Elementary ArithmeticHarper & Brothers, 1878 |
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Page v
... solution is inductively explained . These examples , except in Currency , Compound Numbers , and Percentage , contain only abstract numbers , because a general principle should not be deduced from a special or limited application . The ...
... solution is inductively explained . These examples , except in Currency , Compound Numbers , and Percentage , contain only abstract numbers , because a general principle should not be deduced from a special or limited application . The ...
Page 21
... SOLUTION . 2,344 ) 3,152 Parts . 5,496 Sum . EXPLANATION . - Since these parts are too large to be added mentally , we write them one under the other , writing the ones of one part under the ones of the other , the tens under tens , the ...
... SOLUTION . 2,344 ) 3,152 Parts . 5,496 Sum . EXPLANATION . - Since these parts are too large to be added mentally , we write them one under the other , writing the ones of one part under the ones of the other , the tens under tens , the ...
Page 24
... SOLUTION . 28 76 Parts . 39 2 143 31. A farmer has 46 sheep in one flock and 38 in another . How many sheep has he ? 84 . 32. A merchant sold 13 yards of calico to one lady , 14 yards to another , and 16 yards to another . sell to the ...
... SOLUTION . 28 76 Parts . 39 2 143 31. A farmer has 46 sheep in one flock and 38 in another . How many sheep has he ? 84 . 32. A merchant sold 13 yards of calico to one lady , 14 yards to another , and 16 yards to another . sell to the ...
Page 35
... SOLUTION . 8,397 Minuend . 3,265 Subtrahend . 5,132 Difference . Com- EXPLANATION . - Since these numbers are too large to be subtracted mentally , we write the subtrahend below the minuend , with the ones under ones , the tens under ...
... SOLUTION . 8,397 Minuend . 3,265 Subtrahend . 5,132 Difference . Com- EXPLANATION . - Since these numbers are too large to be subtracted mentally , we write the subtrahend below the minuend , with the ones under ones , the tens under ...
Page 37
... SOLUTION . 16 9 7 SOLUTION . 6 16 76 29 47 EXPLANATION . - As we can not subtract 9 ones from 6 ones , we take 1 of the 7 tens and unite it with the 6 ones , making 16 ones , and sub- tracting 9 ones from the 16 ones , we write the ...
... SOLUTION . 16 9 7 SOLUTION . 6 16 76 29 47 EXPLANATION . - As we can not subtract 9 ones from 6 ones , we take 1 of the 7 tens and unite it with the 6 ones , making 16 ones , and sub- tracting 9 ones from the 16 ones , we write the ...
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Common terms and phrases
12 rods acres amount annex apples blocks bushels cents ciphers Commence Compound Numbers contained cords of wood cost Count by 9's cubic inches dealer decimal figures decimal point Divide Division divisor dollars dreds Dry Measure equal EXPLANATION EXPLANATION.-Since Express by figures farm farmer fence foot fourth gallons Hence higher denomination hundred hundred-thousandths hundredths improper fraction inches long inches wide integer interest Lake Itasca loads lowest terms Manual measure millionths minuend mixed number month multiplicand Multiply ounces paid partial dividend pile pint place the decimal pounds PROBLEMS pupils quarts quires quotient railroad Read Reduce remainder result right-hand figure rods long SECOND SOLUTION sell sheets similar fractions sold square miles subtract subtrahend ten-millionths ten-thousandths tenths third thousand thousandths tons week weighing Write in words write the numbers written yards
Popular passages
Page 177 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.
Page 78 - Cut off the ciphers from the divisor, and the same number of figures from the right of the dividend.
Page 138 - A pile of wood 8 feet long, 4 feet wide, and 4 feet high, contains 1 cord; and a cord foot is 1 foot in length of such a pile.
Page 55 - Zeros at the right of the partial products, since they do not affect the result of the addition, should be omitted as in (2). Care must be taken, however, to put the right-hand figure of each partial product directly under the figure of the multiplier used to obtain it.
Page 32 - It shows that the number after it is to be subtracted from the number before it.
Page 78 - III. Multiply the divisor by this quotient figure, subtract the product from the partial dividend, and to the remainder annex the next figure of the dividend.
Page 64 - It shows that the number before it is to be divided by the number after it. The expression 6 -H 2 = 3 is read, 6 divided by 2 is equal to 3.
Page 183 - This quotient may be obtained by multiplying the numerator of the dividend by the denominator of the divisor for the numerator of the quotient, and the denominator of the dividend by the numerator of the divisor for the denominator of the quotient Hence, the Rule.
Page 41 - RULE. — Place the less number under the greater, so that units of the same order shall stand in the same column. Commencing at the right hand, subtract each figure of the subtrahend from the figure above it.
Page 79 - Then divide the remaining figures of the dividend by the remaining figures of the divisor.