# A Key to Chase's Common School Arithmetic: With Explanations and Remarks Upon the Peculiar Features of the Work, and Operations of the More Difficult Examples

A. Hutchinson, 1853
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### Contents

 Section 1 1 Section 2 2 Section 3 3
 Section 4 5 Section 5 9 Section 6 90

### Popular passages

Page 92 - RULE. — Multiply the length (in feet) by the width (in inches) and divide the product by 12 — the result will be the contents in square feet.
Page 24 - ... thirds, and we wish to divide it into 6ths : We have, therefore, simply to reduce thirds to sixths. 2 sixths make a third, for the unit is divided into twice as many parts, and therefore the parts are one-half as large. Hence the RULE. Divide the required denominator by the denominator of the given fraction, and multiply the quotient by the numerator. The product will be the required numerator. Art. 58. — To reduce a whole number to an equivalent fraction, having a given denominator. 1. Reduce...
Page 92 - But. in measuring timber, you may multiply the breadth in inches, ami the depth in inches, and that product by the length in feet, and divide the last product by 144, which will give the solid content in ftet, &c.
Page 91 - С in. long, 14ft. wide, and 10ft. high. The room contains 4 windows, each 3 ft. 6 in. by 5 ft. 8 in. ; 2 doors, each 6 ft. 4 in. by 2 ft.
Page 69 - The roots of fractions are obtained by extracting the root of the numerator, and of the denominator, separately.
Page 44 - The remainder will form a new principal, upon which interest is to be cast to the time of the next payment.