Elementary ArithmeticHarper & Brothers, 1878 |
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Page 23
... farmer harvests from five fields of wheat , 151 bushels , 204 bushels , 120 bushels , 312 bushels , and 211 bushels . How many bushels of wheat did he harvest ? 998 . 23. In January a laborer deposited in the savings bank 12 dollars ...
... farmer harvests from five fields of wheat , 151 bushels , 204 bushels , 120 bushels , 312 bushels , and 211 bushels . How many bushels of wheat did he harvest ? 998 . 23. In January a laborer deposited in the savings bank 12 dollars ...
Page 24
... farmer has 46 sheep in one flock and 38 in another . How many sheep has he ? 84 . 32. A merchant sold 13 yards of calico to one lady , 14 yards to another , and 16 yards to another . sell to the three ladies ? How many yards did he 43 ...
... farmer has 46 sheep in one flock and 38 in another . How many sheep has he ? 84 . 32. A merchant sold 13 yards of calico to one lady , 14 yards to another , and 16 yards to another . sell to the three ladies ? How many yards did he 43 ...
Page 28
... farmer killed six hogs which weighed 427 pounds , 329 pounds , 314 pounds , 217 pounds , 208 pounds , and 196 pounds . How much did they all weigh ? 1,691 pounds . 72. Seven rafts of saw - logs from Alleghany River passed Pittsburg in ...
... farmer killed six hogs which weighed 427 pounds , 329 pounds , 314 pounds , 217 pounds , 208 pounds , and 196 pounds . How much did they all weigh ? 1,691 pounds . 72. Seven rafts of saw - logs from Alleghany River passed Pittsburg in ...
Page 29
... farmer raised 587 bushels of wheat , 1,229 bushels of oats , 643 bushels of corn , 184 bushels of rye , 259 bushels ... farming implements , $ 423 for grain and seeds , and $ 189 for repairing fences and buildings . How much was his ...
... farmer raised 587 bushels of wheat , 1,229 bushels of oats , 643 bushels of corn , 184 bushels of rye , 259 bushels ... farming implements , $ 423 for grain and seeds , and $ 189 for repairing fences and buildings . How much was his ...
Page 36
... ( 26 ) 167,065,149 4,042,136 27. One year a farmer raised 1,898 bushels of oats , and sold 1,427 bushels . How many bushels did he keep for use ? 471 . CASE II . Any figure of the subtrahend greater than 36 INTEGERS .
... ( 26 ) 167,065,149 4,042,136 27. One year a farmer raised 1,898 bushels of oats , and sold 1,427 bushels . How many bushels did he keep for use ? 471 . CASE II . Any figure of the subtrahend greater than 36 INTEGERS .
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Common terms and phrases
12 rods acres amount annex apples blocks bushels cents ciphers Commence Compound Numbers contained cords of wood cost Count by 9's cubic inches dealer decimal figures decimal point Divide Division divisor dollars dreds Dry Measure equal EXPLANATION EXPLANATION.-Since Express by figures farm farmer fence foot fourth gallons Hence higher denomination hundred hundred-thousandths hundredths improper fraction inches long inches wide integer interest Lake Itasca loads lowest terms Manual measure millionths minuend mixed number month multiplicand Multiply ounces paid partial dividend pile pint place the decimal pounds PROBLEMS pupils quarts quires quotient railroad Read Reduce remainder result right-hand figure rods long SECOND SOLUTION sell sheets similar fractions sold square miles subtract subtrahend ten-millionths ten-thousandths tenths third thousand thousandths tons week weighing Write in words write the numbers written yards
Popular passages
Page 177 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Page 78 - Cut off the ciphers from the divisor, and the same number of figures from the right of the dividend.
Page 138 - A pile of wood 8 feet long, 4 feet wide, and 4 feet high, contains 1 cord; and a cord foot is 1 foot in length of such a pile.
Page 55 - Zeros at the right of the partial products, since they do not affect the result of the addition, should be omitted as in (2). Care must be taken, however, to put the right-hand figure of each partial product directly under the figure of the multiplier used to obtain it.
Page 32 - It shows that the number after it is to be subtracted from the number before it.
Page 78 - III. Multiply the divisor by this quotient figure, subtract the product from the partial dividend, and to the remainder annex the next figure of the dividend.
Page 64 - It shows that the number before it is to be divided by the number after it. The expression 6 -H 2 = 3 is read, 6 divided by 2 is equal to 3.
Page 183 - This quotient may be obtained by multiplying the numerator of the dividend by the denominator of the divisor for the numerator of the quotient, and the denominator of the dividend by the numerator of the divisor for the denominator of the quotient Hence, the Rule.
Page 41 - RULE. — Place the less number under the greater, so that units of the same order shall stand in the same column. Commencing at the right hand, subtract each figure of the subtrahend from the figure above it.
Page 79 - Then divide the remaining figures of the dividend by the remaining figures of the divisor.