 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...18x9x108=17496^-1728=10,125 feet. But, in measuring timber, you may multiply the breadth in inches, and the depth in inches, and that product by the length in feet, and divide the last product by 144, which will give the solid content iu feet, &s. 2. A piece of timber being 1fi inches broad, 11... | |
 | Nathan Daboll - Arithmetic - 1817 - 252 pages
...18X9Xl08=17496-M723=10,l25 feet. But, in measuring timber, you may multiply the breadth in inches, and the depth iu inches, and that product by the length in feet, and divide the last product by 144, which will give the solid content in fe«t, &c. 2. A piece of timber being 16 inches broad, U... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...18x9x108=17496^-1728=10,125 feet. But, in measuring timber, you may multiply the breadth in inches, and the depth in inches, and that product by the length in feet, and divide the last product by 144, which will give the, solid content in feet, &e. *" Y 2. A piece of timber being 16 inches broad,... | |
 | Nathan Daboll - Arithmetic - 1825 - 248 pages
...Ю8=17496-'-1728=10,125 feet. But, in measuring timber, you may multiply the breadth in inches, and the depth in mches, and that product by the length in feet, and divide the last product by 144, which vill give tlte soliífcconteni in feet, &c. f. -T / Ï24 APEENDIX. 2. A piece of timber... | |
 | Nathan Daboll - Arithmetic - 1825 - 256 pages
...18x3x108=17496-7-1728=10.125 foet. But, in measuring timber, you may multiply the breadth in inches, and the depth in inches, and that product by the length in feet, and divide tt'e last product by 144, which will give the. solid content in feet, &e. 324 APPENDIX. K 2. A piece... | |
 | Michael Walsh - 1831 - 348 pages
...and divide by 144 for the content. 2. Multiply % of the circumference by i of the diameter, and the product by the length in feet, and divide the last product by 1 14 for the answer. 3. Multiply the square of the diameter by the length ii» fp~fm (1 that product... | |
 | Nathan Daboll - Arithmetic - 1837 - 262 pages
...18X9X108=174964-1728=10,125 feet. But, in measuring timber, you may multiply the breadth in inches, and the depth in inches, and that product by the length in feet, and divide the last product by J44, which will give the solid content in feet, &c. 2. A piece of timber being 16 inches broad, 11... | |
 | Nathan Daboll - 1843 - 260 pages
...18x9x108=17496-^-1728=10,125 feet. But. in measuring timber, you may multiply the breadth in inches, ami the depth in inches, and that product by the length in feet, and divide the last product by 144, which will give the solid content in ftet, &c. 2. A piece of timber being 16 inches broad, 11... | |
 | 1843 - 272 pages
...Content taken by Calliper, which is in favour of the ship, _ vis.. Multiply the diameter by itself in inches, and that product by the length in feet, and divide by 1s3 for the Cubic Content, Custom-houEe measure. — (Diameter, in inches, to be Ukeu at the Middle... | |
 | Nathan Daboll - Arithmetic - 1844 - 254 pages
...18X9X108=17496-^ 1728=10,125 feet. But, in measuring timber, you mfiy multiply the breadth In inches, and the depth in inches, and that product by the length in feet, and divide the .nst product by 144, which will give the solid content in feet, &c. 2. A piece of timber being 16 inches... | |
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But. in measuring timber, you may multiply the breadth in inches, ami the depth in inches, and that product by the length in feet, and divide the last product by 144, which will give the solid content in ftet, &c. 
