| John Bonnycastle - Algebra - 1811 - 230 pages
...whose difference, multiplied by the lesser, is equal to 1 2 1 Ans. 4 and 7, or $v/2 and yv/2 10. To find a number such that if you subtract it from 10, and multiply the remainder by the number itself, the product shall be 21. Ans. 7 or 3. 11. To divide 100... | |
| John Bonnycastle - Algebra - 1813 - 456 pages
...the number 40 into two such parts, that the sum of their squares shall be 818. Ans. 23 and 1/ 2. To find a number such, that if you subtract it from 10, and then multiply the remainder by the numbpr itself, the product shall be 21. Ans. 7 or 3 3. It is required... | |
| John Bonnycastle - Algebra - 1818 - 284 pages
...the number 40 into two such parts, that the sum of their squares shall be 818. Ans. 23 and 17 2. To find a number such, that if you subtract it from 10, and then multiply the remainder by the number itself, the product shall be 21. Ans. 7 or 3 3. It is required... | |
| Peter Nicholson - Mathematics - 1825 - 1046 pages
...the remainder for 541. and gained 2s. a head by them ; how many sheep did he buy ? Ans. 75. 15. To find a number such, that if you subtract it from 10, and multiply the remainder by the number itself, the product shall be 21. Ans. 7 or 3. 1 6. The sum of... | |
| John Bonnycastle - Algebra - 1825 - 336 pages
...number 40 into two such. parts, that the sum of their squares shall be 818. Ans. 23 and 1 7. 2. To find a number such, that if you subtract it from 10, and then multiply the remainder by the number itself, the product shall be 21. Ans. 7 or 3 3. It is required... | |
| Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 446 pages
...whose difference, multiplied by the lesser, is equal to 12 ? Ans. 4 and 7, or | V2 and ',' V2. 18. To find a number such that if you subtract it from 10, and multiply the remainder by the number itself, the product shall be 21. Ans. 1or 3. 19. To divide 100... | |
| Peter Nicholson - Algebra - 1831 - 326 pages
...Required the quantity of gold and silver in the mass ? Ans. 301b. of silver, and 761b of gold. (29) Find a number, such, that if you subtract it from 10, and then multiply the remainder by the number itself, the product will be 21. Ans. 1 and 3. (30) A privateer,... | |
| Charles Davies - Algebra - 1835 - 378 pages
...digits, the quotient is 3 ; and if 18 be added to it. the digits will be inverted 1 Ans. 24. 8. To find a number such that if you subtract it from 10, and multiply the remainder by the number itself, the product shall be 21. Ans. 7 or 3. 9. Two persons,... | |
| Algebra - 1838 - 372 pages
...its digits, the quotient is 3 ; and if 18 be added to it. the digits will be inverted? Ans. 24. 8. To find a number such that if you subtract it from 10, and multiply the remainder by the number itself, the product shall be 21. Ans. 1 or 3. 9. Two persons,... | |
| John D. Williams - Algebra - 1840 - 634 pages
...391)=20±3= 23, or 17, but z=40— у=П, or 23 ; therefore 17 and 23 are the parts sought. 12. To find a number such, that if you subtract it from 10, and then multiply the remainder by the number itself, their product shall be 21. Let a; represent the number... | |
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