Elementary ArithmeticHarper & Brothers, 1878 |
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Page 36
... dealer , having 247 baskets of peaches , sold 125 - baskets . How many baskets had he left ? 122 . 21. A man whose income is $ 875 a year , expends $ 734 . How much money does he save ? $ 141 . 22. A drover bought a lot of cattle for ...
... dealer , having 247 baskets of peaches , sold 125 - baskets . How many baskets had he left ? 122 . 21. A man whose income is $ 875 a year , expends $ 734 . How much money does he save ? $ 141 . 22. A drover bought a lot of cattle for ...
Page 38
... dealer receiving an order for 525 barrels of beef , has only 354 barrels on hand . How many barrels more will he require to fill the order ? 39. A merchant's sales in January amounted to $ 1743 , and in February to $ 928 . How much did ...
... dealer receiving an order for 525 barrels of beef , has only 354 barrels on hand . How many barrels more will he require to fill the order ? 39. A merchant's sales in January amounted to $ 1743 , and in February to $ 928 . How much did ...
Page 50
... dealer sold 7 pianos , at $ 325 each . How much did he receive for all of them ? 11. How many quarts of milk will be used in a hotel in a week , if 36 quarts are used each day ? 12. The factors are 2,147 and 5 . What is the product ? 13 ...
... dealer sold 7 pianos , at $ 325 each . How much did he receive for all of them ? 11. How many quarts of milk will be used in a hotel in a week , if 36 quarts are used each day ? 12. The factors are 2,147 and 5 . What is the product ? 13 ...
Page 50
... dealer sold 7 pianos , at $ 325 each . How much did he receive for all of them ? $ 2,275 . 11. How many quarts of milk will be used in a hotel in a week , if 36 quarts are used each day ? 12. The factors are 2,147 and 5 . 13. A cooper ...
... dealer sold 7 pianos , at $ 325 each . How much did he receive for all of them ? $ 2,275 . 11. How many quarts of milk will be used in a hotel in a week , if 36 quarts are used each day ? 12. The factors are 2,147 and 5 . 13. A cooper ...
Page 56
... dealer in watches sold 48 watches , at $ 125 each . How much did he receive for them ? $ 6,000 . 60 Twelve things make a dozen . How many eggs in a barrel containing 87 dozens ? 1,044 . 61. A western township contains 36 square miles ...
... dealer in watches sold 48 watches , at $ 125 each . How much did he receive for them ? $ 6,000 . 60 Twelve things make a dozen . How many eggs in a barrel containing 87 dozens ? 1,044 . 61. A western township contains 36 square miles ...
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Common terms and phrases
12 rods acres amount annex apples blocks bushels cents ciphers Commence Compound Numbers contained cords of wood cost Count by 9's cubic inches dealer decimal figures decimal point Divide Division divisor dollars dreds Dry Measure equal EXPLANATION EXPLANATION.-Since Express by figures farm farmer fence foot fourth gallons Hence higher denomination hundred hundred-thousandths hundredths improper fraction inches long inches wide integer interest Lake Itasca loads lowest terms Manual measure millionths minuend mixed number month multiplicand Multiply ounces paid partial dividend pile pint place the decimal pounds PROBLEMS pupils quarts quires quotient railroad Read Reduce remainder result right-hand figure rods long SECOND SOLUTION sell sheets similar fractions sold square miles subtract subtrahend ten-millionths ten-thousandths tenths third thousand thousandths tons week weighing Write in words write the numbers written yards
Popular passages
Page 177 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Page 78 - Cut off the ciphers from the divisor, and the same number of figures from the right of the dividend.
Page 138 - A pile of wood 8 feet long, 4 feet wide, and 4 feet high, contains 1 cord; and a cord foot is 1 foot in length of such a pile.
Page 55 - Zeros at the right of the partial products, since they do not affect the result of the addition, should be omitted as in (2). Care must be taken, however, to put the right-hand figure of each partial product directly under the figure of the multiplier used to obtain it.
Page 32 - It shows that the number after it is to be subtracted from the number before it.
Page 78 - III. Multiply the divisor by this quotient figure, subtract the product from the partial dividend, and to the remainder annex the next figure of the dividend.
Page 64 - It shows that the number before it is to be divided by the number after it. The expression 6 -H 2 = 3 is read, 6 divided by 2 is equal to 3.
Page 183 - This quotient may be obtained by multiplying the numerator of the dividend by the denominator of the divisor for the numerator of the quotient, and the denominator of the dividend by the numerator of the divisor for the denominator of the quotient Hence, the Rule.
Page 41 - RULE. — Place the less number under the greater, so that units of the same order shall stand in the same column. Commencing at the right hand, subtract each figure of the subtrahend from the figure above it.
Page 79 - Then divide the remaining figures of the dividend by the remaining figures of the divisor.