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If a man purchase a yoke of A certain field has four sides oxen for £15 55. 8d. four cows whose lengths are as follows: for £20 10s. 6d. and a horse | 4ch 27lin. 5ch. 19lin. 4ch. for £26 ; what did they all cost? | 50lin. and 6ch. 4lin. what is
Ans. £61, 16s. 2d. the distance round it? The floors of 4 rooms in a
Ans. 20 ch. certain house cover 5rd. 24in. What is the weight of 3hhd. of land; the remaining room of sugar, the first weighing Ird, lyd. Ift.; and the walls | 10cwt. 2016. ; the 2d, 9cwt. and chimney cover 2rd. llin.; | lqr. 15oz.; and the 3d, 11cwt. how much land does the whole 15lb. 14dr. ? house occupy?
Ans. 1 ton, 10 cwt. 2 qr. 7 1b. Ans. 8rd. lyd. lft. 35in.
15 oz. 14 dr.
149. 1. A person bought a cow for 31. 7s. 6d. and sold it for 41. 12s. 3d. how much did he gain?
'We write the less number under the greater, so that l. d. pence shall stand under pence, shillings under shil4 12 3 lings, and pounds under pounds; we then begin at 3 7 6 the right hand, but as we cannot take 6d. from 3d.
we borrow from the 12s. ls.=12d. which we join with Gain 1 4 9 the 3d. making 15d. and then 6d. from 15d. leaves 90.
which we write under the pence. We now proceed Proof 4 12 3 to the shillings, but as we have borrowed 1s. from 12s.
we call the 12s. 11s. and 7s. from 11s. leaves 4s, and lastly, 31. from 41. leaves 11. Thus we find that he gained 11. 43. 94. The above process is called Compound Subtraction.
COMPOUND SUBTRACTION 150. Is the taking of one compound number from another, so as to find the difference between them. (42)
RULE. 15). Write the less number under the greater, so that the parts which are of the same name may stand directly under each other.
Begin with the lowest denomination, and take the number in the lower line from the one standing over: proceed in the same way with all the denominations.
Should the number in the upper line be less than the one standing under it, suppose as many units to be added to the upper number as will make a unit of the next higher denomination, remembering to diminish the number in the next place in the upper line by 1.
PROOF.— The same as in Simple Subtraction.
QUESTIONS FOR PRACTICE.
lb. oz. pwt. gr. Borr. 149 10 8 791
9 8 1 440 5 15 20 27 8 12 10 Paid 86 12 4 197 16 4 2 60 8 1912 194 16 19
TIME. d. h. m. S.
d. h. m. 17 13 27 19 12 125 17 4 12 16 41 35 4 204 16 12
AVOIRDUPOIS WEIGHT. lb. oz. dr. to. cwt. qr. Ib. oz.dr. 84 10 8 9 11 3 19 4 11 76 14 9 3 12 1 20 9 7
WINE MEASURE. yd. ft. in.
deg. mi. fur. rd. ft. in. gal. qt. pt. gs. hhd. gal. qt: pt. 25 2 10 36 40 3 22 8 7 43 1 0 1
63 36 3 1 16 1 11 17 45 1 37 9 3 24 3 1 0
59 42 3 1
A man sold a piece of land A person having 624 yds. for £735 11 s. 6 d. and receiv- 1 3 qr. of cloth, sold at one time ed at one time £195 13 s. 11d. | 247 yd. 2 qr. and at another and at another £61 5 s.; how 114 yd. 1 qr.; how much has inuch remains due ?
he left? Ans. 263 yd. Ans. £478 12 s. 7d.
152. In computing interest, the month is commonly reckoned 30 days, and the year 12 months. (145) In working the following questions, in place of the months, write the numbers of the months. (34)
A note was on interest from How long was that note on Dec. 29, 1825, till June 22, interest,which was given, 1826, 1828 ; what was the length of January 3, and paid August 1, time?
of the same year? years. mo. days.
Aps. 6m. 28d. 1828 5 22 1825 11 29
How long from 1822, April
21, to 1826, March 15? 2 5 23 Ans.
Ans. 3yr. 10m. 24d.
4. Pultiplication and Division.
s. d. Tr.
153. 1. What will 6lb. of coffee 154. 1. If 6lb. of coffee cost 9, cost at 1s. 6d. 3 gr. per pound? 40. 2qr. how much is that per lb. ? The cost of 6lb. is
If we divide the price s. d. gr. evidently 6 times
of 6 lb. into 6 equal 1 6 3 the cost of llb. we 6) 94 2(1s. parts, one of those 6 therefore multiply 6
parts must be the price the price of llb. by
To do this we Ans. 9 4 2 6; thus, 6 times 3qr. 3
first seek how many are 18qr.=4d. 2qr. 12
times 6 in 9s. and write of which we write down the 2qr.
