 - RULE. — Place the less number under the greater, so that units of the same order shall stand in the same column. Commencing at the right hand, subtract each figure of the subtrahend from the figure above it.
Page 79 - Then divide the remaining figures of the dividend by the remaining figures of the divisor.