Elementary ArithmeticHarper & Brothers, 1878 |
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Page 28
... gain $ 1,565 . For how much did he sell it ? 67. A merchant pays for rent of store 1,275 dollars a year , for clerk - hire 3,895 dollars , for fuel 242 dollars , for gas 437 dollars , for freight and cartage on goods 936 dollars , and ...
... gain $ 1,565 . For how much did he sell it ? 67. A merchant pays for rent of store 1,275 dollars a year , for clerk - hire 3,895 dollars , for fuel 242 dollars , for gas 437 dollars , for freight and cartage on goods 936 dollars , and ...
Page 36
... gain ? ( 23 ) 57,698 43,257 ( 24 ) 675,004 245,002 ( 25 ) 2,174,943 42,301 $ 1,322 . ( 26 ) 167,065,149 4,042,136 27. One year a farmer raised 1,898 bushels of oats , and sold 1,427 bushels . How many bushels did he keep for use ? 471 ...
... gain ? ( 23 ) 57,698 43,257 ( 24 ) 675,004 245,002 ( 25 ) 2,174,943 42,301 $ 1,322 . ( 26 ) 167,065,149 4,042,136 27. One year a farmer raised 1,898 bushels of oats , and sold 1,427 bushels . How many bushels did he keep for use ? 471 ...
Page 40
... gain ? $ 2,272 . 51. A forwarder had 40,000 bushels of oats in store at Chi- cago . How many bushels had he in store after shipping 25,487 bushels to Buffalo ? 14,513 bushels . 52. A broker sold stocks for $ 256,200 which cost him ...
... gain ? $ 2,272 . 51. A forwarder had 40,000 bushels of oats in store at Chi- cago . How many bushels had he in store after shipping 25,487 bushels to Buffalo ? 14,513 bushels . 52. A broker sold stocks for $ 256,200 which cost him ...
Page 90
... gain by selling both at 18 cents a pound ? 480 . 7. A farmer bought a lumber wagon for $ 124 , and a market wagon for $ 140 , and paid for them in hay at $ 12 a ton . How many tons of hay did it take ? 22 . 8. A cattle dealer bought 38 ...
... gain by selling both at 18 cents a pound ? 480 . 7. A farmer bought a lumber wagon for $ 124 , and a market wagon for $ 140 , and paid for them in hay at $ 12 a ton . How many tons of hay did it take ? 22 . 8. A cattle dealer bought 38 ...
Page 92
... gain was $ 863 . How much was he worth at the end of the six years ? $ 5,211 . 29. If I buy 137 acres of land at $ 64 an acre , and pay out $ 876 for fences and buildings upon it , how much does it cost me ? $ 9,644 . 30. A man buys a ...
... gain was $ 863 . How much was he worth at the end of the six years ? $ 5,211 . 29. If I buy 137 acres of land at $ 64 an acre , and pay out $ 876 for fences and buildings upon it , how much does it cost me ? $ 9,644 . 30. A man buys a ...
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Common terms and phrases
12 rods acres amount annex apples blocks bushels cents ciphers Commence Compound Numbers contained cords of wood cost Count by 9's cubic inches dealer decimal figures decimal point Divide Division divisor dollars dreds Dry Measure equal EXPLANATION EXPLANATION.-Since Express by figures farm farmer fence foot fourth gallons Hence higher denomination hundred hundred-thousandths hundredths improper fraction inches long inches wide integer interest Lake Itasca loads lowest terms Manual measure millionths minuend mixed number month multiplicand Multiply ounces paid partial dividend pile pint place the decimal pounds PROBLEMS pupils quarts quires quotient railroad Read Reduce remainder result right-hand figure rods long SECOND SOLUTION sell sheets similar fractions sold square miles subtract subtrahend ten-millionths ten-thousandths tenths third thousand thousandths tons week weighing Write in words write the numbers written yards
Popular passages
Page 177 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Page 78 - Cut off the ciphers from the divisor, and the same number of figures from the right of the dividend.
Page 138 - A pile of wood 8 feet long, 4 feet wide, and 4 feet high, contains 1 cord; and a cord foot is 1 foot in length of such a pile.
Page 55 - Zeros at the right of the partial products, since they do not affect the result of the addition, should be omitted as in (2). Care must be taken, however, to put the right-hand figure of each partial product directly under the figure of the multiplier used to obtain it.
Page 32 - It shows that the number after it is to be subtracted from the number before it.
Page 78 - III. Multiply the divisor by this quotient figure, subtract the product from the partial dividend, and to the remainder annex the next figure of the dividend.
Page 64 - It shows that the number before it is to be divided by the number after it. The expression 6 -H 2 = 3 is read, 6 divided by 2 is equal to 3.
Page 183 - This quotient may be obtained by multiplying the numerator of the dividend by the denominator of the divisor for the numerator of the quotient, and the denominator of the dividend by the numerator of the divisor for the denominator of the quotient Hence, the Rule.
Page 41 - RULE. — Place the less number under the greater, so that units of the same order shall stand in the same column. Commencing at the right hand, subtract each figure of the subtrahend from the figure above it.
Page 79 - Then divide the remaining figures of the dividend by the remaining figures of the divisor.