1s. for the quotient. We and reserve the 4d. to be joined | 6)40(63. then multiply and subwith the pence. We then say
tract as in Simple Divitimes 6d, are 36d. and 4d. reserved
sion. We then multiply are 40d.=3s. 4d. of which we write 4 the remainder,3s.by 12, down the 4d. and reserve the 3s, to 4 adding the 4d.(139) and be joined with the shillings. Last
divide the sum, 40d. by ly, we say 6 times 1s. are 6s. and 6)18(3qr. 6, which gives 6d. for a 3s. reserved are 9s, which we write 18 quotient, and 4 d. redown, and the work is done.
main, which reduced to 2. What will 47 yards of cloth added, make 18ğr. These divided
farthings, and the 2qrs. cost at 17s. 9d. per yarıl? We first multiply Thus we find the price of llb. to be
by 6, give 3qr. for the quotient. 9d. by 47, and divi
1s. 6d. 3qr. 17 9 ding the product 423d. 47 by 12, find 355. 3d. to 2. If 47 yards of cloth cost 411.
be the cost of 47yd. 14s. 3d. what is that per yard? 12) 423d. at 9d. Again we mul
Here we divide tiply 17s. by 47, and
l. s. d. the whole price 355. 3d. write the partial pro- 47 ) 41 14 3 (01. by the whole 119 ducts, which are shil
quantity, as be68 lings, under the 35s.
fore. As 47 is These added together 47 ) 834s. (17s. not contained in 210) 83,4s. make 834s. which di
the pounds, we vided by 20 give 411.
place a cipher in A. 411.14s. 3d. 14s. and bringing
the quotient avel down the 3d. we have
329 reduce the pounds 411. 14s. 3d. for the whole cost.
to shillings, adding This method will prevent the ne.
35 the 14s. Dividing cessity of dividing this rule into a
12 834s.by47,we get17s. variety of cases.
in the quotient. The By comparing the corresponding
73 remainder, 353. reexamples in the two columns, it
35 duced to pence, and will be seen that they mutually
the 3d. added, give prove each other,
47 ) 423(9d. 423d. which divided 423 by 47 give 9d. in the
quotient. Thus we 0 find the price of one
yard to be 175, 96,
COMPOUND MULTIPLICATION COMPOUND DIVISION
156. Is the method of sepa155. Is the method of find rating a compound number ing the amount of a compounds into any proposed number of number by repeating it a pro- equal parts. (44) posed number of times. (43)
158. Write the numbers as RULE. 157. Write the multiplier the several terms of the divi.
in Simple Division, and divide under the lowest denomina
dend successively by the divition of the multiplicand. Re
sor. Should the first term of serve from each product as the dividend be less than the many units as may be had of divisor, reduce it to the next the next higher denomination, lower denomination, adding the and write down the excess, ad number of the lower denomiding the number reserved to nation. Do the same with the the next product.
several remainders. NOTE.--This rule is susceptible NOTE.-This rule is susceptible of the same contractions as Simple of the same contractions as Simple Multiplication.
Division. QUESTIONS FOR PRACTICE. 3. What will 6 cows cost at 3. If 6 cows cost £26, how £4 66. 8d. apiece?
much is that apiece? 4 What will 9cwt. of cheese 4. If Icwt of cheese cost cost at £1 11s. 5d. per cwt. ? £14 28. 9d. how much is that
5. What will 28 yards of per cwt.? broadcloth cost at 195. 4d. per 5. If 28yds. of broadcloth
cost £27 ls. 4d. what is that 6. What will 96 quarters of a yard? rye cost at £1 3s. 4d. a qr. ? 6. If 96qrs. of rye cost £112
7. What will 47 yards of how much is that a qr.? cloth cost at 17s. 9d. a yard? 7. If 47yds. of cloth cost
8. How many yards in 17 £41 148. 3. what is that a pieces, each containing 29yds. yard?
8. In 505yd. 3qr. how many 9. What will 94 pair of pieces of 29yd. 3qr. each? stockings cost at 12s. 2d. a 9. If 94 pair of stockings
cost £57 3s. Bd. what is that a 10. What will 512 bushels pair? of wheat cost at 5s. 10d. a bu- 10. If 512 bushels of wheat shel?
cost £149 6s. 8d. what is that 11. If a span of horses eat 2 a bushel ? bu. 3 pks. of oats in one week, 11. If a span of horses eat how many will they eat in 25 68bu. 3pk. of oats in 25 weeks, weeks?
how much is that a week?