The practical arithmetic |
From inside the book
Results 1-5 of 34
Page 45
... amount of any given number of different denominations . CASE I. — When the given quantity does not exceed 12 . RULE . - Multiply the price or compound quantity by the given number , beginning with the lowest denomination ; divide this ...
... amount of any given number of different denominations . CASE I. — When the given quantity does not exceed 12 . RULE . - Multiply the price or compound quantity by the given number , beginning with the lowest denomination ; divide this ...
Page 47
... amount required . But if two numbers or component parts cannot be found to make the given quantity , find two whose product will ap- proximate the nearest to it , and take as many times the given price as the product of the two numbers ...
... amount required . But if two numbers or component parts cannot be found to make the given quantity , find two whose product will ap- proximate the nearest to it , and take as many times the given price as the product of the two numbers ...
Page 48
... amount or value required . N.B. The questions in Practice may be done by this rule EXAMPLES . 1. What is the value of 365 yards , at 12s . 4d . per yard ? S. d . 12 4 X 5 10 X 10 X 3 +60 + 5 = 365 6 3 4 x 6 10 61 13 4 3 185 0 0 value of ...
... amount or value required . N.B. The questions in Practice may be done by this rule EXAMPLES . 1. What is the value of 365 yards , at 12s . 4d . per yard ? S. d . 12 4 X 5 10 X 10 X 3 +60 + 5 = 365 6 3 4 x 6 10 61 13 4 3 185 0 0 value of ...
Page 54
... amounts to 1 1 1 2 at 11 at 1 1 , at 13 1 at 2 " 1 " at 24 1 at 5 " 1 at 7 S. d . 0 to 1 3 to 1 6 to 1 9 to 2 0 to 2 3 to 5 0 to 7 0 & c . , & c , that is , one dozen will cost as many shillings , as each article costs pence . CASE I ...
... amounts to 1 1 1 2 at 11 at 1 1 , at 13 1 at 2 " 1 " at 24 1 at 5 " 1 at 7 S. d . 0 to 1 3 to 1 6 to 1 9 to 2 0 to 2 3 to 5 0 to 7 0 & c . , & c , that is , one dozen will cost as many shillings , as each article costs pence . CASE I ...
Page 73
... amount to £ 369 2s . in seven months ; what is the rate per cent , per annum ? Ans . £ 4 6s . 8d . 12. If a beam of wood 15 feet long , 15 inches deep , and 12 inches broad , weigh 600 lbs . ; how much will a beam of the same kind of ...
... amount to £ 369 2s . in seven months ; what is the rate per cent , per annum ? Ans . £ 4 6s . 8d . 12. If a beam of wood 15 feet long , 15 inches deep , and 12 inches broad , weigh 600 lbs . ; how much will a beam of the same kind of ...
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Common terms and phrases
A's share acres aliquot amount annuity annum arithmetical Bought cash ciphers common denominator common difference compound interest contains cube root denotes discount ditto dividend divisor equal equivalent vulgar fraction Example 2nd EXAMPLES FOR PRACTICE farthings feet 6 inches Find the value gain per cent gallons geometrical progression given fraction given number given price given rate given sum guineas improper fraction last term least common multiple lowest terms miles mixed number moidores multiplicand nails neat weight number of terms pence person person's share pounds present worth prime cost quarters quotient rate per cent ratio Reduce remainder repetend Required each person's Required the cube Required the square Required the sum Required the value Rule of Three RULE.-Multiply selling price series of numbers shillings simple fraction sold square root subtract tare whole gain whole number yards of cloth
Popular passages
Page 15 - The number to be divided is called the dividend. The number by which we divide is called the divisor.
Page 25 - TABLE. 4 gills (gi.) - make - - 1 pint, marked pt. 2 pints ------- 1 quart, - - - qt. 4 quarts ------ 1 gallon, - - - gal. 31£ gallons ------ 1 barrel, - - - bar.
Page 68 - Multiply the first and second terms together, and divide the product by the third ; the quotient will be the answer in the same denomination as the middle term was reduced into.
Page 89 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Page 63 - Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required.
Page 173 - ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Page 188 - Sessa requested that he might be allowed one grain of wheat for the first square on the chess board, 2 for the second, 4 for the third, and so on, doubling continually, to 64, the whole number of squares. Now, supposing, a pint to contain 7680 of these grains, and one quarter or 8 bushels to be worth yja 6d, it is required to compute the value of all the corn ? Ans.
Page 27 - January 31, February 28, March 31, April 30, May 31, June 30, July 31, August 31, September 30, October 31, November 30, December 31.
Page 89 - To reduce an improper fraction to a whole or mixed number. RULE. Divide the numerator by the denominator, and the quotient will be the whole or mixed number sought.
Page 145 - DISCOUNT. DISCOUNT is an allowance made for the payment of money before it is due. The present worth of a debt payable at some future time, without interest, is such a sum of money as will, if put at interest for the given time, amount to the debt.