Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks |
From inside the book
Results 1-5 of 7
Page 63
... excess ( 6 ) of 9s equal to the excess of 9s in that number . And from the nature of Addition , it follows , that the sum of the excesses of 9s in two or more numbers , always has an excess equal to the excess in the sum of those ...
... excess ( 6 ) of 9s equal to the excess of 9s in that number . And from the nature of Addition , it follows , that the sum of the excesses of 9s in two or more numbers , always has an excess equal to the excess in the sum of those ...
Page 64
... excess of 9s in their sum equal the excess in the minuend , the work is right . 6 3 4 5 6 ... 6 5 2 0 0 1 ... 8 1 1 4 5 5 ... 7 The sum of the excesses 8 and 7 are 15 , from which rejecting the 9s leaves 6 ; equaling the excess in the ...
... excess of 9s in their sum equal the excess in the minuend , the work is right . 6 3 4 5 6 ... 6 5 2 0 0 1 ... 8 1 1 4 5 5 ... 7 The sum of the excesses 8 and 7 are 15 , from which rejecting the 9s leaves 6 ; equaling the excess in the ...
Page 65
... excess . 8 excess . Remainder , 32 68 5 excess . 5 excess . Dividend , 10 38998 , .. 1 excess . 1 excess . RULE . Multiply the excess of 9s in the quotient , by the excess in the divisor , and reject the 9s from the product : to which add ...
... excess . 8 excess . Remainder , 32 68 5 excess . 5 excess . Dividend , 10 38998 , .. 1 excess . 1 excess . RULE . Multiply the excess of 9s in the quotient , by the excess in the divisor , and reject the 9s from the product : to which add ...
Page 67
... excess of each above the smallest given , to find those numbers . - From their whole sum subtract the given excess , and if there be more than two numbers , subtract the sum of the excesses ; then divide the remainder into 2 equal parts ...
... excess of each above the smallest given , to find those numbers . - From their whole sum subtract the given excess , and if there be more than two numbers , subtract the sum of the excesses ; then divide the remainder into 2 equal parts ...
Page 68
... excess ; 1000-300-700 ÷ 4 years = 175 . A. 175 ; 225 ; 275 ; 325 . 30. Divide 1,300 dollars so that B may have 300 more than A , and C 200 less than A ; what sum will each receive ? The excess is 100 . A. 400 ; 700 ; 200 . 31. PROB . VI ...
... excess ; 1000-300-700 ÷ 4 years = 175 . A. 175 ; 225 ; 275 ; 325 . 30. Divide 1,300 dollars so that B may have 300 more than A , and C 200 less than A ; what sum will each receive ? The excess is 100 . A. 400 ; 700 ; 200 . 31. PROB . VI ...
Other editions - View all
Common terms and phrases
12 cents 50 cents acres amount annexing barrels of flour breadth bushels called cents apiece ciphers common denominator composite number compound interest compound number contain cows cube root cubic decimal fraction denom diameter difference dimes Divide dividend Division dollars eagles equal example excess factors farthings Federal Money feet long Find the sum gallons given number greater greatest common divisor Hence hogsheads horses hundred hundredths improper fraction inches indorsed least common multiple length miles million mills minuend mixed number molasses months multiplicand Multiply ounces payment pence pieces pints pounds present worth prime proportion purchase quantity quarts quotient ratio receive Reduce remainder Repeat the Table repetend sells shillings sold solid feet square rods square root subtract subtrahend Suppose thousand thousandths TROY WEIGHT units vulgar fraction weight whole number write yards of cloth